22:30: Can somebody explain how the net pressure diagram derived from two straight lines is a curved line, which has to be approximated by straight lines?
Hi thank you for your video so great just one question please , after 39:10 you didnt calculate the small triangle DO distance (a) , someone could explain me how did he calculate the pressure of that triangle thank you so much
Late but may be helpful for others: Small triangle part DC1 distance (a) is considered in pressure calculation at the point (C1): Ka.Gamma.(H+a)=Kp.Gamma.a
Dear Sir In the derivation of granular soil without anchoring (very first case) for writing the equation number 2 and 3 , you use pressure (Pa) that was the active pressure at the dredge line was not correct. Here we will have to use (Ra) that was the resultant of all forces above point "O" from the right-hand side. please check it.
Hey,if any one is having confusion regarding pp2b as me then it might be helpful, consider the full right side has active pressure and left side is passive pressure, Then, Pp2b = (Kp*r*d ) - (Ka*r*(H+d)) As, d=a+y from fig put in the above eqn then solve you get Also at last you need to put a condition of point c1, i.e, active pressure = passive pressure Kp*r*a - Ka*r*a - Ka*r*H =0 Then you will get Ppb2=(Kp-Ka)*r*Y
Thankyou sir ....sir one question i am confuse in cohesive soil after 39.50 calculating the moment at point B you have written Pa(y+ý) bt according to your solution there should pa(ý+D)....Ý=y bar ...
So how might this change with a varying water table? I.e., a water table on the right side up to a height, where the water table on the left side is equal to the dredge line.
In active and passive earth pressure diagrams as shown, a is from point D to O (O being the point of rotation). In net pressure diagram, point D to point C1 is also called a. Are points O and C1, both points of rotation and value of the a is the same? Anyone?
Hey,if any one is having confusion regarding pp2b as me then it might be helpful, consider the full right side has active pressure and left side is passive pressure, Then, Pp2b = (Kp*r*d ) - (Ka*r*(H+d)) As, d=a+y from fig put in the above eqn then solve you get Also at last you need to put a condition of point c1, i.e, active pressure = passive pressure Kp*r*a - Ka*r*a - Ka*r*H =0 Then you will get Ppb2=(Kp-Ka)*r*Y
Great skill Sir, The way you explain is amazing sir, May God give you healthy and long life.
Many thanks for the amazing lecture. It was very useful to me.
Great knowledge... thanks for sharing
22:30: Can somebody explain how the net pressure diagram derived from two straight lines is a curved line, which has to be approximated by straight lines?
Hi thank you for your video so great
just one question please , after 39:10 you didnt calculate the small triangle DO distance (a) , someone could explain me how did he calculate the pressure of that triangle
thank you so much
Late but may be helpful for others:
Small triangle part DC1 distance (a) is considered in pressure calculation at the point (C1):
Ka.Gamma.(H+a)=Kp.Gamma.a
Thank you for this beautiful expression.
Thank u sir so helpful u shud be the god of sheetpile
Dear Sir
In the derivation of granular soil without anchoring (very first case)
for writing the equation number 2 and 3 , you use pressure (Pa) that was the active pressure at the dredge line was not correct. Here we will have to use (Ra)
that was the resultant of all forces above point "O" from the right-hand side.
please check it.
Yes, that's what i thought. He used the pressure at O instead of the resultant force, for which the formula is F = 0.5 Ka Y H^2
Why is the net pressure at 23:30 isn't linear ?
Hey,if any one is having confusion regarding pp2b as me then it might be helpful, consider the full right side has active pressure and left side is passive pressure,
Then,
Pp2b = (Kp*r*d ) - (Ka*r*(H+d))
As,
d=a+y from fig put in the above eqn then solve you get
Also at last you need to put a condition of point c1,
i.e, active pressure = passive pressure
Kp*r*a - Ka*r*a - Ka*r*H =0 Then you will get
Ppb2=(Kp-Ka)*r*Y
Thankyou sir ....sir one question i am confuse in cohesive soil after 39.50 calculating the moment at point B you have written Pa(y+ý) bt according to your solution there should pa(ý+D)....Ý=y bar ...
Boss first that is for granular soil. And its correct if you taking moment @ B how Pa multiplied by Y+D. Its correct moment x distance wrt B point
So how might this change with a varying water table? I.e., a water table on the right side up to a height, where the water table on the left side is equal to the dredge line.
is this practical possible ?
Tnxs.for knowledgeable lecture..
In granular soil how will calculate Ybar you haven't mentioned anything.
where do you get Ka¥(H+D) in active pressure diagram
Late but may be helpful to others:
At point B total Depth is (H+D) so active pressure is Ka.Gamma.(H+D)
@@SahinAhmed but there's no active pressure acting there
Thanks for this helpful video.
Very well explained
Thank you guri ji
thank you sir...
In active and passive earth pressure diagrams as shown, a is from point D to O (O being the point of rotation). In net pressure diagram, point D to point C1 is also called a. Are points O and C1, both points of rotation and value of the a is the same? Anyone?
Good work
I need a help with designing a cofferdam .. any idea?
Z is itself variable of D and Y,how can we find Z from equation 2 and put in equation 3??
at 27:08.. you mentioned wrong distance 'a'
Indeed, that's what i noticed as well.
@@mohamedsaidamakhlouf1225 same. mee too. and there is a lot of miss explanation on the 30m and above which quite confusing.
good teaching
Less sound is the measure problem of your channel...please try to overcome this problem
headphones help
how to decide the pressure is active ya passive
When the wall/sheet moves away from the backfill-active
And when wall/sheet moves towards backfille-passive pressure.
THANKS
But you didn't explain the formation of pressure diagram for cohesive soil. Why??
Yes, he didn't, I was looking this video only for that reason, and same is missing.
@@SanjayKumar_optimist it is complicated due to the cohesion in clay
At time 13.25 explanation is not clear sir . Thanks !
video has low sound
Pp2(b) is not well explained
Same question
Yes
Hey,if any one is having confusion regarding pp2b as me then it might be helpful, consider the full right side has active pressure and left side is passive pressure,
Then,
Pp2b = (Kp*r*d ) - (Ka*r*(H+d))
As,
d=a+y from fig put in the above eqn then solve you get
Also at last you need to put a condition of point c1,
i.e, active pressure = passive pressure
Kp*r*a - Ka*r*a - Ka*r*H =0 Then you will get
Ppb2=(Kp-Ka)*r*Y
Plz provide lectures in hindi language
use a video translator (votch.tv or similar)
Sheet Pile Manufacturer - google：shunli sheet group.
get free sheet piles solutions
sir thanks but cohesive vala thoda or elaborate krte to or samjh Ataa
Acha nhi lga video sir
Not upto the standards of NPTEL
Boring
you guys are teaching outdated methods...use simplifies method instead.
Sir sorry to say but u should stop making these nonsense videos