Probability using permutations and combinations : ExamSolutions
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- Опубликовано: 15 сен 2011
- Permutations and combinations probabilities.
In this tutorial I demonstrate how to calculate probabilities using permutations (arrangements) and combinations.
See also
PERMUTATIONS AND COMBINATIONS PLAYLIST at • Permutations and Combi...
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I am shocked literally you post this video 10 years ago..... youtube give you award for the founder of educational content on youtube
I would recommend this playlist to anyone struggling with perms and combs.
BEST EXPLAINATION EVER
faxxx
Hope it goes well for you - Good luck.
1st 11C5 is wrong... It is 77..
Thanks! You remind me of Ross from F.R.I.E.N.D.S.
Cheers - that's a new one.
I can't unhear his voice now
@Grady Rowen dunno if anyone told u but you are a lifesaver lmaoo
@@ExamSolutions_Maths hey how you make these videos ?
If he was British
Thank you and all the best for tomorrow.
I have been looking for a good hour now for a clear tutorial on probability with combinations, and I have finally found it here! Thank you so much
I've been struggling with perms and combs since the start my A levels, and finally now, after a year, I understand them, maybe now I'll pass my A level! Thank you so much!
I always wonder if you passed ur A levels
@@internetborn I did, I have my bachelor's now
@@ZazzlesGS shoutout
could i bag you
youre so cute @@ZazzlesGS
No probs, pleased to hear they helped
Thanks to u I just found the answer to a maths problem I spent the last half hour straining my mind over, thanks!
AMAZING now at least I understand how the two are different and when to use them, thank you
You are one in a million or one in 100 years kind of a teacher. It is hard to find one like you, you deserve special mathematics society honor confirmed upon to teachers like you similar to fields medal. Always stay upbeat, you are blessed. Thanks a million.
You should train and produce mathematics teachers like u.
You are great . Many videos do not explain the same thing so well as you do. Thanks a lot.
thank you v helpful, million times better than my teacher!
You guys are good. This kind of explanations makes probability simple. Kudos!
well elaborated.... I have got no problem at all... thank you very much🙏
Your videos are outstanding! and I really appreciate it, thank you.
Your explaination is great and clear,thank you so much.
You really deserve more subscription. Keep up the hard work! Really understood and would really be blessed if you are my lecturer.
Cool. Keep at it and I am sure you will get there.
thanks man! I have an exam today on combinations and permutations and this really helped!
Thanks a lot. I was really confused about the permutation and combination part. But you cleared it. Thanks!!!❤️
Glad it was helpful!
@anglican09 Pleased to hear you found it helpful.
Thank You! Your videos are so clear, and are really helping me get through my AS! Thanks!!! :)
you explain so much better than my teacher!! Thank you so much!!
that was a really awesome series very well explained
Bro thank you so much. You helped me out so much. I wish i could give you a warm hug. Keep up the great work broo!👍
Thank you for saving my life.
Omg you're a lifesaver and a really awesome teacher ❤️❤️
This was amazing! Thank you so much.. your way of explaining is awesome! :)
Flattery will get you everywhere!
You are helping me more than my teachers. I finally have a grasp on it! Thank you! :)
Well done.
Omg thank u soo muchhh i owe u big bits if it werent for i i wouldnt have graduated
thank you so much! it's our finals today and I really needed this I love you!
+pauline valdez I wish you every success.
wow i did not understand even i took days but i understand in 5 minute on this thank u
you are an excellent teacher ... may the King reward you
Thank you! This helped me out a lot.
Omg thank you so much, exams are coming up and I just realised that I do not understand how to do probability worded questions
Thanks alot. I wamted this last one bit to do questions with both P and C and Probability mixed.
Now I understand better! =D
Thank you! ^^
I'm having my examination on Monday! I was still finding a way to solve this stuff but later when I got into this channel I understood nearly 90% of this Permutations and combinations in Probability
How was your examination bro.....?😄😄
Found this the night before my statistics exam, thank you so much! I may have a chance now!
did you pass?
It is most wonderful series of lectures i have ever seen on Utube for aforesaid topic do u have few more lectures on the same pls do upload the lec for circular permutation & pls do inform me i very much greatful to u for ur lectures
Thanks. Well explained 👏
Got stuck with this subject during online classes. TY
Pleased it helped. Best wishes.
thank you very much from oman. You have helped me a lot
Amazing Thank You !!!!!
Excellent video! Really helped! Thanks a lot!
Thanks for watching.
Thanks a lot mate.
thank you very much for the video :)
thank you sir !!!
This was a great video thanks a lot!
Cheers - thanks for watching
Thank you so much 💖
thanks super helpful
Thank you very much!!!:)
Oh so helpful! Thanks
Good to hear, thank you
thank you sir 😊
saw this questions on a cambridg statistics as level past paper, very usefull thanks!
Rly? I wished Im gonna have questions like this this coming OCT NOV AS test
very understandable teacher.
