Solved Problem based on Centrifugal Pump (1) - M4.14 Fluid Mechanics in Tamil

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  • Опубликовано: 27 окт 2024

Комментарии • 9

  • @maheshkumars4241
    @maheshkumars4241 Год назад +5

    The formula of work done (W) is 1/g* vw2 * u2

  • @engsherif4657
    @engsherif4657 20 дней назад

    Good

  • @tamizhyoutube9338
    @tamizhyoutube9338 6 лет назад +2

    Sir
    I am your Regular student
    of your class
    in RUclips channel
    In the Above video...
    W.D formula is wrong sir
    the denom. should be "g"

  • @sanjaypranesh7221
    @sanjaypranesh7221 Год назад +2

    1/g sir not 1/2 for work down per unit length

  • @albinjohn6735
    @albinjohn6735 6 лет назад +1

    *Sir,I think you can't complete the whole syllabus within these few days so it is better to complete Part B topics of 4&5 units*

  • @arunachalamp2062
    @arunachalamp2062 6 лет назад

    நன்றி ஐயா

  • @VijayaKrishnaVK
    @VijayaKrishnaVK 6 лет назад

    Sir! Indha sum la work done formula thappu nenaikkuren work done = rho*discharge*(Vw2*U2) dhana sir please reply me fast tomorrow semester exam irukku

    • @abineshbabu8099
      @abineshbabu8099 5 лет назад +1

      Workdone formula thaapu thaan
      Workdone = (w/g)× Vw2 ×U2
      weight per kg so = (Vw2 × U2)/g
      avaru thappa divided by 2 nu potrukaru bro

    • @ahamedsameer7724
      @ahamedsameer7724 Год назад +1

      Hi bro