"without a good presentation, everything becomes meaningless" - realised after watching the video, but thanks to the speaker for his endless efforts. Hopefully his contribution will help a number of begineers :)
Quick sound fix : Download the videos and play it with VLC .Right click on the video while playing and change the audio setting from default stereo to Right .
Calculation of the probability of bob succeding is done incorrectly as it should be done using the posterior probability of seeing the value of f(x) and not x. If the event of 0 and 1 were not equally likely then the probability would have come out incorrect.
I dont understand the second case of "Alices cheating probability" - X is odd. if x[0] = 1 then f(x)| at bit 0 will always be = 1. but now if alice tries to change parity of X to even, then x[0] = 0 and f(x)| at bit 0 will depend again on x[100]. How can this mean that alice can still cheat with probability = 1. please explain ...
this is totally a different thing I have learnt in other classes. I am now confused which one to follow. I can understand both. both are good. so I m confused
After downloading these whole series on cryptography, I only had motion(video) without sound(audio). Even when playing it on youtube, am I the only one experiencing this?
The presentation has to be better. I know it is a free lecture and you cannot expect more. I am commenting only because it is coming from a IIT prof. i felt this simple introduction was made difficult to understand, particularly for novices. The Prof should prepare more thoroughly, and should not go back and forth with his own words Or correct his statement.The students Or Learners should use these videos as a basis on which they can make further research and make things clearer for themselves.
Sir you teaches very nicely but you should change your teaching methodologies and presentation skills,you should make something like Howard Universality (cs50.).
malhar jajoo when the value of x is odd then then x[0]=1 so output of f(x)|0 = 1 always so the probability of alice cheating given the value of x is odd is 1*1/2=1/2 where 1/2 comes for x[100] since value of x[0] cannot change (it is always 1). But the second case that u refer to is entirely a different case which produces 2 values of f(x)|0 at x[0] being 0 1) x[0]ORx[100]=depends on x[100] now since value of x[100] cannot be 1 because if it was 1 then it will contradict the value of earlier proclaimed value of x as odd .Which would make our hypothesis wrong . 2) value of f(x)|0 = 1 it can be due to x[100] thus producing value of 1/2 making final prob to be 1/2*1/2 =1/4 . ur skepticism was wrong its 1/4 not 1
please needing a good respond , will i going to learn everything about network security in this lesson right? please your respond will be good helpful thanks
"without a good presentation, everything becomes meaningless" - realised after watching the video, but thanks to the speaker for his endless efforts. Hopefully his contribution will help a number of begineers :)
Quick sound fix : Download the videos and play it with VLC .Right click on the video while playing and change the audio setting from default stereo to Right .
thanks
My right ear feels more educated
thanks .. my university should not be allowed to teach this subject ..
My left ear enjoyed this video...
for me its the right one
Calculation of the probability of bob succeding is done incorrectly as it should be done using the posterior probability of seeing the value of f(x) and not x. If the event of 0 and 1 were not equally likely then the probability would have come out incorrect.
I dont understand the second case of "Alices cheating probability" - X is odd.
if x[0] = 1 then f(x)| at bit 0 will always be = 1.
but now if alice tries to change parity of X to even, then x[0] = 0 and f(x)| at bit 0 will depend again on x[100]. How can this mean that alice can still cheat with probability = 1. please explain ...
I really enjoyed the video, it was very clear and well explained! I will obviously watch the next one
Thank you for your sharing ! Good explanation by Prof.
this is totally a different thing I have learnt in other classes. I am now confused which one to follow. I can understand both. both are good. so I m confused
Good Explanation by Prof !
It was great video tutorial.
After downloading these whole series on cryptography, I only had motion(video) without sound(audio). Even when playing it on youtube, am I the only one experiencing this?
+Richard Kits , I watch videos with my headphones and left side does not give any sound
+Eren Okur The video is only having audio for right ear plug.
You may download it from nptel.ac.in/courses/nptel_download.php?subjectid=106105031 Try the flv links.
The presentation has to be better. I know it is a free lecture and you cannot expect more. I am commenting only because it is coming from a IIT prof. i felt this simple introduction was made difficult to understand, particularly for novices. The Prof should prepare more thoroughly, and should not go back and forth with his own words Or correct his statement.The students Or Learners should use these videos as a basis on which they can make further research and make things clearer for themselves.
you are right
why we are or with x[100] to x[0] ....
IPSec, SSH are missing in course.
I Rajni can't believe that even IIT professors have problem with their English!
My right ear says thank you
Engaging lecture.
Sir you teaches very nicely but you should change your teaching methodologies and presentation skills,you should make something like Howard Universality (cs50.).
malhar jajoo when the value of x is odd then then x[0]=1 so output of f(x)|0 = 1 always so the probability of alice cheating given the value of x is odd is 1*1/2=1/2 where 1/2 comes for x[100] since value of x[0] cannot change (it is always 1).
But the second case that u refer to is entirely a different case which produces 2 values of f(x)|0 at x[0] being 0
1) x[0]ORx[100]=depends on x[100] now since value of x[100] cannot be 1 because if it was 1 then it will contradict the value of earlier proclaimed value of x as odd .Which would make our hypothesis wrong .
2) value of f(x)|0 = 1 it can be due to x[100] thus producing value of 1/2 making final prob to be 1/2*1/2 =1/4 .
ur skepticism was wrong its 1/4 not 1
yeah exactly
please
needing a good respond , will i going to learn everything about network security in this lesson right?
please your respond will be good helpful thanks
good work
Why can't Alice and Bob just go to a multi cuisine restaurant? Problem solved..
no sound in the videos
i cannot understand your english. you have something on your mind and something else on your tongue.
nice,but too slow
boring ,dull.