Dude this video finally helped me learn how to do this. You are so much better at teaching than my teacher who does nothing to make sure everyone understands.
THE REASON HE ADDED NEGATIVE 2 when the equation is 2x +3 And there is X under in order to get rid of the 2 you would have to add -2 and you cant only do it to one you have to distribute it to the whole problem.
But where did you get -2 from???! I dont understand it at all I am so confused and I want to die and cry. I am in 8th grade and I dont understand this one bit, it switches up really weird.
Dude he got negative two because he wanted to cancel the number out. If it was positive two, it would've equalled four. But if you change it to negative two, it'll be zero. I'm an eight grader who was confused so I understand how you feel so I hope that sort of helps.
+MyWhyU Thank you so much! I'm in eighth grade algebra and I've been struggling with systems the entire year. This was such a great help. Again, thank you!
at 2:11 it showed 2x + 3y = 15 and x - 3y = 3 and they said to add the like terms. If a subtraction sign is in front of the number, its considered a negative number. I'm about to finish doing this, for accelerated math grade 7. But I'm just giving you tips just in case youre new to this
@@adi4937 I found it out, the goal is to eliminate x or y so you multiply the top or bottom (or both) in order to get a like -2x and 2x or any other positive and negative
bLiXy in math u are allowed to multiply by a random number if u multiple the both side by the same number. Let’s say u got 5x=10 u can do 2(5x)=2(10) see I’m multiplying both sides by 2 and the answer won’t change, it will be 10x=20. It’s the same thing
So I was like dying in class and all bc I got random ones right and random ones wrong, right? So I watch this and BAM! I find my problem. I was multiplying the variables by each other every time no matter what. Like, say 2x+4y=2 and 4x+5y=56 or whatever. Instead of just multiplying the top one by 2, I would multiply the top by 4 and the bottom by 2. (solving for x)
Hello. First off, I would like to start of by thanking you for teaching me how to do this but I have a question. What is there were questions that was like 7(x + 5) = 2( y + 3) do you have any good tips on making this easier? 4(x + y) = 13 + 3x
A good first step is to change the form of both equations to Ax + By = C. 7(x + 5) = 2(y + 3) --> 7x + 35 = 2y + 6 --> 7x - 2y = -29 4(x + y) = 13 + 3x --> 4x + 4y = 13 + 3x --> x + 4y = 13 The system of equations is: 7x - 2y = -29 x + 4y = 13
You bring the -2x to the opposite side so that it becomes + then, we have 4x =3y-5 and when u even bring the 3y to this side we have, 4x-3y = -5 then you solve it As usual.
Thanks this helped me a lot I get this math a little more better now I don't understand six grade math that well but i understood video !!!☺😊😂😁😅 thanks!!!.
Multiplying both sides of an equation by the same non-zero constant gives an equivalent equation with the same solution set. Therefore, both sides of an equation can be multiplied by negative two during the elimination process if it helps to find the solution.
+Chamisa Bass When everything cancels out, producing the equation 0 = 0, this indicates that the system consists of two dependent equations and therefore has an infinite number of solutions. Watch algebra chapter 39 - "Inconsistent, Dependent, & Independent Systems", and chapter 40 - "Solving Inconsistent or Dependent Systems", for more information about dependent systems.
+Mighty We want the sum of the x terms in the two equations to be zero when the equations are added, so multiplying both sides of one equation by negative one is essentially the same thing as subtracting the second equation from the first equation.
If you multiply the second equation by one fourth and add the two equations, you will get the equation 0 = 6 which indicates that the system is inconsistent, having no solutions.
I dont understand if y is by itself on one side of the equation if it should be combined into 2y or just stay its own variable as y. This doesn't help at all.
Hello Aurora: The goal of the elimination method is to create an equation which contains only one variable (either x or y) by adding two equations from the system of equations. However, in order to produce an equation with only one variable, you may need to first multiply one or both equations by non-zero constants before adding. If we wish to eliminate "x" given the two equations 2x + 3y = 15 and x - 3y = 3, we must find multipliers for one or both equations which cause the x terms to cancel when the equations are added. Multiplying both sides of the second equation by negative 2 before adding will cause the x terms to cancel, producing the equation 9y = 9 or y = 1.
