Astronomy & Astrophysics Olympiad Question | IOAA 2019 Question 2
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- Опубликовано: 16 янв 2024
- Diving into Question 2 from the International Olympiad on Astronomy and Astrophysics (IOAA) 2019 Theory Paper! Did you manage to solve it?
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Finally!! The wait is over for some astrophysics! Liked it ❤❤
If Halton Arp is right, quasars
have an *intrinsic redshift*
(because the electrons there
are less massive than those on Earth
causing spectral lines to
shift towards the red).
and so quasars are not at cosmic
distances at all and have in fact
have been ejected by Active
Galaxies.
Relatively easy problem!
indeed one of the easiest problems in the paper considering q14 and the whole of data analysis exists
Thanks for your videos, Ellie. Given the historical significance of measuring light's deflection by the Sun, for General Relativity ... it was interesting to see the calculation also done for Jupiter and the Moon. I appreciated your clear exposition of the calculations in solving this question.
I enjoyed it ❤.
Very interesting video😊
Wounderful PROF 👍
Amazing...!!!😊
Soon U will get million subscribers keep it up)
The most interesting RUclips CHANNEL.
As classes full longs lectures IOAA Olympiad lectures full complete after analysis questions all before years❤❤❤❤❤
Big fan from Bangladesh ...
Give a video on inverse trigonometry ❤
But why do you use as d the radius? Is it an approximation? i didn't understand :)
I wish to speak with you ma , from nigeria about to study mathematics
Madam, please do more Astrophysics videos
Thank you ma'am ❤❤ I am studying for jee advanced.
I don't understand why d=R_sun. Can someone explain?
same
In short: you measure d from the center of the Sun. The light rays nearly touch the Sun's surface, so this distance is the solar radius.
Explanation:
The formula in this problem assumes that the Sun can be treated as a point mass. At first glance, this feels wrong. The stars appear near the edge of the Sun's disk, so the light rays must pass the Sun very close to its surface. How could the Sun be treated as a point mass then? Basically, the gravitational field of an object with spherically symmetric mass distribution is identical to that of an equally massive point mass (only if you are outside of the object, but that isn't important here). This is because of Gauss's law for gravity and the spherical symmetry of the gravitational field of such objects. You measure d from this equivalent point mass.
I this video to much
Could you solve beautiful physics problems too
more videos for coding in astrophysics