Hi Shashank…Thanks for appreciating my work…and congrats for doing awesome in examsI am sure this channel has helped you learn…You can support my channel by donating and do watch this video: ruclips.net/video/WfyUEhxhjZUH/видео.htmlave a nice day.
Thank you so much sir ...Your videos have equally helped me in clearing my critical graphics subject . So blessed You are doing a great job sir ! Respect
A rectangular room, a peg is drawn at the centre of the floor. Another peg is drawn at the midpoint of the common edge between the two mutually perpendicular walls. The minimum length of the thread connecting these two pegs is 5.5m. The thread makes 300 with the floor. The TV of the thread makes 400 with the longer wall. Find graphically the size of the room.
A straight line PQ, equally inclined to the HP and the VP, has its end P in front of the VP and 20 mm above the HP. End Q is behind the VP and 40 mm below the HP. A point on this line is in the VP and 10 mm below the HP. Draw the projection and finds TL and inclination of line with HP, if the distance between the projections ends is 60 mm.
God bless u sir ,u r really doing a great job ,,ur vedio's really helped me a lot ,once again i heartly express my gratitude to u for this noble cause ,stay blessed ,rise and shine
Hi Arif..... I am sure that these videos are helping u learn... Keep watching and do let your friends know about this channel so that they can also benefit.......
a line AB 75mm long is in the second quadrant with the end A in the HP and end B in the VP the line is inclined at 30 deg in the HP and 45deg in the VP draw the projection of AB and find traces.
A line PQ, 75 mm long, has its end P in the V.P and the end Q in the H.P. The line is inclined at 30 degree to the H.P and at 60 degree to the V.P. Draw its projections. Sir how to do this kinda problem?
A 80mm long line AB is inclined at 30° to the H.P. and 45° to the V.P. Its midpoint C is 25mm above the H.P. and 45mm infront of the V.P. Draw its projections.
Sir what if there are no inclinations and given like this end A is 10mm in front of VP and end B is nearer to HP in this midpoint sum please help me with this doubt sir
Aren't we supposed to make the full true length of line PQ by extending it backward from mid point? You just extended apparent one(s). Just a doubt, try to answer.
A line PQ 100 mm long is inclined at 30° to the H.P. and at 45° to the V.P. Its mid point is in the V.P. and 20 mm above the H.P. Draw its projections, if its end P is in the third quadrant and Q in the first quadrant.
A line PQ, 80 mm long has its end P 15 mm above the HP. Line makes an angle of 30o with HP and 45o with the VP. End Q of the line is 10 mm in front of VP. Draw the projections the line considering it in first quadrant. How to slove this question
sir can u solve this problem. A point M is 50 mm above HP and 15 mm behind the VP .and other point N is 20 mm below HP and 30 mm in front of VP. the distance between the projectors of M and N is 70 mm. (1)draw the projections mn and m'n' of the line MN. (2) determine the traces of line joining M and N. (3) determine the inclination of straight line with reference frames. (4) determine the true length of MN. please solve and upload sir. I suggested u r channel to most of my frnds and still i will suggest to my coming juniors. thanking you, SATYA......
the midpoint of 80 mm long line is 30 mm above hp and 30 mm infront of vp the line inclined is 30 degree to hp and 45 degree with in the vp draw the projections of the line Pls say solution
Sir can you explain this sum please A line AB 100mm long measures 80mm in front view and 70mm in top view. The mid point M of the line is 65mm from both HP and VP. Draw the projections of the line and find it's inclination with the planes of reference HP and VP
Tomorrow is My EG exam.... you saved me sir..if I would've found u early,I would've scored centum...hats off 😀😘
bhai relatable moment...mera bhi kal hai paper...help kar dena plssssssssssssssssss
Engineering khatam ho gaya bro 😂
@@ahmedwaseem6207 paper Kaisa gaya phir??
This is our core subject and your are very helpful for me sir....I scored good marks only because of u sir..... Thanks a lot sir.......