+Jay Patel You can always eliminate a variable by multiplying the term in one equation which includes that variable by the coefficient of the term for the same variable in the other equation and vise versa and then subtracting one term from the other. For example if equation one included the term 3x and equation two included the term 4x then we would multiply equation one by 4 and equation two by -3 and add the two equations.
x + 2y = -14 x - y = 13 Using elimination to solve this problem you can decide to either start by eliminating x and solve for y, or eliminating y and solve for x . The easiest approach is probably to eliminate x by multiplying the second equation by negative one and adding the two equations. This gives the equation 3y = -27 or y = -9. Substituting this value for y back into the second equation gives x -(-9) = 13 or x = 4. Don't forget to check these results by plugging these values for x and y back into the original equations and making sure they work.
+ProGaming If you multiply one equation by negative one and add the two equations, you will get a statement which can never be true, such as 0 = 7. This indicates that this system is "inconsistent" and therefore has no solutions. For more information on this, check out "Algebra 39 - Inconsistent, Dependent, and Independent Systems".
+michelle perex Hint: You could eliminate "x" by multiplying the second equation by -2 and adding the two equations, or you could eliminate "y" by multiplying the first equation by -4 and adding.
+dagonet molina If you multiply the first equation by -3 and then add the two equations, you will get 0 = -1. This indicates that this system is "inconsistent" and therefore has no solutions. For more information on this, check out "Algebra 39 - Inconsistent, Dependent, and Independent Systems".
Thanks. I'll be back next week when I forget
😂😂😂😂😂😂
Hows it going in 2018?
mood
@@danielcherisme6159 oh it's ok right now. Why?
@@griffinmietzner it's 2022
Dude this video finally helped me learn how to do this. You are so much better at teaching than my teacher who does nothing to make sure everyone understands.
PREECH
Try my RUclips channel mathfullyexplained
this video was actually very useful. I liked how he kept it entertaining, but not so entertaining thats it's like a little kids show.
ELIMINATION HAS ME SHOOK, THIS VIDEO HELPED ME SOOOO MUCH.
2:00 Addition Elimination
4:23 Multiplication Elimination
7:20 Multiplication with no common integer multiplier
Try my RUclips channel mathfullyexplained
This is very helpful. It is very understandable and explained it better than my teachers.
Don’t worry I moved to a SPED class. We good
Try my RUclips channel mathfullyexplained
Why did my teacher have such a complicated way of doing this, this video is much simpler and useful.
Try my RUclips channel mathfullyexplained
@@mathfullyexplained stoprommoting
This so hard way i have easy way to put this sum
2x + 3y = 15
2x = 15 - 3y
x = 12/2
x = 6
"Simpler" lmao
Clear, deliberate, and efficient! The animations were clarifying enhancements, not distractions. Great video!
i was having a hard time figuring what to do when the x have no way of canceling out each other and you helped me to solve it,thanks.
Algebra 2 be on some shit but watching this i feel like I’m learning 🤷🏻♀️
Try my RUclips channel mathfullyexplained
I would like to start of by thanking you for teaching this.Thank you so muchhh
Another excellent video from Why U. It really helps in understanding how to solve systems of equations.
Me: I’m taking Algebra 1... who in the world is taking Algebra 37?! (Realizes) oh yeah I was just joking.... hehe... 😰
You're a saint my dude
THE REASON HE ADDED NEGATIVE 2 when the equation is 2x +3
And there is X under in order to get rid of the 2 you would have to add -2 and you cant only do it to one you have to distribute it to the whole problem.
