sir, it might sound crazy, but you can teach yourself a long division method with which you can find the CR of ANY number to 10 digit accuracy in 14 to 20 minutes. On less than 1 sheet of paper.. Pen/paper only. No calculator help. What is the CR of 169.993 421 007 666 552 891 600 748 003 444, taken out to the 10th digit?? By now, someone like you should be able to do that in less than 20 minutes
I have no idea what ur talking about but it's a good concept. I can see immediately the cube root of 4096 is 16 however, the CR of 4 being 1~ and the digit root of 6 = 6
a is your currently completed root in each iteration b is your next digit in your CR in each iteration. It is easier in each iteration to square the current a, and multiply by 300. 300a^2. Also multiply the current a by 30. 30a (Write them beside each other in your workspace beside the long division configuration) Using those, estimate your next digit b Add that to the 30a figure. 30a +b Multiply that by the b. b(30a + b) Add that to the 300a^2 figure Multiply that again by b. Write that under your current remainder. Subtract, bring down your next 3 digit group. This is you new remainder Proceed. I find this far easier than what he does What is the CR of 259601.222174338? I can find the CR of that number (or any number) to 10 digit accuracy in about 16 minutes using only 2/3rd of a sheet of paper Imagine using his method to do that! You couldn't! He is only at the very beginning of really learning how to do CRs in an efficient manner
Best teaching sir
sir, it might sound crazy, but you can teach yourself a long division method with which you can find the CR of ANY number to 10 digit accuracy in 14 to 20 minutes. On less than 1 sheet of paper.. Pen/paper only. No calculator help.
What is the CR of 169.993 421 007 666 552 891 600 748 003 444, taken out to the 10th digit??
By now, someone like you should be able to do that in less than 20 minutes
I have no idea what ur talking about but it's a good concept. I can see immediately the cube root of 4096 is 16 however, the CR of 4 being 1~ and the digit root of 6 = 6
Sir
How did you get the 100? 3 × 1 × 6 × 100 why not × 96?
Why did u take 6. So poor explanation!
a is your currently completed root in each iteration
b is your next digit in your CR in each iteration.
It is easier in each iteration to square the current a, and multiply by 300. 300a^2.
Also multiply the current a by 30. 30a
(Write them beside each other in your workspace beside the long division configuration)
Using those, estimate your next digit b
Add that to the 30a figure. 30a +b
Multiply that by the b. b(30a + b)
Add that to the 300a^2 figure
Multiply that again by b.
Write that under your current remainder.
Subtract, bring down your next 3 digit group. This is you new remainder
Proceed.
I find this far easier than what he does
What is the CR of 259601.222174338?
I can find the CR of that number (or any number) to 10 digit accuracy in about 16 minutes using only 2/3rd of a sheet of paper
Imagine using his method to do that! You couldn't!
He is only at the very beginning of really learning how to do CRs in an efficient manner
G8