Junior JavaScript Interview - Part 2: Algorithm + Debrief

[@rdnexta]

what is the name of this extention, when he typing, we saw somthing in front of that line. plz let me know.

[@casull6447]

Thanks for your effort Justin

[@harpo187bling]

Thanks for these videos.

[@justinmlawrence]

Glad you like them!

[@RainOnline]

Would this be a good solve?
function findUnique(arr) {
let allArrs = [];
for (let i = 0; i < arr.length; i++) {
allArrs = allArrs.concat(arr[i]);
}
console.log([...new Set(allArrs)]);
}
findUnique(words);

[@casull6447]

by the way here is my "amazing" solution for this question :)
const uniqueArr = arr.map((subArr) => [...new Set([...subArr])]).flat(Infinity);
const output = [];
for (let i = 0; i < uniqueArr.length; i++) {
if (
![...uniqueArr.slice(0, i), ...uniqueArr.slice(i + 1)].includes(
uniqueArr[i]
)
) {
output.push(uniqueArr[i]);
}
}
console.log(output);

[@moezzzz9341]

This should work in python
def uniqueWords(wordsList):
hashMap = {}
counter = 0
for words in wordsList:
for idx in range(len(words)):
currentWord = words[idx]
if currentWord not in hashMap:
hashMap[currentWord] = counter
else:
if hashMap[currentWord] != counter:
del hashMap[currentWord]
counter += 1
return list(hashMap.keys())
print(uniqueWords([["hello", "goodbye", "morning", "hello"], ["goodbye", "night"]]))
Should return ['hello', 'morning', 'night']

[@prakashsubba1373]

function uniqueWords(arr) {
const obj = new Map();
const result = [];
for (let i = 0; i < arr.length; i++) {
const removeDuplicate = [...new Set(arr[i])];
removeDuplicate.forEach((word) => {
if (obj.has(word)) {
obj.set(word, obj.get(word) + 1);
} else {
obj.set(word, 1);
}
});
}
for (let [word, count] of obj) {
if (count === 1) {
result.push(word);
}
}
return result;
}

[@dzdzdzdzjbjbjbjbbjbbjb]

const uniqueWords = arrayOfArrays.reduce(folder, [])
const folder = (met, next) =>
( met.filter(e => !next.includes(e))
).concat([... new Set(next)].filter(e => !met.includes(e)))

[@justinmlawrence]

Awesome! 👏🏻

[@c-cg]

const returnSingleAppearance = (arr) => {
const unique = [];
arr.forEach((strArray) =>
strArray.forEach((string) => {
const index = unique.indexOf(string);
index >= 0 ? unique.splice(index, 1) : unique.push(string);
})
);
return unique;
};