integration of 0 to infinite log(x + 1/x) + logsinx | CBSE XII NCERT INTERNATIONAL STUDENTS

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  • Опубликовано: 25 янв 2025

Комментарии • 65

  • @nithyashreevenkataraman3
    @nithyashreevenkataraman3 6 лет назад +8

    I really can't thank you enough for this video! I love how you've explained it and I'm particularly grateful for that step (5:54) when you use log log mn = log m + log n because I was doing it the long way and I used to go wrong quite often. Great video! :)

    • @mehuliyer8079
      @mehuliyer8079 6 лет назад

      Gowri miss will be disappointed in you. But hey mouni sir didn't even finish this sum for us and here I am!

    • @nithyashreevenkataraman3
      @nithyashreevenkataraman3 4 года назад

      ​@@mehuliyer8079 ohmygosh hahaha I just noticed this response! Law school is great, no math xD

  • @jitenderasingh5455
    @jitenderasingh5455 5 лет назад +4

    sir u are amazing...and i thinks that this is the channel for maths on youtube✌✌✌✌✌

  • @sohambande2798
    @sohambande2798 5 лет назад +1

    Sir at 6:00 if we make it sin2x then also the problem is solved in fact if we do that way it is more easier as when u use logm +logn property and brought 2logsinx which is further going to integrate in the sin 2x way so that will be lengthy

  • @jsonetif606
    @jsonetif606 6 лет назад +1

    Sir i have problem in continuity chapter of class xII so plese suggest any vedio from ur channel to cope with any type of problems

  • @adarshpratapsingh077
    @adarshpratapsingh077 6 лет назад +2

    Sir ji ap time km lete ho or perfect smjaate ho or sbse achhi chees hme apki hand writing lgi or speed k bad bhi apki hand writing ...Lajwab

  • @igxninja9641
    @igxninja9641 6 лет назад +2

    Please tell me the link to buy The integration book of AVTE

    • @avte-edu
      @avte-edu  6 лет назад

      You may send us WhatsApp at 9871041788, regards

  • @sunnyupadhyay3388
    @sunnyupadhyay3388 6 лет назад +2

    Sir any tricks to accurately suppose the value of x ??

    • @avte-edu
      @avte-edu  6 лет назад

      Hidden substitution, tan inverse x has the derivative so put that

  • @mehaktakkar3280
    @mehaktakkar3280 4 года назад +1

    Thank you sir 👍🏻👍🏻

  • @jamwal4714
    @jamwal4714 6 лет назад +3

    Awesome vedio sir 🙂

  • @jsonetif606
    @jsonetif606 6 лет назад +2

    U r amazing sir .... i love ur techniques

  • @ADARSHSINGH-y9c
    @ADARSHSINGH-y9c 10 месяцев назад +1

    Sir mughe nda ki teyari Karni hai aap Kara denge

    • @avte-edu
      @avte-edu  7 месяцев назад

      Kindly call at 9871041788 Mr Vineet ji

  • @Sagar_5678
    @Sagar_5678 3 года назад +1

    Thankyou sir🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼

  • @twishakacker5863
    @twishakacker5863 4 года назад +1

    Done sir, thank you !!

  • @Pattnaik11
    @Pattnaik11 4 года назад

    Sir exams to khatam hogeye,paar aaap ke pyarri voice and aswm teaching style mujhee baar baar integration dheek ne ke le bula detii hai.Love the way you solve sir,hope you are safe nowadays.Love you the math wizard

  • @hitakshibedi6555
    @hitakshibedi6555 4 года назад +1

    Thankyou sir, this is very helpful!

