In the plane of complex numbers, we have 6 solutions located on a circle of radius 5. They are evenly distributed, i.e. every 60 degrees The solutions k=5 and k=-5 are trivial and can be easily guessed. The general solution is therefore: k=5*{cos(n*60[deg])+i*sin(n*60[deg])} for n=0, 1, 2, 3, 4 k0=5+i*0 k1=5*sqrt(3)/2+i*5/2 k2=-5*sqrt(3)/2+i*5/2 k3=-5+i*0 k4=-5*sqrt(3)/2-i*5/2 k5=5*sqrt(3)/2-i*5/2
too complex solution (pun intended), just divide circle in 6 equal parts and thats it
In the plane of complex numbers, we have 6 solutions located on a circle of radius 5. They are evenly distributed, i.e. every 60 degrees
The solutions k=5 and k=-5 are trivial and can be easily guessed.
The general solution is therefore: k=5*{cos(n*60[deg])+i*sin(n*60[deg])} for n=0, 1, 2, 3, 4
k0=5+i*0
k1=5*sqrt(3)/2+i*5/2
k2=-5*sqrt(3)/2+i*5/2
k3=-5+i*0
k4=-5*sqrt(3)/2-i*5/2
k5=5*sqrt(3)/2-i*5/2
Bruh 😂😂
K=5 easy
if the exponents are equal the base is equal
well it can still be -5
and complex numbers, ur not him