Very clear and simple explenation, specialy for entangelmen. Nobody explaind it with math, but now taht you did it very clear and not confusing as people try to make it seem.
Truly excellent!!! Great work, I truly appreciate the aid in distinguishing between direct product and tensor product of vector spaces! I am always delighted by your animations in general, but I truly appreciate just how much insight this series brings. Looking forward to more! ❤
Please upload the next videos in the series, that is the best explanation i have ever seen, very fun and includes all possible information , thank you for your hard work
The tensor product has starking similarities with the geometric product, but instead of a welding it's a wedging (exterior) plus an inner product. That way, an entangled systems is a diagonal system, a matrix of projections of states, or in tensor lingo, a symmetric rank-2 tensor. The off-diagonal components are the anti-symmetric components of that tensor, or the parallelograms made by extruding one vector in the direction of the other and vice-versa, giving two congruent parallelograms, but w/ opposite perimetral circulation. In 3D, we have 3 basis vectors, whose produces 3 scalar projections and 3 parallelogram areas, each of these with 2 versions. Giving off a total of 9 components for the tensor's matrix. *In quantum gates, it's easier to convince yourself, bc instead of row/column-like descriptions of vectors, their basis is composed of the Pauli matrices and the components of the tensor calculated by AB = A•B+iA×B.
But there are no actual 6D spaces, only 3D ones. Shouldn't these two "spaces" be considered just two systems of coordinates in the same only real space?
good question. The thing is, tensors and there relations don't depend on coordinates, only their representations do, so I would avoid the two coordinates argument. Suppose the red vector is force (say, a gravity field), while the blue vector is nabla (d/dx, d/dy, d/dz), they make a six independent degree-of-freedom tensor (i.e. a 6D space, but it is the tensor product of two 3D spaces that are completely different, on has lengths in newtons, while the other is meters).
![BLACK BAG - Official Trailer [HD] - Only in Theaters March 14](http://i.ytimg.com/vi/Du0Xp8WX_7I/mqdefault.jpg)
I've been waiting for this video.
Your channel is a gem
We are eating good
Thanks everyone for this great life.
hell yeah bro udiprod and food goes HARD
it's finally here
I literally had an abstract lin alg exam today! I love how everything comes together :)
These videos can't come fast enough, they are so quality
you guys are amazing. Keep it up. Not even universities put this much effort into their material. Beautiful
I've been waiting for this for almost a year
Very clear and simple explenation, specialy for entangelmen. Nobody explaind it with math, but now taht you did it very clear and not confusing as people try to make it seem.
Truly excellent!!! Great work, I truly appreciate the aid in distinguishing between direct product and tensor product of vector spaces! I am always delighted by your animations in general, but I truly appreciate just how much insight this series brings. Looking forward to more! ❤
Great Animations cant wait for next Video :3
Amazing video!! Can't wait for the next one :)
Nice explanation of entangled states. Thanks!
Wow this channel is finally active.
Please upload the next videos in the series, that is the best explanation i have ever seen, very fun and includes all possible information , thank you for your hard work
new Tempt6 video, new udiprod video - LETS GOOOOOO
The tensor product has starking similarities with the geometric product, but instead of a welding it's a wedging (exterior) plus an inner product. That way, an entangled systems is a diagonal system, a matrix of projections of states, or in tensor lingo, a symmetric rank-2 tensor. The off-diagonal components are the anti-symmetric components of that tensor, or the parallelograms made by extruding one vector in the direction of the other and vice-versa, giving two congruent parallelograms, but w/ opposite perimetral circulation.
In 3D, we have 3 basis vectors, whose produces 3 scalar projections and 3 parallelogram areas, each of these with 2 versions. Giving off a total of 9 components for the tensor's matrix.
*In quantum gates, it's easier to convince yourself, bc instead of row/column-like descriptions of vectors, their basis is composed of the Pauli matrices and the components of the tensor calculated by AB = A•B+iA×B.
very good explanation :) thank you!
Wow amazing, great video...
Love this series. Great content and really helpful in my studies. May I ask what dou you use for animation?
Thanks :) I'm using Maya.
Looking forward for more
Wonderful video 👏👏👏👏
really really great video
ok i might need to rewatch this but it's good stuff thank you!
excellent, thanks!
We out here entangling qubits.
the vidéo of year finally here
It's been 84 years...
What the the element material use to be a single qubits for quantum computing?
Damn, this is good
Look what I have found! This is the most terrific video that explains quantum entanglement I've ever seen!
Omg what timing
Spinors go SPEEEN!
(I'm already filled with quaternion)
3B(next video) plz
Only my grandchildren will see 3B...
Now wait for another year for the next part
Here is the thing. I’m 73 and I grew up reading books (you sprogs can Google what they are) so I would really, really some text references.
i got goosebumps when entanglement is mentioned
Peak
I have an exam on this Monday ✨✨
lol same
notes?
added.
@@udiprod thanks
But there are no actual 6D spaces, only 3D ones. Shouldn't these two "spaces" be considered just two systems of coordinates in the same only real space?
good question. The thing is, tensors and there relations don't depend on coordinates, only their representations do, so I would avoid the two coordinates argument. Suppose the red vector is force (say, a gravity field), while the blue vector is nabla (d/dx, d/dy, d/dz), they make a six independent degree-of-freedom tensor (i.e. a 6D space, but it is the tensor product of two 3D spaces that are completely different, on has lengths in newtons, while the other is meters).
Seems like you also know about tensors; what books would you suggest me to learn about tensors?@@DrDeuteron
@@DrDeuteron - Whatever they are they should exist in our 4 dimensions, there are no others.
A space doesn’t have to “exist physically” to be a space.
R^6 is a 6D space.
@@drdca8263 - IMO it does, all the rest is idealism, not realism = science.