I was wondering if I could get further explanation on the last example with the 3 carbon chain. Why would attaching the O at either end with the carbon in the middle be the same? I don't know if that made sense but thank you so much for these videos they help a lot
Ask and ye shall receive! This was set to be released later today but I just released it early just for you! 5.1 Overview of Isomers | Constitutional Isomers and Stereoisomers ruclips.net/video/q3_UBRKzkHQ/видео.html I'll be releasing the remaining lessons in this chapter throughout the week which include the following: 5.2 Absolute Configurations - Assigning R and S 5.3 Molecules with Multiple Chiral Centers 5.4 Fischer Projections 5.5 Isomeric Relationships Between Molecules 5.6 Amine Inversion and Chirality without Chiral Centers 5.7 Optical Activity Happy Studying!
Hi Vladimyr! A ring incorporates a degree of unsaturation having 2 fewer hydrogen atoms. The last two examples were both saturated hydocarbons so cyclic carbon chains would not have worked. If you draw one out you'll see that it must have 2 fewer hydrogen atoms. Hope this helps!
Thank you so much
I wish I started with you at=the beginning of the semester
Glad you found us!
Truly grateful for your work!
Thanks for saying so.
THANK YOU SO MUCH! I have my first orgo exam tomorrow and you just saved me!
You're welcome - I hope you do well!
What a Chad!
Welcome to the channel.
I was wondering if I could get further explanation on the last example with the 3 carbon chain. Why would attaching the O at either end with the carbon in the middle be the same? I don't know if that made sense but thank you so much for these videos they help a lot
You would get the same structure above the 3 carbon chain.
Thank you
You're welcome
Do you have a video on enantiomers? If not can you do one please!
Ask and ye shall receive! This was set to be released later today but I just released it early just for you!
5.1 Overview of Isomers | Constitutional Isomers and Stereoisomers ruclips.net/video/q3_UBRKzkHQ/видео.html
I'll be releasing the remaining lessons in this chapter throughout the week which include the following:
5.2 Absolute Configurations - Assigning R and S
5.3 Molecules with Multiple Chiral Centers
5.4 Fischer Projections
5.5 Isomeric Relationships Between Molecules
5.6 Amine Inversion and Chirality without Chiral Centers
5.7 Optical Activity
Happy Studying!
@@ChadsPrep Omg! Thank you so much! we're covering this topic now and I needed this
Well my professor gave us C5H11Br and that is not saturated and now I'm confused on how to do this
I'd have to see the question, as this seems to be bromopentane
Couldn't another example include cyclic carbon chains?
Hi Vladimyr! A ring incorporates a degree of unsaturation having 2 fewer hydrogen atoms. The last two examples were both saturated hydocarbons so cyclic carbon chains would not have worked. If you draw one out you'll see that it must have 2 fewer hydrogen atoms. Hope this helps!
@@ChadsPrep thank you
You're welcome.
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