The IP addresses which you have mentioned will be the first usable and the last usable IP addresses. But the range of Ip addresses is from 192.168.17.0 - 192.168.17.255 where 192.168.17.0 is the network address and 192.168.17.255 is the broadcast address.
192.168.17.1 is the first host address, 192.168.17.254 is the last host address , host range network range consists of 192.168.17.0 and 192.168.17.255 which is the broadcast address. I hope you got the difference
I think first ip should be 192.168.17.1
And last ip should be 192.168.17.254
As you have said we have only 254 host in class C😊
The IP addresses which you have mentioned will be the first usable and the last usable IP addresses. But the range of Ip addresses is from 192.168.17.0 - 192.168.17.255 where 192.168.17.0 is the network address and 192.168.17.255 is the broadcast address.
No, you are wrong.
192.168.17.1 is the first host address, 192.168.17.254 is the last host address , host range
network range consists of 192.168.17.0 and 192.168.17.255 which is the broadcast address. I hope you got the difference
The total addresses will be N=2^32-n
Which equals N=2^32-24 = 256
I think the total address should be : 2^29
How can we simulate this?
Can I buy your course on your website from Pakistan? Is transaction possible through a bank?
We don't have Paypal here.
Lmao what a country 😂
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@@tejasanil1743 why you try to violate
@@tejasanil1743lmao pajiit think he is funny
@@hussnainkhurshid5068 yo mujeet ignore him
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Yooo