You did a better job explaining this than anything else i could find and this helped my notes a ton.
you made this 100x easier holy crap
this video really helped me as my school teacher couldn't explain it and I couldn't afford a tutor. thank you
Thank uuu cuz I didn’t learn anything from my teacher with this
I LIGIT CHECKED ALL VIDS BUT NON WERE GOOD. THIS IS THE BEST SOLVING SYSTEM OF EQUATIONS VID EVER I RECOMMEND IT IF YOUR 6 THROUGH 9TH GRADE
bruh my school must be dumb then, cause im doing this in 10th grade in higher level maths
@@apologies5398I’m going into 7th grade and learning this :l
I’m having a mental breakdown ;c
@@natalie423 looks like its true my school isn't good in maths
Try my RUclips channel mathfullyexplained
But where did you get -2 from???! I dont understand it at all I am so confused and I want to die and cry. I am in 8th grade and I dont understand this one bit, it switches up really weird.
Dude he got negative two because he wanted to cancel the number out. If it was positive two, it would've equalled four. But if you change it to negative two, it'll be zero. I'm an eight grader who was confused so I understand how you feel so I hope that sort of helps.
take deep breaths
Try my RUclips channel mathfullyexplained
this GUY IS AWESOME!!!!!!! Keep your awesome videos man i liked and subscribed!
2:24
he is basically telling us 1-1=0
This makes my life so much easier. Thanks.
wow, ok im subscribing to this guy, i actually understand this now 😮
Nice n very easy ways of solving....thank u sir...
online school:
Try my RUclips channel mathfullyexplained
amazing video, you're a lifesaver
i wish this guy can be my math teacher forever
You're better than my teacher
Try my RUclips channel mathfullyexplained
@@mathfullyexplained oh okay, thanks
+MyWhyU Thank you so much! I'm in eighth grade algebra and I've been struggling with systems the entire year. This was such a great help. Again, thank you!
I love this
Thanks for help I have bad teashar
gharib game العب yes I have a bad “teashar” too.
@@thereisalwaysarainbowafter1364 lol 😂
Thank you so much it was really helpful
so helpful! thank you
Make more videos! Your video really helped me with my homework!
at 2:11 it showed 2x + 3y = 15 and x - 3y = 3 and they said to add the like terms. If a subtraction sign is in front of the number, its considered a negative number. I'm about to finish doing this, for accelerated math grade 7. But I'm just giving you tips just in case youre new to this
Thank you. It helps a lot❤️
It’s safe to say that u r the best math teacher ever.
Thank goodness for this video ! It really explained better than my math teacher she confused me so much
truuue I mean he isn't confusing, I just sometimes don't understand it. other than that, this is the best vid for this topic😁😀
your presentations are beautiful !
Where did you get -2 from?
Why would you distribute that random number to all the others in order to eliminate x
where in the video?
@@adi4937 I found it out, the goal is to eliminate x or y so you multiply the top or bottom (or both) in order to get a like -2x and 2x or any other positive and negative
bLiXy in math u are allowed to multiply by a random number if u multiple the both side by the same number. Let’s say u got 5x=10 u can do 2(5x)=2(10) see I’m multiplying both sides by 2 and the answer won’t change, it will be 10x=20. It’s the same thing
Try my RUclips channel mathfullyexplained
So I was like dying in class and all bc I got random ones right and random ones wrong, right? So I watch this and BAM! I find my problem. I was multiplying the variables by each other every time no matter what. Like, say 2x+4y=2 and 4x+5y=56 or whatever. Instead of just multiplying the top one by 2, I would multiply the top by 4 and the bottom by 2. (solving for x)
Easier when numerical coefficients are opposites ( - 4 and 4) sum is zero. Try my RUclips channel mathfullyexplained
VERY helpful, test tomorrow. 😅
I WAS LEGIT BOUT TO RIP MY HOMEWORK THIS JUST SAVED ME!!!!
its the best math tutor
Lol!!! I fell so smart now!
Thanks a bunch! This video really helped
@MyWhyU, I have a question. This video helps a lot, but how do yo solve this problem?
