Extreme Value Theorem

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  • Опубликовано: 18 окт 2024

Комментарии • 43

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  Год назад +2

    Derivative Applications - Formula Sheet: bit.ly/4eV6r1b
    Final Exams and Video Playlists: www.video-tutor.net/
    Next Video: ruclips.net/video/Bp9EbV3COVA/видео.html

  • @SNIPE263
    @SNIPE263 4 года назад +30

    Just wanted to say thanks for your videos man! They're super helpful and the way you explain is easy to follow. I can literally type in any concept and you've made a video for it. amazing!

  • @Dmangames-gg3cl
    @Dmangames-gg3cl 2 года назад +8

    Love these videos. very helpful for night before cramming for calculus mid term

  • @Zenbeau
    @Zenbeau 4 года назад +124

    you are DOING GOD's WORK. You have a video on everything that's in my first year uni calculus course

  • @georgesadler7830
    @georgesadler7830 Год назад +2

    MR. Organic Chemistry Tutor, thank you for a solid explanation of the Extreme Value Theorem. This is another important theorem in Calculus/Advanced Calculus. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.

  • @Sabineee3
    @Sabineee3 5 лет назад +29

    A question in my maths textbook told me to comment on "extreme values". So here I am!

  • @aguilarexequielandrew4758
    @aguilarexequielandrew4758 5 лет назад +22

    keep doing what youre doing! helps alot

  • @krovely8649
    @krovely8649 Год назад

    you are the best, you always have a video on literally anything I search

  • @azaa2188
    @azaa2188 4 месяца назад +1

    4:38 Reasoning for no absolute minimum on left graph: the interval isn't closed at points a and b. // a and b are at open intervals and therefore can't have absolute maximums or minimums. if a was a closed point, then it would be abs. minimum
    On right graph, b represents an abs minimum because it's lowest point AND has closed interval. C is not abs max, because its an open circle.
    5:13 right graph, the EVT doesnt apply here because there is a break in the graph, therefore no closed interval

  • @rodelynespinosa6311
    @rodelynespinosa6311 11 месяцев назад

    thank u so much u always save my life

  • @ahlam5915
    @ahlam5915 4 года назад +2

    God bless ur mind

  • @ilkeuyankerstudent5347
    @ilkeuyankerstudent5347 5 лет назад +4

    thankss

  • @zeroblade8315
    @zeroblade8315 4 года назад +6

    question if u had a horizontal line at a closed interval[a,b] EVT says there should be a max and a min right, but there isn't one, in that case right?

    • @just.a.guy522
      @just.a.guy522 4 года назад +6

      You could say that the minimum and the maximum values are the same, equal to the line's y value. Or you could also say that the EVT doesn't apply to constant functions.

    • @zeroblade8315
      @zeroblade8315 4 года назад

      @@just.a.guy522 Alright thx

  • @HDitzzDH
    @HDitzzDH 6 лет назад +11

    5:30 Wouldn't f(d) be considered a local maximum since that is an endpoint?

    • @therencehabon2916
      @therencehabon2916 6 лет назад +1

      The graph isn't​ a closed interval

    • @explorerofworlds512
      @explorerofworlds512 4 года назад

      I think in this case it is a relative maximum that happens to also be the absolute maximum. I think of them as attributes or descriptions of the point that are not mutually exclusive. Think if it was a graph of temperature. Just because it's the hottest portion on the graph doesn't mean it is Not the hottest portion in its region in fact the hottest portion on the graph will inevitably also be the hottest portion of its region.

  • @ElifArslan-l9g
    @ElifArslan-l9g 3 года назад

    thank you

  • @felipenetto5646
    @felipenetto5646 5 лет назад +8

    What if the function is for example y=1? it is continuous for every xER and it has neither max and mins

    • @justmisu
      @justmisu 5 лет назад +4

      In those cases, the maximum and minimum are the same. The smallest value you can get is also the highest value possible

    • @sustrata9125
      @sustrata9125 Год назад

      ​@@justmisu could you say that it has neither min nor max?

  • @emmanuelssali6694
    @emmanuelssali6694 3 года назад +1

    Thanks a lot. But how would I tell if a graph contains open circles or closed circles?

    • @kasm1488
      @kasm1488 2 года назад +5

      ( ) this show it open, [] it show closed

  • @matthewkoob7600
    @matthewkoob7600 Год назад

    What a god.

  • @explorerofworlds512
    @explorerofworlds512 4 года назад

    Shouldn't this be called the definition of extreme values & not the extreme values? There's no proof you can make for this. It seems like we literally define relative mins & maxs values as points at which x equals 0 between an decreasing & increasing slope. We do the same for absolute max & min as the largest possible value of our function i.e if there is a maximum or minimum value to the function.

  • @Humblemanvice
    @Humblemanvice Год назад +1

  • @Humblemanvice
    @Humblemanvice Год назад

    Our Savior 😂

  • @kissmeok1004
    @kissmeok1004 3 года назад

    엑스바 어찌됨evt

  • @daizybaby1088
    @daizybaby1088 2 года назад +1

    really bad never understood anything from the video!!!! and never did

  • @dontyouwonder
    @dontyouwonder 9 месяцев назад

    this video was not very useful