Professor Hanson ,thank for an excellent introduction to Friction Forces. This topic is really the beginning of Engineering Physics One for first year students in science and engineering
So basically, you can just carry the friction variable throughout the calculations until the end, and then give it a positive and negative sign for the minimum and maximum weights.
For some of the forces yes, as is the case with W2, the normal force, and the firction force. All three of these are coincident with the new xx axis (W2 and friction) or the new yy axis (normal force). However, the weight of W1 is always vertical, which means that when you tilt the axis it's no longer coincident with yy. They are always on the Oxy plane, just on different "coordinates" so to speak. That's why you use the components, so that you can sum and subtract these vectors that are at an angle with each other. Don't know if this made sense, or if it's still helpful but yeah :)) good luck!
hold on, the problem asks to find the weight of w2 to maintain equilibrium, but you calculated the min and max values. so, what is the weight of w2 to maintain equilibrium?
Man my professor sucks, discussed friction and moment of inertia in one discussion. The finals was three days later…. Thank youuuuuu. I failed the exams
4:26 and the answer is depending on the angle of your legs with the floor, and lets be honest at the picture youe draw legs are at an angle thats not 90, so there is a reaction by the friction in the horizontal direction. If that wasn't the case your drawing will need to take some gymnastic lessons
You deserve a medal. I’m basically paying tuition for a course whereas there’s a better teacher online for free
Professor Hanson ,thank for an excellent introduction to Friction Forces. This topic is really the beginning of Engineering Physics One for first year students in science and engineering
Let the bodies hit the floor LOOOL
Professor Hansen is so fricking good & funny. He's such a gem!
Thank you do much, I wish my teachers were Fun and Interactive
Just in time for my final next Friday! Thank you!!
How did it go?
@@parva7152 we will never know...
A subscriber and a student from India 🇮🇳
"just drive 70 above the bumps" lmao
So basically, you can just carry the friction variable throughout the calculations until the end, and then give it a positive and negative sign for the minimum and maximum weights.
Wonderful Statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
Got my bachelor's in 2015, If I could turn back the hands of time, nonetheless I'm still provided with more clarity!!
These videos are awesome thanks a lot
Why do you break them into components if you tilt the axis? Would they not just be on the x y plane and not need components?
For some of the forces yes, as is the case with W2, the normal force, and the firction force. All three of these are coincident with the new xx axis (W2 and friction) or the new yy axis (normal force). However, the weight of W1 is always vertical, which means that when you tilt the axis it's no longer coincident with yy.
They are always on the Oxy plane, just on different "coordinates" so to speak. That's why you use the components, so that you can sum and subtract these vectors that are at an angle with each other. Don't know if this made sense, or if it's still helpful but yeah :)) good luck!
are cos and sin backwards in this? shouldnt the force on the y axis be 100sin30 instead of 100cos30?
wait, 100sin30=100cos60...ok I think i figured it out, I was mixing up reference angles
can you add section how to solve cables in your videos? thank you!
I encounter some teaching videos:
they solve the resultant force first before including the friction force
let the bodies hit the floor awooooga thanks daddy Jeff for your grate videos
hold on, the problem asks to find the weight of w2 to maintain equilibrium, but you calculated the min and max values. so, what is the weight of w2 to maintain equilibrium?
Ur a legend mate thank u for these vids
Dr. Hanson still #1
Love You Professor Hanson THANK YOU SOO MUCH !!
question here shouldnt it be
Man my professor sucks, discussed friction and moment of inertia in one discussion. The finals was three days later…. Thank youuuuuu. I failed the exams
thanks
Love these videos! Keep it up.
Thank you so much for these
May I know why you are using .35N as the value of friction yet it is given in the question as it's coefficient
N in this case represents normal force, not newtons- He is saying for it to be (0.35)*(Normal Force)=Friction
Thank you soooooo much sir for your help and me and friends appreciate your great afer
Thank you so much
Will the direction of tension change too if the direction of friction opposes.
No, the cable will always be pulling so it will always point in that direction. Cables can not push, they only pull.
Friction = fun
Why is the y component 100cos30 instead od sin30?
Rotated axis
let the bodies hit the floor
7 hours before my final exam
:( wish me luck
what about exam
@@arift.dogan.youtube i got A+ ;)
From what I can see, there is not a playlist for statics on your channel? If you have some free time, that would be really helpful! Love the videos!
he does have one :)
4:26 and the answer is depending on the angle of your legs with the floor, and lets be honest at the picture youe draw legs are at an angle thats not 90, so there is a reaction by the friction in the horizontal direction. If that wasn't the case your drawing will need to take some gymnastic lessons
Georges !
Oau student
of of of
feet feet
Cc