Pillai: "Function of Two Discrete Random Variables: max(X, Y), min(X,Y)". (Part 5 of 6)

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  • Опубликовано: 19 ноя 2024

Комментарии • 35

  • @lekokotonteso
    @lekokotonteso 5 лет назад +1

    Amazing! He just made me want to study wherever he is lecturing just because of his emphasis on not making minor mistakes because however minor they may be, their effect may cost someone a huge financial loss.

  • @namangoyal1986
    @namangoyal1986 8 лет назад +5

    Hats off to you sir. Very helpful videos.

  • @mathewslisboa3718
    @mathewslisboa3718 2 года назад

    HOW CAN I HAVE CLASS WITH THIS MAN

  • @rameshkhatri9257
    @rameshkhatri9257 8 лет назад +2

    Great teacher...I salute you sir ..Thank you very much

  • @cnbrksnr
    @cnbrksnr Месяц назад

    extremely good lecture

  • @PankajKumar-ot3mg
    @PankajKumar-ot3mg 3 года назад

    great pedagogy
    love from india

  • @rakeshkumar-nm6lm
    @rakeshkumar-nm6lm 2 года назад

    Very knowledgeable sir 🙏

  • @ernestgty1442
    @ernestgty1442 7 лет назад +4

    super informative, thank you so much I really needed this (:

  • @kritikasharma2127
    @kritikasharma2127 3 года назад +1

    I am not getting that B intersection A union A' at 7:29...why we add that AUA'

    • @probabilitystochasticproce2625
      @probabilitystochasticproce2625  3 года назад

      The same logic was used earlier at 2:34 Watch that first. The problem becomes linear if we use the partition A = X>Y and Abar = X

    • @alexeyzaa9399
      @alexeyzaa9399 2 года назад

      @@probabilitystochasticproce2625 for me it still unclear, why in "max" part we should use _union_ with (A union Abar) but for "min" part we should use _intersection_ with (A union Abar).

    • @probabilitystochasticproce2625
      @probabilitystochasticproce2625  2 года назад

      @@alexeyzaa9399 . A intersection Abar is always the empty set, 0; no matter what A is. So intersecting A with Abar makes no sense. Whereas AUA' is always the whole set, so intersecting with AUA' with B will remain as B. Then simplify it as BA U BA' where BA and BA' are always mutually exclusive. Then proceed w/ the context of the problem.

  • @TheFinalRevelation1
    @TheFinalRevelation1 9 лет назад +2

    Well explained

  • @Wasim_Raza
    @Wasim_Raza 4 года назад

    Let X and Y be a uniformly distributed random variable over the interval [0, 4] and [0, 6] respectively. If X and Y are independent
    events, then compute the probability, P(max(X, Y ) > 2)
    a) 1/6
    b) 5/6
    c) 2/3
    d) None of the above

  • @blogginbuggin
    @blogginbuggin 5 лет назад

    Thank you so much for the illustrations!

  • @HansyProductions
    @HansyProductions 8 лет назад +1

    Actually pretty helpful, thanks!

  • @ShivaniAMehta
    @ShivaniAMehta 4 года назад

    Thank you so much Sir.

  • @alexzhang330
    @alexzhang330 4 года назад

    Sooooo much better than my shitty prob teacher and textbook combined, very well explained!!

  • @mamus165
    @mamus165 6 лет назад +1

    Why cameraman doesnt focus on the teacher's interested part of blackboard ?Teacher explain somethin that he wrote on the board before and is explaining something but we only see the teacher hair and back.He explains very critical point of the course we see again teachers back or hair .This cameraman is messing up this valuable teacher's labour.

  • @naitikgreyman
    @naitikgreyman 8 лет назад

    Your so good at teaching. Your my idol

  • @123XTSK
    @123XTSK 2 года назад

    very fluent

  • @rinatgorbachev5007
    @rinatgorbachev5007 3 года назад

    thank you

  • @ms97
    @ms97 5 лет назад +1

    wow

    • @probabilitystochasticproce2625
      @probabilitystochasticproce2625  5 лет назад +1

      I hope you got something out of the lecture.

    • @ms97
      @ms97 5 лет назад

      Defiantly had a few "aha" moments. Thanks :D @@probabilitystochasticproce2625