Hi Shashank…Thanks for appreciating my work…and congrats for doing awesome in examsI am sure this channel has helped you learn…You can support my channel by donating and do watch this video: ruclips.net/video/WfyUEhxhjZUH/видео.htmlave a nice day.
Thank you so much sir ...Your videos have equally helped me in clearing my critical graphics subject .
So blessed
You are doing a great job sir !
Respect
❤
Sir explain the principle of how this steps work
Line is in second quadrant. How to show the projection
This deserves more views
A rectangular room, a peg is drawn at the centre of the floor. Another peg is drawn at the midpoint of the common edge between the two mutually perpendicular walls. The minimum length of the thread connecting these two pegs is 5.5m. The thread makes 300 with the floor. The TV of the thread makes 400 with the longer wall. Find graphically the size of the room.
A straight line PQ, equally inclined to the HP and the VP, has its end P in front of the VP and 20 mm above the HP. End Q is behind the VP and 40 mm below the HP. A point on this line is in the VP and 10 mm below the HP. Draw the projection and finds TL and inclination of line with HP, if the distance between the projections ends is 60 mm.
God bless u sir ,u r really doing a great job ,,ur vedio's really helped me a lot ,once again i heartly express my gratitude to u for this noble cause ,stay blessed ,rise and shine
Hi Arif.....
I am sure that these videos are helping u learn...
Keep watching and do let your friends know about this channel so that they can also benefit.......
Very helpful
PROJECTION OF LINE | RELOADED | BEST ANIMATIONS: ruclips.net/p/PLIhUrsYr8yHwEyvIlxf4EDsfoStqk2JMu
Thanks a lot ...it helped me to prepare for exams day before it.
Thanks Himanshu for the appreciation
All the best...
And do let your friends know about this channel so that you all can benefit...
Sir which software are you using?
a line AB 75mm long is in the second quadrant with the end A in the HP and end B in the VP the line is inclined at 30 deg in the HP and 45deg in the VP draw the projection of AB and find traces.
Superb explaination
You are so helpful sir
You did a lot for us which our sir couldn’t : in lines n in planes also !
Thanku once again 🔥🔥🔥
Useful video 👍👍.Is the FV of point Q ,q' and TV q?please reply...
Nice video sir ji
Hi.............
I am sure my videos are helping you learn.....
Keep watching and do share this with your friends also...
All the best......
What if m divides pq in 4:5 ratio??
Can u explain the approach sir?
A line PQ, 75 mm long, has its end P in the V.P and the end Q in the H.P. The line is inclined at 30 degree to the H.P and at 60 degree to the V.P. Draw its projections.
Sir how to do this kinda problem?
A 80mm long line AB is inclined at 30° to the H.P. and 45° to the V.P. Its
midpoint C is 25mm above the H.P. and 45mm infront of the V.P. Draw
its projections.
Sir what if there are no inclinations and given like this end A is 10mm in front of VP and end B is nearer to HP in this midpoint sum please help me with this doubt sir
very helpful sir
Very good explanation sir thank you so much 🙏
King 👑 of ED
Sir when we check the true length .it is not found to be 100 mm
tum bhut acha kaam krta hai maksood bhai.
All the best
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1. Engineering Drawing/Graphics (English): ruclips.net/video/WG6H2pISUzQ/видео.html
2. Engineering Drawing/Graphics (Hindi): ruclips.net/video/SB83cUaAiCM/видео.html
3. Engineering Mechanics / Applied Mechanics: ruclips.net/video/Z4WN2Z9okfs/видео.html
4. Mechanics of Solids / Strength of Materials / Mechanics of Materials: ruclips.net/video/Co4YlavCpeQ/видео.html
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8. Physics for Class 11: ruclips.net/video/0fejUC79LZY/видео.html
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10. Channel 2 Link:
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thanksssss alotttttttt ❤️...May god bless you 😊
Hi Shezan.....