Thank you
thanks man that was awesome
Thanks
thank you, friend :D
This is the easy stuff........ I need more advanced examples.
thanks a LOT
Thanks Gordon
i) 29C6 is correct and (ii) 29C7
You explain better than my professor. I can't even read half my professor's handwriting.
really helpful series, pls make 1 on geometric and binomial distribution
ruclips.net/video/NaDZ0zVTyXQ/видео.html&ab_channel=ExamSolutions Please check out our series on the binomial distribution.
Good
A multiple-choice question on an economics quiz contains 10 questions with five possible answers each. Compute the probability of randomly guessing the answers and getting exactly 9 questions correct.
I figured the answer should be 10C9*((1/5)^9)*(4/5). But a website says it is 9*4/(5^10). I will be grateful if you can clear the confusion.
Good luck
7 years later, thank you
Good day sir, I just want to ask quick question, where did you get the 120 and the 48 from? I tried to work it out where you actually get the 120 and 48 from, can you explain on the comment box please!
october exams are close and thank god your videos are so damn helpful keeo up the good work
Thanks and good luck.
@@ExamSolutions_Maths
Hi sir can you tell me the answer for this question.
A coach has 16 players and can pick from 11 players for a match. it consist of 7 specialist batsmen, 4 fast bowlers, 3 spinner and 2 wicketkeeper. how many different teams can be formed if it must comprised of 6 specialist batsmen, 3 fast bowlers , 1 spinner and a wicketkeeper.
@@kathleenolivier1588 7C6 * 4C3 * 3C1 * 2C1 Dude use combinations.
@@isi6402 divided by 16C11
this is an easy question....do one where the letters of a word have to be in an order and we need that probability
Yes it can be
Thank you! I don’t live in an English speaking country, but your videos make much more sense than my professor (˃̵ᴗ˂̵)
In the second example, when finding the no of arrangements where A and B are together, shouldn't we divide by 2! instead of multiplying?
Also, thank you very much your videos explain the concepts very well!
no you should multiply. since a and b can swapped and still be grouped together (b before a), that effectively doubles the number of possible arrangements that have a and b being beside each other which is why you multiply the 4! by 2.
Im actually dont understand how and when I gonna use P and C. Thanks, now Im understand. Tomorrow I have quiz about Statistics. zzz
+NurFarrah Soda Good Luck - I hope it goes well for you.
+ExamSolutions Thanks again. 😊
me too
@ExamSolutions hey im in 7th grade and learning this and this was helpful a lot but how did u know wether or not it was combination or permutation? If u have a trick with this it would help a lot and i am now going to use these videos for future reference all of the time get it or not. Thanks for being such a smart person and being able to do this stuff. To me this is difficult
if the quesrion is asking to arrange, then permutation, if ir's asking to SELECT/CHOOSE, it's combination
watching from 2024 amazing video really 🫡🫡
@MsHeartBreaker16 cool
If I roll 2 dice and the only thing I care about is sum of these dice should I use permutation or combination?
Andy has 5 toy ships and 6 toy planes. He wants to make an exhibition showing 3
models of one kind and 4 models of the other kind. How many ways there are to pick the exhibition
set from his collection?
good luck on fri guys
@stupermanana thanks I passed it....with a 65...now I'm in 8th grade so yea thanks again only 2 months too late tho...
can u use the notation (permutation) for the ABCDE question, as in 4 permute 2 (eg) because I dont understand how to show it.
In how many ways can seven students from a class of 30 be chosen for a field trip if Jack must go on the field trip. I'm assuming this is the same equation as 6 out of 29 students being chosen (29 nCr 6 on a graphing calculator). Is that correct? I'm assuming on the next question (what if Jack can't go on the trip) is the same formula. I just want to make sure I'm doing it right. Thanks, guys! You rock!
what if by any chance cards with letter A and B refuses to be together what would the solution be?
You Made this EASY - awesome teacher. you are SAVING my ass right now!
Saving ass's is what I do.
how come for the second video the nPr=n!/(n-r)! wasn't used?
dont worry ur stil in grade 7^^ permutations: order matters (how many ways can 5 books be arranged on a shelf) the way you order the books.
Combinations: order doesn't matter. eg (how many ways can 3 groups be formed from 7 ppl, the order doesn't matter)
I didn't quite follow you on the ABCDE problem. How exactly did you come up with 4! ways of A and B being together? There are only 5 places for an A; out of those 5 places, for 2 of them - first and last, there's only one place a 'B' can be put, to be next to A, and out of remaining 3 middle places for 'A', there are only two neighboring places for 'B' to be next to 'A'.
Which gives us total of 1+1+2+2+2 = 8 combinations for A and B to be next to each other.
thanks.
My teacher decided to teach this instead of giving us an EOC exam.
is this for o level add math?
is it OCR?
Sir may you clarify?
In the second example did you mean 4!/2! Or 4! × 4! ?
Neither. 4! x 2!
Care to elaborate any further?
oh and im having a quiz tomorrow March 30
Why do we multiply the combinations instead of adding them up? Can someone explain?
Sean Tristan Francisco principles of counting...multiplication rule
Sean Tristan Francisco
Sean Tristan Francisco...because there are different sets... So we have to use the multiplication operation. However, if we have the same set then we can use adition.
There were 5 gaps to fill not 6
48 is the correct ans dude
Anyone else using this to experiment with herbs in Pathologic?