also for determining irrogation period, the units are not consistant. Volume/ discharge = 10.21 cubic meters divided by 4lph... so how u get 2.5 hrs?????
@@saurabhghodeswar7855 that was typing error, he had to write 10.21L instead of writing 10.21 cubic m. From step 2, answer should be 0.010206 cubic m. But dividing it by 1000 you get 10.21 L
at 06:29 you have calculated the volume of water applied by multiplying area into depth... area and depth units are not consistent... so how did you get 10.21 cubic meters??????
Dear professor please try to make things more clear specially when you are doing calculations.. there are 1000s of things which i noticed where you just rushed away and it matterd alot to students. when you were explaining the size of manifolds and laterals, there you skipped alot... if you have already given much of your time for.preparing lectures, please make them very clear and understandble... i total did not like your videos
This IITK professor should go to a farmer in Maharashtra and should get some hands on experience before going to give lecture to students. Very poor presentation.🤮🤮🤮
For finding velocity through lateral, ypu divided the discharge in lateral by its area... how you got 2961 lph for discharge???? atleast you must have explained that..WTF
2 liter discharge ,20 mm lateral का example क्यों नही देते, किसान रात भर हर 2-3 घंटे में cock बदलते रहे । Discharge कम और lateral mm ज्यादा रखने पर एक ही बार ज्यादा देर के लिए pump चलकर और काम या आराम कर सकता है ।
Substandard explanation. Monotonic and lethargic
Depth of irrigation values are not clear. What are Kp and Kc? How did you get it and previous figure didn't mention these values.
also for determining irrogation period, the units are not consistant.
Volume/ discharge = 10.21 cubic meters divided by 4lph...
so how u get 2.5 hrs?????
Yes bro u r right = 10m3= 10000litres
Ten thousand litre/ 4 = 2500
I also didn't get
@@saurabhghodeswar7855 that was typing error, he had to write 10.21L instead of writing 10.21 cubic m.
From step 2, answer should be 0.010206 cubic m. But dividing it by 1000 you get 10.21 L
Thank God I didnt study in IITK...feeling sorry for the new generation engineers. So bad preparation, worst know how of the system. All worst.
Thanks, good explanations
Why the discharge in main is not 4 times of discharge in single manifold????
but why do you convert to the same units like you multiplied the ETc in mm/day with the area in meters and u get meter cubed to me thats not realistic
i meant why don't you convert the units
How did he calculate Q = 2961 l/h?
Where does the Hemmitter come from?
at 06:29
you have calculated the volume of water applied by multiplying area into depth... area and depth units are not consistent... so how did you get 10.21 cubic meters??????
I think is 10.21 L/day, because it is 8.4mm
@@tomaszezezeze you are right that is typing error
Dear professor please try to make things more clear specially when you are doing calculations.. there are 1000s of things which i noticed where you just rushed away and it matterd alot to students. when you were explaining the size of manifolds and laterals, there you skipped alot... if you have already given much of your time for.preparing lectures, please make them very clear and understandble...
i total did not like your videos
This IITK professor should go to a farmer in Maharashtra and should get some hands on experience before going to give lecture to students. Very poor presentation.🤮🤮🤮
Right, his calculations are not satisfactory
Sir pls explain how did you caluculated Q value 2961lph
For finding velocity through lateral, ypu divided the discharge in lateral by its area... how you got 2961 lph for discharge????
atleast you must have explained that..WTF
any reply here
I am getting half the value
2 liter discharge ,20 mm lateral का example क्यों नही देते, किसान रात भर हर 2-3 घंटे में cock बदलते रहे ।
Discharge कम और lateral mm ज्यादा रखने पर एक ही बार ज्यादा देर के लिए pump चलकर और काम या आराम कर सकता है ।
Why does he not just use a friction loss chart to calculate the head loss at the flow rate?
Good