yeah .... PUSH PUSH decrements SP (the stack pointer) by two and then transfers a word from the source operand to the top of stack now pointed to by SP.
POP transfers the word at the current top of stack (pointed to by SP) to the destination operand and then increments SP by two to point to the new top of stack.
Yes :) you are correct and the video is wrong. PUSH decrements SP and POP increments SP. This is because the larger the memory address, the deeper it is in the stack diagram.
Stack push() Method in Java The Java.util.Stack.push(E element) method is used to push an element into the Stack. The element gets pushed onto the top of the Stack. ... SP increases for push .
❤ very different and most suitable method is this to teach .. all clear about stack ... Thanks mam 😌
i think 4 types of operation are there.. Push, Pop, Peek and isempty.... correct me if I am wrong
You're always right ma'am.
Isfull?
Thank you so much for this video, it helps me a lot. I understand it clearly. Thank you so much.
thanks very much but can you send these all lesson videos
Such a beautiful...voice ma'm....totally sabh kuch dil se...sikh liya...thnQ...
thanks very much mam i clearly understood your lesson . thanks very much
Mam PUSH instruction decrement sp
Amd POP instructions increment sp
Noo
Thanku for such information
thank u sooooooo much it helped me in exam
your explanation is excellent mam. i understood clearly thanks
Super mam.. Your explanation was awesome..
Thanks mam 😊❤
PUSH instruction decreases SP by 2 and POP instruction increases SP by 2, get your facts cleared!
But in 8051 by 1 only
yeah .... PUSH
PUSH decrements SP (the stack pointer) by two and then transfers a word
from the source operand to the top of stack now pointed to by SP.
POP transfers the word at the current top of stack (pointed to by SP) to the
destination operand and then increments SP by two to point to the new top
of stack.
Depends on the micro
Thank u
Thanks
Ur great mam keep it up!!!!!!
your video is amazing mam you are great
Push means decrease....
Pop increased
Explained in an understandable manner..thnku
thank you so much 💗💗💗
PUSH instruction decreases SP..... dont teach wrong things for god sake..........
thank you :)
Ur correct
Yes :) you are correct and the video is wrong. PUSH decrements SP and POP increments SP.
This is because the larger the memory address, the deeper it is in the stack diagram.
U r right but if we consider the register then it is correct for memory it's wrong
Stack push() Method in Java
The Java.util.Stack.push(E element) method is used to push an element into the Stack. The element gets pushed onto the top of the Stack. ...
SP increases for push .
Very nice.
amazing tutorial.
The video makes me to understand clearly......but the length of video can be minimized.
Thanq sooo madam.....
thank you so much!!!
here for exam preparations😂😂
hahah same here bro...!
all the best guys
😂🤣😂🤣mine too
Tomorrow is my exam 18092018
Wish me luck
same brother tomorrow xam
Stack pointer contains the top of stack (location) not a top element of stack☺️
Voice volume should be more than now
Can you add subtitles to the videos?
this video for 8086
Push decreases sp and pop increases sp, dont spread wrong information please
yes asif you are right
8051 sp increases for push and decrease for pop,
8086 sp decreases for push and increases for pop.
Thanks ma'am
Shubham mane
bhushan musale
Aap aamesa hi galta padhti ho don't teach wrong ma'am for god sake 🙏🙏🙏
Voice is very slow please improve voice...And given subtitle into video .
Main please Hindi mein video banao
try to improve your english or you can make these types of videos in hindi which will be more helpful for the students
This video also listening south indians.....so better to teach in english
Sir she is not a professor of English it's understandable very much what she is teaching