It's a humble praise for you sir for providing v good material and I also include that the last complete sheet provided for all elements was really best it helps us the more thank you 🙏 god bless you sir 😊
This is because 3d and 4s are in close energy . Any subshell having half filled or completely filled electronic configuration has extra stability . Thus in order to gain extra stability ,the last e instead of occupying 4s orbital occupies 3d orbital.and results in 3d5 4s1 and not 3d4 4s2
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Very helpful video sir ji.
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BEST 😍😍😍lecture
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Spin magnetic moment of Ti2+ is 2.84
2.83😍
It's coming 1.73 B. M
@@Alapanwesha ya it's 1.732 bm
@@Alapanwesha ✓3 = 1.732bm
@@hemantgodakhindi9933 nope Ti at no 22 for Ti²+ it is 20 so no of unpaired e- is 2
So, it is 2.84
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Thank us o much forproviding ur beneficial knoweldge heartly thank u 😊
Thankyou sir for making our concepts clear
Very nice video sir my topic is clear thanks
best explanation out there. thank you sir.
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best explanation
thank you, sir. 🙏
Thank u sir for easy explanation...👍❤️
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Sir very nice explanation
Amazing explanation 👏👌
2.8 approximately.
Ans for Ti ^2 +.
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helpfull to neet aspirant
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Thank you sir very much 👍❤
Thank you sir understood well
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Sir I am completely understand thanks sir 🙏
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It's a humble praise for you sir for providing v good material and I also include that the last complete sheet provided for all elements was really best it helps us the more thank you 🙏 god bless you sir 😊
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sir how to find no of ppi dpi bonds PLZ GIVE TRICKS AND VEDIO ON COORDINATION COMPOUNDS.
Thankyou sir I am confused but now I am understanding thank you sir❤❤❤
Great explanation Sir...
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Helpful.Thank u
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Jai Ho 😂😂
Sir please tell me why we written when cr(24) = 3d5 4S1 except 3d⁴ 4s² why we not take 3d⁴ 4s2
This is because 3d and 4s are in close energy .
Any subshell having half filled or completely filled electronic configuration has extra stability .
Thus in order to gain extra stability ,the last e instead of occupying 4s orbital occupies 3d orbital.and results in 3d5 4s1 and not 3d4 4s2
Sir sone ki angoothi💍💍 kitne rupay ki hai.. acchhhii lag rahi hai😁😁❤️❤️❤️
Thank you sir👍
Tq easily understood sir
Thanks sir to Show 1 to 5 value mu👌
Sir thanks a lot 🙂......
So the answer is 2.84 where n =2 sir
Thanks sir my concept on mgntc mmnt is now has been cleared
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Really ,I love chemi...
Thank sir ,
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Thank you sir it helped a lot
Tq so much
Formula to find n is [n=atomic number of tht element-oxidation state-atomic number of Argon]
Sir is this correct, I can use the above method also?
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So simple sir
Thank u sir ☺️
Nice video
Nice
Thanks 👍🏻🙏
Helpful
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Why so long ads dudde
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Tq
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Tnx sir 🙏🤞
How learn pd pt titanium atomic numbers?
Sir ya arrow matlab spin galat hai half aygi
Sc3+ ka ky hoga magnetic moment
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Thank u
Thanks
Sir tell me how root 24 is 4.9
Answer is 2.84.
2.84
its work with 4f electrons?
Yes
No of unpaired electron is 2 therefore BM root of 8 i .e 2.84BM
Ans - 2.84
👌👌
Who to drive magnetic movement of uranium
2.84 Bm??
Sir can u pls how to came tat 5.92
Thank you sir for clearing my doubts.
Yen ky hua sir
Ti 2+ answer 2.82
Cu ka kya hoga..
n= 2
Magnetic movement= 2.84BM
2.84 as unpaired Electrons are 2 💯