-14=-20y - 7x
10y + 4=2x
This would be greatly helped. Thx!
you can find the answer to your question here
ruclips.net/video/dQw4w9WgXcQ/видео.html
@@user-px6ye4is9d YOU FUCK
@@user-px6ye4is9d damn gonna do him like that
@@user-px6ye4is9d WHY YOU GOTTA DO ME LIKE THIS.
Slightly Depressing Waffle fucking waffle
How do you know what number to multiply by
Thank you, great explanation and video!
Try my RUclips channel mathfullyexplained
Very helpful thank you
thank you so much, it helped me a lot on clarifying a couple of things.
Thx now I'm ready for my test :D
Hello. First off, I would like to start of by thanking you for teaching me how to do this but I have a question. What is there were questions that was like 7(x + 5) = 2( y + 3) do you have any good tips on making this easier?
4(x + y) = 13 + 3x
A good first step is to change the form of both equations to Ax + By = C.
7(x + 5) = 2(y + 3) --> 7x + 35 = 2y + 6 --> 7x - 2y = -29
4(x + y) = 13 + 3x --> 4x + 4y = 13 + 3x --> x + 4y = 13
The system of equations is:
7x - 2y = -29
x + 4y = 13
what if i have a question 6x=3y-5-2x
You bring the -2x to the opposite side so that it becomes + then, we have 4x =3y-5 and when u even bring the 3y to this side we have, 4x-3y = -5 then you solve it As usual.
+Drovan Reddy How about this:
2y=3(x+4)
5x+2y=-4
I'm so confused!
Perfectly explained.
Try my RUclips channel mathfullyexplained
Can you just use the first one on every equation? It made more sense to me
Thanks this helped me a lot I get this math a little more better now I don't understand six grade math that well but i understood video !!!☺😊😂😁😅 thanks!!!.
Good video, ending starting to confuse me however
thank you so much i'm frensh and i understand you more than the fucking frensh lessons thx
Greeaaaaaaaaat thx my teacher mister George didn't explain it
Do you always add the top and bottom equations?
THANKS!!! ^~^ this helped sooo much
Thanks! this helped a lot.
play it at 1.25x speed, you're welcome
Skynexstar *sigh* mobile can't.
Zenarif Ender yes mobile can
IM IN 8TH GRADE
same 😭I literally having a mental breakdown doing the work
Aye mate I’m in 7th (well it’s blended classes so my math is combined with 8th but I’m in seventh)
@@firewee1615 im going into 7th grade and learning this :l
Don’t worry I’m having a mental breakdown too.
Try my RUclips channel mathfullyexplained
Real
Sooo muchhh effort for the animation
Very helpful, thank you
In this equation how did you get -2 when the equation is x-3y=3?
This just helped me a lot, thanks you just earned a subscriber :D
how would i solve this?
3x+2y=16
4x-3y=9
I've tried to use all methods but I always get confused
Keep them coming. Love WhyU
Substitution sucks. So glad elimination is an option.
You a League player and you struggle at Algebra?
:)
+Guinsoos Rageblade I'm a challenger and I struggle at math.
Im a mlg mincrafter an i suk at matth
Thank You so Much
I'm confused on the thing about multiplying by negative 2. If that happens doesn't it change the equation?
Multiplying both sides of an equation by the same non-zero constant gives an equivalent equation with the same solution set. Therefore, both sides of an equation can be multiplied by negative two during the elimination process if it helps to find the solution.
How do you solve when everything cancels out??
-12x-15y=-9
4x+5y=3
+Chamisa Bass When everything cancels out, producing the equation 0 = 0, this indicates that the system consists of two dependent equations and therefore has an infinite number of solutions. Watch algebra chapter 39 - "Inconsistent, Dependent, & Independent Systems", and chapter 40 - "Solving Inconsistent or Dependent Systems", for more information about dependent systems.
thank you sir
what would you do if you had 3x-5y=-35 and 3x-5y=12
plese make video for rectangle construction too and algebric diagram
thank you I didn't get it dieing class and now I do!
