Refraction and Snell's Law

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  • Опубликовано: 1 янв 2025

Комментарии • 11

  • @zebra2218
    @zebra2218 29 дней назад +1

    your way of explaining physics is crazy good.

  • @luquinhas5004
    @luquinhas5004 4 года назад +3

    This is a great explanation 👍🏻

  • @Kamron99
    @Kamron99 4 года назад +1

    great explanation, thank you!

  • @sawyerhall6564
    @sawyerhall6564 4 года назад +3

    when you wrote the case descriptions on the left you wrote N2>N1 twice.

  • @haroldmanweiler4654
    @haroldmanweiler4654 4 года назад +1

    Great video. Hoping you can clear something up for me. How does wavelength change, but frequency does not? I have been beating myself up on this one.

    • @PhysicsNinja
      @PhysicsNinja  4 года назад +2

      That's a great question Harold! I'm not sure i can answer here but i'll give it a try. Speed of waves typically depend on 2 things - restoring forces divided by inertial terms - for waves on a string we get v=sqrt(T/mass density). So if i thin string is connected to a larger one and keep the tension uniform the wave on a thin string will have a faster speed because it's mass density is smaller. The frequency will depend on the source - in this case the person holding the thin string moving their hand up and down. At some point the thin string is connected to the larger one. At this point the frequency must be the same on both sides - otherwise the string is going in different directions. At the end if the speed changes - (medium changes)- frequency is the same - wavelength has to also change. For electromagnetic waves the arguments are a little more complicated but similar. The speed of the light in medium depends on the properties of the medium. The frequency depends on the source only (whats doing the shaking up and downs to create the electromagnetic waves) At the boundary the frequency must be the same otherwise there would be mismatch between the waves in different medium which would violate several laws of physics (Maxwell's Equation).

  • @raphaelkingen6945
    @raphaelkingen6945 7 месяцев назад

    can light be reflected even if total refraction occurs?

  • @AhmedKhaleelAhmedAhmed
    @AhmedKhaleelAhmedAhmed 29 минут назад

    thank you

  • @yourfavouritescepticx8969
    @yourfavouritescepticx8969 5 лет назад

    I’m unable to get this answer in my calculator 😔

    • @xxdenixx21
      @xxdenixx21 4 года назад

      Make sure your calculator is in degrees and not radians. On a TI-83 or similar calculators, you should be able to do (2nd)(sin^-1) and that will open parenthesis. Type in (1/1.33) and hit enter. Should get the 48.75 degrees.