How do the units work out to be rad/s? I understand that radians have no units so we can take them out if it doesn't fit our answer but does that mean we can just add them in anytime when describing angular displacement? or is there a better way to think about this? Thanks for the awesome videos!
Thanks for the video, very cool! I’m actually looking at this as a reference for a golf swing as you are swinging a mass on the end of a stick in golf. I was wondering if there is an equation to find out how much force you have to put in with your hand to maintain the radius. It seems you have to be constantly pulling against the mass in the opposite direction to get a smooth radius. Thanks for your help! 👍🏼
We don't need to consider Tension to my understanding. We are looking at the forces acting on the water mass inside the bucket. So it would be the mass of the water and the normal force on the water mass due to the bottom of the bucket.
Because it takes careful planning, knowledge, technical skills, and a whole lot of time. See: flippingphysics.com/making-a-video.html Glad you think it is useful!
I have a question for when you are solving the problem. So I had mg = mv^2/r. while you have mg = mrw^2. when I solved I got 2.76 m/s and you got rads/s. Is the difference in answer because of the units used, and the equation that I used?
I am pretty sure the difference is that I used angular velocity and you used tangential velocity. I talk about the difference in this video after the 4 minute mark. www.flippingphysics.com/centripetal-acceleration.html
Can someone explain how the tension force is 0 at that point? Also can we takeaway from this video that when a rope is slack it is at rest and that the tension force is 0?
Sir it's was very helpful ❤️ teacher gave me this question so can I consider r=0.77m in this.......what is minimum speef of a bucket filled with water at the highest point so that water does not spill during vertical circular motion???
Indeed it does. Roller coaster inverted loops, are designed such that the passengers only feel a push from their seat, rather than tension in their restraint harness. When you are at rest in the loading station, you only feel an upward push from your seat. When at the top of the inverted loop, you also only feel a push from your seat, albeit much less of a push force. You feel like you are pulled by an apparent force that acts radially outward, holding you in contact with your seat. But the reality is, you are accelerating downward toward the center of the loop's curve, at a rate slightly greater than g. The normal force from your seat plus gravity are causing this acceleration. The restraint harnesses are only there in case the real method of supporting your body doesn't work, such as if the roller coaster doesn't pick up enough speed, and you actually do fall downward in to your harness. It would be an uncomfortable ride for passengers if it was built for this to happen on a regular ride, so the ride is designed in order to avoid this situation.
Ultimately, it is the normal force from the base of the bucket that pushes inward on the water. But the substance of this problem is the same, whether you examine the tension in the rope, or the normal force at the base of the bucket. Ultimately, we are looking at solving for the special case, where an object can follow the circular path with no constraint force at the very top of the curve, and the object will momentarily be in free fall.
i used another method came out as 204 degrees /s , that looks way off :( (i used the speed that ensures 1g upward to be canceled with g then i divided that speed by the circumference and multiplied by 360)
that the same value except 3.6 is in radians per second not degrees per second. to convert degrees to radian multiply by pi/180 and you will get close to the same value
We are drawing the free body diagram on the water and bucket system. The force normal between the water and bucket is internal to that system, so we do not include it in the free body diagram.
Wow!
Love the way you ACTUALLY do the experiment and not show some animated video to explain it!!
I always do my best. Glad you appreciate it!
honestly this helped more than my actual phys teacher. thank you so much
This video should get more views and like.
Hope you will get it next time
Thanks for the sentiment. I'll just keep making videos; views and likes with come.
Wow! The production of this video is unreal! I love the creativity!
Thanks so much!!
Thanks, man. I was doing a book in which this experiment was needed. This video really helped!
Saweet! Glad to help.
The each points u have covered actually are my doubts which has been cleared till now...amazing physics by amazing teacher
Best Physics videos on the net. Enjoy learning Physics.
Ahh man! Thanks a lot 🙏
That helps me....
Sending love from Bangladesh 🇧🇩
You are welcome my friend!
sir you are the best Thank you for your contribution in youtube not even a second of the video was boring sir thank you very much
Glad you appreciate it!
The only video found where they really explain without hiding behind theories
😀
Amazing. You simplified the concept. Thanks.😀
'tis what i do
sir you are too good... you deserve more.. i have subscribed
Such amazing videos for physics,plz make more
Currently making more.
How do the units work out to be rad/s? I understand that radians have no units so we can take them out if it doesn't fit our answer but does that mean we can just add them in anytime when describing angular displacement? or is there a better way to think about this? Thanks for the awesome videos!
Love from india what a practical teaching
Thank you!
