35:00: Everything I know, I learned from the "Great B". But, I'm still learning, and this drove me nuts for a few days. Please let me know if making K should have been "negative" on left side of = sign. It is the only way it works out for me. I tried the math and many simulations to prove it out. Is False: Ix+KI1 = I1+(I1R1/R2)+ (I1R1/R3+R4||R5)+Iy Is True: Ix-KI1 = I1+(I1R1/R2)+ (I1R1/R3+R4||R5)+Iy Also True: Ix = I1+(I1R1/R2)+ (I1R1/R3+R4||R5)-KI1+Iy => Ix-KI1 = I1+(I1R1/R2)+(I1R1/R3+R4||R5)+Iy Finally "I1" I1 = Ix-Iy/(I+(R1/R2)+ (R1/(R3+R4||R5))+K) Thank You for any help! MGM
21:00 Why doesn't he put a ground on the schematics. When inserted into the circuit simulator, the simulation without gnd does not work, and when gnd is inserted, the current through the R1 and R2 branches is 0? Thank you.
35:00 NO HELP YET!!!! What he says about current going in equals current going out makes sense. But the dependent current source other than 1 to 1 (no gain) will not follow KCL. The extra current has to come from somewhere. The formula will only work if K is reversed logic. Example, K being positive with the other drains (I1+I1R1/R2+KI1,,,etc,,) or negative when moved left of the equals sign. PLEASE, if anyone else has tried this example, let me know what worked out for you! Thank You MGM
35:00:
Everything I know, I learned from the "Great B". But, I'm still learning, and this drove me nuts for a few days. Please let me know if making K should have been "negative" on left side of = sign.
It is the only way it works out for me.
I tried the math and many simulations to prove it out.
Is False:
Ix+KI1 = I1+(I1R1/R2)+
(I1R1/R3+R4||R5)+Iy
Is True:
Ix-KI1 = I1+(I1R1/R2)+
(I1R1/R3+R4||R5)+Iy
Also True:
Ix = I1+(I1R1/R2)+
(I1R1/R3+R4||R5)-KI1+Iy
=>
Ix-KI1 = I1+(I1R1/R2)+(I1R1/R3+R4||R5)+Iy
Finally "I1"
I1 = Ix-Iy/(I+(R1/R2)+
(R1/(R3+R4||R5))+K)
Thank You for any help!
MGM
Thank you!
21:00 Why doesn't he put a ground on the schematics. When inserted into the circuit simulator, the simulation without gnd does not work, and when gnd is inserted, the current through the R1 and R2 branches is 0? Thank you.
35:00 NO HELP YET!!!!
What he says about current going in equals current going out makes sense. But the dependent current source other than 1 to 1 (no gain) will not follow KCL.
The extra current has to come from somewhere.
The formula will only work if K is reversed logic.
Example, K being positive with the other drains
(I1+I1R1/R2+KI1,,,etc,,)
or negative when moved left of
the equals sign.
PLEASE, if anyone else has tried this example, let me know what worked out for you!
Thank You
MGM
11:43 how the current from voltage source and resistor are the same. as the voltage source do not follow the ohm's law.
pick any point between the voltage source and the resistor, apply KCL, you can see that the current is the same.