Thank you
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Why did you add the negative at the 7:51 mark?
+Mighty We want the sum of the x terms in the two equations to be zero when the equations are added, so multiplying both sides of one equation by negative one is essentially the same thing as subtracting the second equation from the first equation.
you helped a lot
how do you do x+y=3
-4x-4y=12? I am so confused on it....
If you multiply the second equation by one fourth and add the two equations, you will get the equation 0 = 6 which indicates that the system is inconsistent, having no solutions.
MyWhyU thank you
I dont understand if y is by itself on one side of the equation if it should be combined into 2y or just stay its own variable as y. This doesn't help at all.
Always combine all the y terms and all the x terms into a single y term and a single x term.
Prove that||x+y||=||x-y|| then =0 ?
How can I solve it?
Can anyone help me?
Why negative 2 and not a different negative number?
Hello Aurora: The goal of the elimination method is to create an equation which contains only one variable (either x or y) by adding two equations from the system of equations. However, in order to produce an equation with only one variable, you may need to first multiply one or both equations by non-zero constants before adding. If we wish to eliminate "x" given the two equations 2x + 3y = 15 and x - 3y = 3, we must find multipliers for one or both equations which cause the x terms to cancel when the equations are added. Multiplying both sides of the second equation by negative 2 before adding will cause the x terms to cancel, producing the equation 9y = 9 or y = 1.
what if the equation system is 6x+y=4
x-4y=19
how about this 5x-3y=18
x+4y=24?
I know this is probably too late but I think
x=144/23 and y=102/23
Please solve this one for me.
What is the value of X and Y if 4x -+ 2y - 2 = 30
Wheres the second system of Equation?
Get photo math or ask your parents or friends ;-;
Peace Ozokwere nice
What if you have different x and y's and can't get them alone
+Jay Patel You can always eliminate a variable by multiplying the term in one equation which includes that variable by the coefficient of the term for the same variable in the other equation and vise versa and then subtracting one term from the other. For example if equation one included the term 3x and equation two included the term 4x then we would multiply equation one by 4 and equation two by -3 and add the two equations.
helpful👌🙏thanks
Nice
where the -2 come from ? help please!
Okay so i have a problem one of my questions on my algebra paper is x+2y=-14
x-y=13
would you solve this problem the same way you did the last problem
x + 2y = -14
x - y = 13
Using elimination to solve this problem you can decide to either start by eliminating x and solve for y, or eliminating y and solve for x . The easiest approach is probably to eliminate x by multiplying the second equation by negative one and adding the two equations. This gives the equation 3y = -27 or y = -9. Substituting this value for y back into the second equation gives x -(-9) = 13 or x = 4. Don't forget to check these results by plugging these values for x and y back into the original equations and making sure they work.
thank you so much!!!!
what if the equation is
5X+7Y=-1
5X+7Y=6
+ProGaming your shit outta luck
+ProGaming If you multiply one equation by negative one and add the two equations, you will get a statement which can never be true, such as 0 = 7. This indicates that this system is "inconsistent" and therefore has no solutions. For more information on this, check out "Algebra 39 - Inconsistent, Dependent, and Independent Systems".
***** thnx ;)
***** can you help me with this one
-14x+y=-12
-7x+4y=1
+michelle perex Hint: You could eliminate "x" by multiplying the second equation by -2 and adding the two equations, or you could eliminate "y" by multiplying the first equation by -4 and adding.
Thank god i saw this i had an test about it
thanks a lot :)
why didnt you add 15 and 14 at 8:43 ?
Kirk Salmon It's +15y - 14y, which equals 1y. If the coefficient is 1, you typically do not write it.
thank you alot .
What if the question is this?
6x+2y=1
18x+6y=2
+dagonet molina If you multiply the first equation by -3 and then add the two equations, you will get 0 = -1. This indicates that this system is "inconsistent" and therefore has no solutions. For more information on this, check out "Algebra 39 - Inconsistent, Dependent, and Independent Systems".