English -Truss Analysis Using Method of Sections
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- Опубликовано: 15 сен 2024
- [NOTE: Force HC = -48 kN and is in COMPRESSION]
An video tutorial introducing the method of sections in analyzing a truss along with an example.
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#civil_engineering
#structuralengineering
#structural_engineering
#هندسة_مدنية
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The tutor has the required patience to pass the message properly. I love this video. God bless you sir.
By spending half an hour here, pausing here and there to soak it in, I finally understand a concept that I have failed to comprehend for the past few months. thank you!
sir, if you're reading this, I just want you to know that i am with my utmost gratitude for you have taught me well. Im currently taking 2nd year of civil engineering and was struggling with my topic until ive watched couple of your videos. This really helped me alot and hope this would help others as well. thank you sir
This has got to be one of the most clear demonstrations i've ever seen in this subject. Incredible work, thank you very much!
One 20 minute video helped me understand Method of Sections better than my 3 hour class. Thank you so much. I wont be failing my final :)
Just wanna say, you made my day bro.. I felt great for the way you calculated HC
:D
shahed uzzaman Good to know that you liked it :)
You are so thorough! You've answered all my questions I've had on trusses/ methods by sections, thank you!
you are very welcome.
thank you for stopping by
thanks for stopping by
and I will see into that Fink truss in the future
you're my favorite tutor
Thanks for your kind words
Ahhh, because we are only considering external forces. This makes perfect sense. Thank you much.
it is the most perfect video of method of sections which i was looking for thank you sir
Thank YOu so much..you'll really help me alot for my exam ..i've understand your explanation more than my teacher..;)
AMAZING. NET, SIMPLICITY AND DIRECT FORWARD
Thanks
i never thought it would be so easy to solve these problems!! your clip was really helpful! thanks a lot sir!! :)
Sachin Kakade Great to know that was useful. Thank you for stopping by
You are welcome and thanks for your kind words
Hi, I just made an account to say many thanks to you....
vary helpful video,
greetings from Iran
Expertly done! I wish I watched these videos when I was in school.
Hi Engineer :)
you are very welcome and thanks for your kind words
Thank you very much. Very clear explanation and easy to understand. Again,Thank you soooo muchhh!!!
you are right IF we have a horizontal force acting on the truss. Since we don't, there will be no horizontal reaction AX.
Try to do summation of forces in the x direction and see what you get :)
Thanks
CTS Admin
Thank you so much, now I understand about it because of your explain is very well.
you are welcome
Thank you! I was so confused our textbook is errornous and only uses the Moment law, your a life saver!!!
Thanks a lot , your explanation is very clear and makes the problems vivid.
nicely explained and very helpful for students and teachers.
jagdish moudgil great to know that
Wow!!!! Gr8 video and very easily understood...thanks a lot....
Nasratullah Amarkhail you are welcome
For the last part, an easier method is to find the angle of the triangle which is tan^-1(4/5) = 38.7 degrees, then go sum of Fx=0 , and solve for HC by using it's X component of cos(38.7) .. you're equation will be../ sum of fx = -75 + 112.5 + cos(38.7)xHC = 0 , and when you solve for HC, you get -48kN, which is 48kN in compression
You are awesome!! Thank you for this explanation. Very much appreciated
you are so welcome
:) too late I already trusted you I'm terribly disillusioned.....Great instructional! It was very helpful thankyou
A n d r e a s You are so welcome
The error he was talking about is that HC is actually in compression not tension fyi, the answer comes out negative 48kN
You are right
Awesome video once again, except at the end both values of HC are -48kN, so it would be compression instead of tension.
Thankyou for this video man!!! :) So many questions have been answered and I found this video exceptionally helpful. Thankyou very much :)
Armaan McLeod You are so welcome
Great Explanation! Thank you soooo much! I will be going to your other videos to freshen my statics up!
Thank you so much, this video was very helpful. You should really have more views you explain in a manner that is very easy to understand. Assalamuakum and hope to see some more videos later.
You are welcome. Thanks for your kind words :)
wish you were my teacher! 100000 thank you! u saved my year! :)
thank you so much, this has made it super easy to understand ..
الله يوفقك ويسعدك :")
+The Daisy Thank you جزاك الله خير
Thanks for stopping by :)
thanks soo much.. ill be relying on u for my next 4 years!! haha
Good job, I admire your approach.
Very good explanation. Thanks for the video :)
The Moment to find BC is taken about Joint ( H ) which makes the rotation clockwise therefore negative. as for the moment to find HG, the rotation is about point ( C ) which makes this rotation counter clockwise, therefore positive.
remember, we are rotating about two different points here. although the direction of the forces is the same, tho points we are rotating about are different.
