let's solve for x|Math Olympiad|Exponential maths problem

[@emmajeanpierre8052]

I enjoyed this video very much. Fun….

[@RyanLewis-Johnson-wq6xs]

2^(Log[2,1.6 recurring ]+2)+2^(Log[2,1.6 recurring ]+2)+2^(Log[2,1.6 recurring ]+2)=20 x=Log[2,1.6 recurring ]+2

[@dadejoka6653]

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[@JJONLINEMATHSCLASSchannel]

I'm so glad! Thank you

[@TariqHussain-u6c7j]

Remarkable effort ❤

[@maths01n]

I never saw it coming but finally you nail you nailed it, keep up my fellow Mathematician content creator ❤❤

[@JJONLINEMATHSCLASSchannel]

Thank you

[@BrijLalSahu-bb1lu]

Very nice

[@JJONLINEMATHSCLASSchannel]

Thanks

[@joachimschulz4792]

More easy => x = ln(20) / 3 * ln(2)

[@subratabiswas2502]

This problem does not mention that 2^x.2^x.2^x=20 ; It is mentioned that 2^x+2^x+2^x=20.

[@venkatesank3841]

Your question is about addition. But your solution is about multiplication

[@abrahammelkonian9698]

Red is my favorite

[@JJONLINEMATHSCLASSchannel]

Wow

[@RyanLewis-Johnson-wq6xs]

That means x=(2+Log[5,2])/3.

[@jmich7]

JJ, it is not 2^x times 2^x times 2^x It is 2^x + 2^x + 2^x Check it out please!

[@subratabiswas2502]

3.2^x=20 ; i,e 2^x=20/3 ; i,e x=[log(20/3)]/log2 ; i,e x=[log2^2.5)]/log2 ; i,e x= (2log2+log5)/log2 ; i,e x=2+(log5/log2).

[@nizamuddinahmed2193]

log10=1. Then put log2.

[@Amt-p2h]

Good Morning
I'm your 1st 1 like❤

[@JJONLINEMATHSCLASSchannel]

Thank you so much

[@kimba381]

That is NOT the problem posed.

[@Danielomisola]

Hey beautiful 😍 🤩 👌 ❣️ 😘 how old are you?

[@JJONLINEMATHSCLASSchannel]

Am an adult

[@maths01n]

Well answered dear​@@JJONLINEMATHSCLASSchannel

[@Danielomisola]

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[@maths01n]

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[@shaileshbhatia4460]

The question given is 2x+2x+2x=20 and not 2x.2x.2x=20

[@JJONLINEMATHSCLASSchannel]

Oh! Sorry about that