Equations in Modular Arithmetic

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  • Опубликовано: 1 янв 2025

Комментарии •

  • @charlesjomoyeni2333
    @charlesjomoyeni2333 3 года назад +3

    NICE ONE BOSS, WELL UNDERSTOOD

  • @emperorsconquest
    @emperorsconquest 3 года назад +3

    nice very easy to understand bless boss

  • @priscillaakuffo7691
    @priscillaakuffo7691 8 месяцев назад +1

    So understanding.

  • @my_virtual_learning_hub_
    @my_virtual_learning_hub_ 11 месяцев назад

    Great video

  • @Estherolori
    @Estherolori 7 месяцев назад +1

    I always understand you thank you

  • @AbrahamM.MusahJr
    @AbrahamM.MusahJr Год назад +1

    Thanks a lot🎉

  • @alphasaffi9230
    @alphasaffi9230 Год назад

    Thank you sir God bless you sir

  • @ZERO-ud1oi
    @ZERO-ud1oi 2 года назад +2

    I LOVE YOU MAN

    • @OninabResources
      @OninabResources  2 года назад

      Thank you so much for your feedback.
      We really appreciate your comment.
      Warmest regards.💕💕💕

  • @MarionOjotola-lo7gf
    @MarionOjotola-lo7gf Год назад +1

    Thank you so much, I now understand this topic better ❤️❤️.
    Please I have a question, how many values of x can we find for a particular question?
    Thanks.

    • @OninabResources
      @OninabResources  Год назад

      You are welcome. The values of x depends on the nature of the problems.

  • @perpetualuwanuakwa1790
    @perpetualuwanuakwa1790 2 года назад +3

    How would you solve/ simplify the question
    (x+3) (x+5) mod 4

    • @OninabResources
      @OninabResources  2 года назад

      Could you please check and correct the question. (x + 3)(x + 5) is not an equation. Let us know what is it equal to.

    • @perpetualuwanuakwa1790
      @perpetualuwanuakwa1790 2 года назад

      @@OninabResources so it has to be an equation? Someone sent multiple questions like this without an equal sign so I thought it’s possible to do

    • @perpetualuwanuakwa1790
      @perpetualuwanuakwa1790 2 года назад

      @@OninabResources in cases like 2-3(mod 6) I was told the answer was 5 but it’s not an equation

    • @OninabResources
      @OninabResources  2 года назад

      Yes, the answer is 5. This is subtraction of numbers in modulo 6.
      2 - 3 = - 1. Since we can't have negative in modulo 6, we add 6 to it to give 5 as the result of 2 - 3 (mod 6)

    • @perpetualuwanuakwa1790
      @perpetualuwanuakwa1790 2 года назад

      @@OninabResources so why can’t is the question (x+3) (x+5) mod 4 not solvable

  • @edwinagbeze8232
    @edwinagbeze8232 2 года назад +2

    What if I solve a question and get
    Y= 5 (mod7) should I leave it like that?

  • @evagberienoghenekevwe2471
    @evagberienoghenekevwe2471 3 года назад +1

    Thanks u

  • @manteyericohene5754
    @manteyericohene5754 2 года назад +2

    Please sir the (a) I think the x=10 because if I multiply 4 by 5 the answer is 20
    20=8(mod 6) is wrong but 50=8(mod 6) I think is right

    • @OninabResources
      @OninabResources  2 года назад

      Kindly watch this video on simplification and equivalent of modular arithmetic for further clarification:
      ruclips.net/video/ss4YY7s6GSY/видео.html

  • @margaretibukun9909
    @margaretibukun9909 3 года назад +2

    Sir can we leave the (b) answer as7(mod2)

  • @namhlamahlezana
    @namhlamahlezana Год назад

    😭😭😭 ive been struggling for so long

  • @onyeariedeogu1350
    @onyeariedeogu1350 Год назад

    What if you have 9-5x=13 (mod 7)😮

    • @OninabResources
      @OninabResources  Год назад +1

      9 - 5x = 13 (mod 7)
      5x = 9 - 13 (mod 7)
      5x = - 4 (mod 7)
      5x = - 4 + 14 (mod 7) {since 14 is a multiple of 7}
      5x = 10 (mod 7)
      x = 2 ( mod 7)

  • @onyeariedeogu1350
    @onyeariedeogu1350 Год назад

    Be more specific sir.But it was really help full thanks

  • @SamuelKbiadoo
    @SamuelKbiadoo 9 месяцев назад +1

    You don't explain into details

    • @OninabResources
      @OninabResources  9 месяцев назад

      Thanks for your feedback. You can get from other channels for better explanation or email us at oninabresources@gmail.com for online tutoring.