  • @tarunkhede3556
    @tarunkhede3556 6 лет назад +2

    Thank you very much sir

  • @nagasravani1866
    @nagasravani1866 6 лет назад +1

    I can't understand how to get upper & lower limit plss explain

  • @manyaahuja9187
    @manyaahuja9187 4 года назад +1

    done sir.. thank you

  • @jayakumarmhk2486
    @jayakumarmhk2486 7 лет назад +1

    How did u canceled cos theta
    It is whole upon costheta

    • @DRMUKESHSETIA
      @DRMUKESHSETIA 7 лет назад

      Jayakumar MHK by changing respect we get cos theta in numerator and cos theta in denominator so the two get cut ; Regards

    • @jayakumarmhk2486
      @jayakumarmhk2486 7 лет назад

      DR.MUKESH SETIA no it is logsinthetacosthet/costheta

    • @DRMUKESHSETIA
      @DRMUKESHSETIA 7 лет назад +1

      Jayakumar MHK warchbit carefully, it is logsinetheta multiplied with costheta ; Tc

    • @jayakumarmhk2486
      @jayakumarmhk2486 6 лет назад

      DR.MUKESH SETIA thx

  • @sonukumar-1997
    @sonukumar-1997 4 года назад +2

    thanks a lot

  • @bhaavyagupta5065
    @bhaavyagupta5065 6 лет назад +4

    Thank you 😁 this was wonderful!

  • @samarthsethji
    @samarthsethji 4 года назад

    Done Sir
    Thank You!
    Samarth Seth..

  • @nameerali3197
    @nameerali3197 Год назад +1

    Already done sir

  • @muhammadrazzaq8211
    @muhammadrazzaq8211 6 лет назад +3

    fantastic

  • @jahaannagpal
    @jahaannagpal 4 года назад +1

    Done sir 👍🏻

  • @aanchalmehta1145
    @aanchalmehta1145 4 года назад +1

    Done sir thankyou

  • @ADARSHSINGH-y9c
    @ADARSHSINGH-y9c 10 месяцев назад +1

    Thanks sir

    • @avte-edu
      @avte-edu  10 месяцев назад

      All the best

  • @mehakchopra7213
    @mehakchopra7213 4 года назад +1

    Done Sir

  • @Jaddiey
    @Jaddiey 5 лет назад +1

    Danken, Spaciba, Thank You....

  • @currentgk1359
    @currentgk1359 5 лет назад +1

    Limit 0 to 1 integration log(1+x)/x

  • @nalini1052
    @nalini1052 2 года назад +1

    Revised Sir

  • @adityakumarjain7007
    @adityakumarjain7007 4 года назад +1

    done sir

  • @safiaq_ueen
    @safiaq_ueen 6 месяцев назад +1

    The best

    • @avte-edu
      @avte-edu  6 месяцев назад

      Do all the questions from playlist , if want to study with us feel free to contact us at 9871041788 , regards

  • @ravirock6685
    @ravirock6685 5 лет назад +2

    sorry Maine pura vedio nahi dekha tha

  • @ankursingh2651
    @ankursingh2651 11 месяцев назад +1

    Samjh nhi Aaya

    • @avte-edu
      @avte-edu  11 месяцев назад

      Try slowly this is also good for jee and CUET

  • @sankalpkaushal316
    @sankalpkaushal316 5 лет назад +1

    Where is this fake accent from?

  • @inferno4738
    @inferno4738 3 года назад +1

    Done sir, thanks!

  • @ananyaarora7996
    @ananyaarora7996 4 года назад +1

    Done sir, thank you

  • @dakshagarwal5921
    @dakshagarwal5921 2 года назад +1

    Done sir thank you

  • @gamingandfunadda6759
    @gamingandfunadda6759 3 года назад +1

    Thank you sir

    • @avte-edu
      @avte-edu  3 года назад

      Kindly do all the playlists related to XII regards

  • @aryanbatra2989
    @aryanbatra2989 2 года назад +1

    Done sir, thank you !!

  • @krrishchoudhary2721
    @krrishchoudhary2721 3 года назад +1

    Thank you sir

  • @stutigrover5410
    @stutigrover5410 4 года назад

    Done sir, thank you

  • @anjalijindal8078
    @anjalijindal8078 4 года назад +1

    Done sir

  • @kashishjadwani1188
    @kashishjadwani1188 4 года назад +1

    Done sir

  • @astitvagoel8207
    @astitvagoel8207 3 года назад +1

    Done sir

  • @astitvagoel8207
    @astitvagoel8207 3 года назад +1

    Done sir

  • @shradulkhurana7683
    @shradulkhurana7683 3 года назад +1

    Done sir

  • @suhanisoni3741
    @suhanisoni3741 2 года назад +1

    Done sir