I am sure this channel is helping you learn...
All the best.....
Aren't we supposed to make the full true length of line PQ by extending it backward from mid point? You just extended apparent one(s). Just a doubt, try to answer.
This is the half-line approach....
And this seems to be very easy and casual.....
A line PQ 100 mm long is inclined at 30° to the H.P. and at 45° to the V.P. Its mid point is in the V.P. and 20 mm above the H.P. Draw its projections, if its end P is in the third quadrant and Q in the first quadrant.
A line PQ, 80 mm long has its end P 15 mm above the HP. Line makes an angle of 30o with
HP and 45o with the VP. End Q of the line is 10 mm in front of VP. Draw the projections the
line considering it in first quadrant. How to slove this question
Shouldn't we rotate q1' and then drop a perpendicular to locus line thru q to get Q? Why is it done in reverse?
sir....can you solve few exercise problems [10(b)].... they're pretty difficult.... anyway awesome video
Thank you sir
Sir I will make this figure on exam but in ND bhatt book figure is not given this type so sir mark will be given me on this question or not
Thank yu .
It is really helpful
p'q1' is supposed to be true length but here it is not so?
Awesome sir😊😊😊👌
Why can't we draw full line and then from Q draw projections to loucs line of P. And further solve like normal problems
Thanks sir
sir can u solve this problem. A point M is 50 mm above HP and 15 mm behind the VP .and other point N is 20 mm below HP and 30 mm in front of VP. the distance between the projectors of M and N is 70 mm. (1)draw the projections mn and m'n' of the line MN. (2) determine the traces of line joining M and N. (3) determine the inclination of straight line with reference frames. (4) determine the true length of MN. please solve and upload sir. I suggested u r channel to most of my frnds and still i will suggest to my coming juniors. thanking you, SATYA......
Thank you very much sir
the midpoint of 80 mm long line is 30 mm above hp and 30 mm infront of vp the line inclined is 30 degree to hp and 45 degree with in the vp draw the projections of the line
Pls say solution
What if m is not mid point but at random distance from q please upload this type of questions
Sir what about when other end point lies in second quadrant pls explain Sir
Sir what we have to do when the angle above HP is no given??
hey that was good but I want to know the lengths of PL & EL
very helpful
Tq sir
can you make video on how to do reverse of this problem when angles with vp and hp is not given but TL is given.
Thanks sir ,love you
All the best Tarun.....
Sir can u upload more problem like this one
Sir I have two problems relating mid point that u hv not covered .how can I contact u?
Shiva....add me on FB messenger and post the problem description.
sir can u tell alpha and beta here!?
so that i can check my answer
Rutvik........Alpha is 45 deg and Beta is 55 degrees....
Manas Patnaik
thank you very much sir
Sir what are the imp topics for FE 1st Semester
sir can u send me one video in related to second quadrant and fourth quadrnt ppppppppppplllllllllllzzzzzzzzzzzzzz
i mean similar to above question
Sir I have a doubt sir
Technic achhi h sir
sir,what is the book that u r refering?
I refer ND Bhatt and PS Gill...
These are the two best books on engineering drawing.............
Manas Patnaik Thanq sir😊
Sir can you explain this sum please
A line AB 100mm long measures 80mm in front view and 70mm in top view. The mid point M of the line is 65mm from both HP and VP. Draw the projections of the line and find it's inclination with the planes of reference HP and VP
Where is the true length sir
Please watch the video again my friend....
sir plz help me over this problem
+radhika Agrawal
WHat is the issue radhika......
+Manas Patnaik sir i m not getting how to solve this problem..
Sir i want to ask ques
Sahil Gupta yes sahil.....go ahead...whats the matter
Hello
Hello sir WhatsApp
Bhai Hindi mein bhi bol liya kar
Thank you sir
+Ajay Zade
Hi Ajay....
You are welcome....
All the best
Thank u so much sir
Thanks Sir