Thnks the way you explained my real teacher he never taught me thnks
Thanks for the video, very cool! I’m actually looking at this as a reference for a golf swing as you are swinging a mass on the end of a stick in golf. I was wondering if there is an equation to find out how much force you have to put in with your hand to maintain the radius. It seems you have to be constantly pulling against the mass in the opposite direction to get a smooth radius. Thanks for your help! 👍🏼
I love the explain..it's soo practical👍👍
Thank you so much for your excellent videos. So well done. Huge help.
You are welcome. Glad to help you learn!
We don't need to consider Tension to my understanding. We are looking at the forces acting on the water mass inside the bucket. So it would be the mass of the water and the normal force on the water mass due to the bottom of the bucket.
Thank you sir😭😭😭😭
Very good practical demonstration followed by the physics. Why can't everyone do that?
Because it takes careful planning, knowledge, technical skills, and a whole lot of time.
See: flippingphysics.com/making-a-video.html
Glad you think it is useful!
@@FlippingPhysics I know. I have a degree in physics and I look for ways to help the students I tutor.
@@nugget9245 Well, I hope you sometimes use my videos to help your students learn.
Superb teacher
I love your style of video! Really informative, thank you :)
You are welcome!
you guys deserve more views. Keep it up!
Thanks. I will do my best. You can help!! flippingphysics.com/help-out.html
Also should not the tension force be upwards because the bucket is falling down?
I have a question for when you are solving the problem. So I had mg = mv^2/r. while you have mg = mrw^2. when I solved I got 2.76 m/s and you got rads/s. Is the difference in answer because of the units used, and the equation that I used?
I am pretty sure the difference is that I used angular velocity and you used tangential velocity. I talk about the difference in this video after the 4 minute mark. www.flippingphysics.com/centripetal-acceleration.html
Can someone explain how the tension force is 0 at that point? Also can we takeaway from this video that when a rope is slack it is at rest and that the tension force is 0?
Sir it's was very helpful ❤️ teacher gave me this question so can I consider r=0.77m in this.......what is minimum speef of a bucket filled with water at the highest point so that water does not spill during vertical circular motion???
Glad I can help. Please make sure you *understand* the solution and do not just copy it down. 😬
@@FlippingPhysics sure♥️
Omg I love your channel
v=(5gr)^1/2 this velocity u required to move the bucket or any thing without going down from bucket and moves in vertical circular motion
Just amazing
Thanks!
does this also applied on roller coaster physics? because the function is the same as the bucket of water
Indeed it does. Roller coaster inverted loops, are designed such that the passengers only feel a push from their seat, rather than tension in their restraint harness. When you are at rest in the loading station, you only feel an upward push from your seat. When at the top of the inverted loop, you also only feel a push from your seat, albeit much less of a push force. You feel like you are pulled by an apparent force that acts radially outward, holding you in contact with your seat. But the reality is, you are accelerating downward toward the center of the loop's curve, at a rate slightly greater than g. The normal force from your seat plus gravity are causing this acceleration.
The restraint harnesses are only there in case the real method of supporting your body doesn't work, such as if the roller coaster doesn't pick up enough speed, and you actually do fall downward in to your harness. It would be an uncomfortable ride for passengers if it was built for this to happen on a regular ride, so the ride is designed in order to avoid this situation.
I am confused. Does the tension force even work upon water ? I thought the tension force only works upon bucket since it is connected with a string.
Ultimately, it is the normal force from the base of the bucket that pushes inward on the water. But the substance of this problem is the same, whether you examine the tension in the rope, or the normal force at the base of the bucket. Ultimately, we are looking at solving for the special case, where an object can follow the circular path with no constraint force at the very top of the curve, and the object will momentarily be in free fall.
Nice creativity
Thanks.
it's just perfect!!!
Thank u soo much! It helped a lot 💜
Glad to help
Good job :) Looks like another hair donation is approaching? Keep up the great work.
Probably. Starting to look a little too much like an 80's hair band member.
i used another method came out as 204 degrees /s , that looks way off :(
(i used the speed that ensures 1g upward to be canceled with g then i divided that speed by the circumference and multiplied by 360)
that the same value except 3.6 is in radians per second not degrees per second. to convert degrees to radian multiply by pi/180 and you will get close to the same value
👍
Thank you 👍
You are welcome.
Ur amazing
Thanks.
Shoudn't you include the normal force between the water and the bucket??
We are drawing the free body diagram on the water and bucket system. The force normal between the water and bucket is internal to that system, so we do not include it in the free body diagram.
I found out your IQ level in this video. Your IQ level is about 260.
why don't you factor in the weight of the bucket and water?
If you follow along with the math, you will eventually see that weight cancels out and is irrelevant.
Will the water even stay in bucket if the bucket is full
Yes, if the large force does not rip the handle off the bucket or out of your hand.
amazing!!
thank you! I enjoyed your violin videos as well.
thank you as well !! :)))
9.82 m/s? (Before watching)
Everybody brought mass to the party 😎🥳😎
❤️
gud art
wow