JavaScript Interview Questions- Machine Coding - Most Asked Question

Javascript Interview Question on objects and Array will be discussed in this video .
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[@PriyaHm-o4j]

Nice explanation. Thank you ❤

[@VinitNeogi]

Should we use data.forEach instead of data.map as we are not concerned with return value of map function?

[@pranavpawar7792]

Wow such a nice explanation... I really liked your approach and logic... Thanks Nisha

[@websilt]

Another way to do this:
const items = ["a", "b", "c", "a", "b", "b", "c", "d"];
const count = {};
for (const item of items) {
if (count[item]) {
count[item] += 1;
} else {
count[item] = 1;
}
}
console.log(count);

[@sivatirumani531]

Nice Explanation

[@Aravind-mh5wh]

we can write using ternary operator like below
let ar = ['a','s','s','b','c','a','c','d','a','s'];
function arrOccurances(items){
let output = {};
items.forEach(item=>{
output[item] = output[item] ? output[item]+1 : 1
})
return output;
}
console.log(arrOccurances(ar));
(OR)
let ar = ['a','s','s','b','c','a','c','d','a','s'];
let output = {};
for(let item of ar){
output[item] = output[item] ? output[item]+1 : 1
}
console.log(output) ;
not only these ways, as Nisha said we have many ways to do it.
Thanks Nisha :-)

[@amitbm3608]

Thank u for the awesome video. Please continue react tutorial and complete the series.

[@DanielSparza]

Thanks for do this kind of videos

[@akiratoriyama1320]

Thank you!!

[@kavinkumar]

well if you cant use map ,
let arr=['a','b','z','a','b','a','c']
let obj={};
for (let key in arr) {
console.log(obj[arr[key]],arr[key]); //undefined , a initially
obj[arr[key]]?obj[arr[key]]=obj[arr[key]]+1:obj[arr[key]]=1;
}

console.log(obj)
{
a: 3,
b: 2,
c: 1,
z: 1
}

[@Aravind-mh5wh]

last line of code is repeated , so simply we can write like below
obj[arr[key]] = obj[arr[key]] ? obj[arr[key]]+1 : 1;