Hope that answered your question.
CTSCIVIL
to be honest, I never thought of it this way.
I think if I do it the way you are suggesting, I am feeling that I am switching my assumption somewhere in the solution.
I always assume positive moment counterclockwise and tension as positive as well.
do it the way you proposed but for some reason I am feeling that clockwise and tension go together and clockwise and compression go together.
sorry for not having a clear answer for now. i need to give it some more thoughts I guess.
great video, and very clear audio... nice explanation as well.. i love to see a fink truss example
good to know that. any ideas for future videos?
Having an exam tomorrow! :) Thanks for this! :)
Very very very obvious tutorial .. thank u very much
Thanks for your kind words
Thanks for stopping by
your video is very helpful. nice and clear explanation. thanks:)
Salam please other topics if possible could be done in English cos I really understand how you explain very well. Thank you
Very very clear explanation..
check the playlist
English - Topics in Engineering Statics
you should have a video (of two parts) on the method of joints :)
thanks for stopping by
Thank you! u teach a lot better than my prof, thanks for clearing things up for me! :D
Ppeeerfeect *_____*
ma Shaa'a Allah
Thaaank Yoooou 😄😄😄 👍🏻
+Farạh Mohammad You are so welcome
جزاك الله خير
Hi, for member HC shouldn't HC= -48kN (Compression). Thanks for uploading this video.
very good at explaining, appreciate the help
tjsh11 thank you for stopping by
Thank you for your kind words John.
I always have problems with people claiming that they are they best or among the best. Teaching is a skill that can be developed. Do not claim to be the best. Let your student decide. Do your part of crossing the idea to others and be thankful if 1 out of 10 people appreciates it.
CTSCIVIL
very well and thoroughly explained
Good to know that
thanks for stopping by
Thanks for watching.
Keep on learning though
CTSCIVIL
good to know
thanks for stopping by
Excellent video. Thank you so much!
you are so welcome
THANKS BOSS....I AM REFRESH BEFORE I AM CONFUSE HOW TO INVESTIGATE THE TRUSSES IF THE MEMBERS IS COMPRESSION OR TENSION....
This video is very helpful for truss
For calculating HC we can use (sin/cos) of the angle after we calculate it by (tang) witch equal to 4/5
yes you can. But the question is, how many numbers after the decimal place will you use?
it is always nice to use ALL of them right? However, that is impossible. That is why I use the triangular ratios
Tx for the video sir n u r talking in Russian accent that I really liked
Since there are no horizontal forces acting on the truss, the pin connection at A will not provide any reaction in the horizontal direction
try to solve the equation "Sigma Fx =0" and let me know
Thanks for a nice question :)
thank you so much . best video ever!!
you are so welcome
It is good t know that helped.
thanks for stopping by
Very good explanation, thank you!
you are so welcome
Very informative. I'd like to clarify why Ay=Ey=60Kn. Why 30Kn is not part of the equation? Please Explain it more. Thank you very much. :)
very detailed, well explained, so helpful, thanks!
+z progress You are so welcome
did you assume the positive as tension and the negative as compression along with a counterclockwise moment as positive?
if you did, you should not have a different answer as mine.
You are the best...thank you very much
At 5:42 you mention the reaction forces Ay and Ey. Since A is held by a pin, would there be a reaction force in the x direction, Ax? Thank you, great video.
masshallaa.. the best
YOU ARE RIGHT
Thank you for pointing that out. I should have been more careful about that.
I made a correction in the video
CTSCIVIL
Wa Alikom Alsalam
Thank you for the kind words. It is not about the number of views, it is about the number of people who get it, understand it, and implement it.
CTSCIVIL
you are very welcome
Isaac
All I need from you to tell me that you nailed that test and we will call it even
wishing you the best
regards
CTSCIVIL Admin
Many thanks for clarifying a few things. *Subscribed* :)
Nice and clear,
Brilliant job! Thank you!
Robert White Thanks for your kind words
Nice of you saying that
stop by more often :)
CTSCIVIL
You are always welcome
keep it up
good video really well done thank you
My pleasure
Thanks for your kind words
CTSCIVIL
many thanks < i hope the best life for you
Thank you! Got perfect on my exam!
Congrats :)
So happy for you
Amazing explanation. thanks sir
Thank you so much !!! you are so helpful!!!
You are welcome
This is Awesome!
thank you soo much its clear now your great thx again
thanks a lot, very helpful! got my exam in 2 hours hahaha
you are welcome
Thanks for a great explanation! :)
you are so welcome
hello
thanks a lot for your videos they truly help a lot.
one question though, at the end when i checked my answer like you did, i got the same value (in compression instead of tension ). any idea where I might went wrong?
thanks again