F.Sc Physics Practical - Charging and discharging of capacitor and to measure time constant

[@swaggerbois_56]

9:58, sir ye 0.37 kahan se agaya? samjh nhi ayi

[@kabeerfcc4153]

Capacitor ki charging equation SE. q=q0(1-exp^-t/RC)

[@SantoshKale-yx9ov]

😊😊❤

[@AlishaAli-mn1vj]

Great explanation. May Allah bless you ❤

[@FA23-BEE-035]

Thank you sir

[@DEVILSGAMES07]

sir g , Time condtant ki value experiment se find krte walt hm ne maximum current ko 0.37 se multiply kue kia hay

[@abdulnafay8106]

Thank you soo much sir

[@muhammadrazaansari3344]

sir in circuits ki diagram banani hai kia ??plzzzzzzzzzzzzzzzz tell me

[@TobeadoctorVerysoon]

Bht acha smajhtay hn ap...book ka nam bata sakty hain?

[@anonymouslyridiculous9091]

Ilmi ki practical book hai

[@kabeerfcc4153]

Behtar he aap video SE samjhein, practical notebooks ki samjh nahee AP ko lagay gee,

[@kabeerfcc4153]

Sorry wrong method for usage of stop watch, dont stop the stop watch,just note the time at regular intervals without stopping time.

[@ashwininair5503]

Sir can you attach the pdf for this please...

[@PhysicsDept.YouTube]

0.37 kaha se liye sir ?

[@kabeerfcc4153]

Capacitor ki Jo equation he discharging ki.os se

[@nawwafmuhammad5958]

Sir why do we have to multiply the maximum charging current with 0.37

[@ontopFactSnack]

By differentiating the equation of charging of capacitor i.e q=q•(1-e^-t/rc), current equation is formed i.e i=i•e^-t/rc... Which for one time constant, is equal to 0.37

[@nawwafmuhammad5958]

@@ontopFactSnack thank you brother

[@Mughalprincess-h4t]

Ya konsi class ka ha

[@salimahere0.0]

It literally says Fsc which means 12th