You explained this incredibly well. Coming from an engineering student studying from home during the pandemic, your videos are a lifesavers. Thank you very much!
You are correct - if you look at the coordinate system that I draw at 1:42 you will see that the y-axis has a zero value at the center line of the channel.
My only question is that the "y" in your formula represented the distance between the plate and where Umax is located? Thank you for showing this example.
Thank you. It's a really good explanation. But could I ask a question? what about the shear stress of the lower wall? if y= -0.25, then tau on fluid is positive,on the other hand, tau on wall is negative, so shear stress of the upper wall and lower wall are opposite directions. it's really confused.
The coordinate system is defined at the centerline of the channel. The y in the last equation is the y-location of the upper wall - so half the channel width.
I think it came from interpolating the values from the table A.1 I interpolated and got 0.001155 so I guess it's about right with different tables and slightly different numbers
You explained this incredibly well. Coming from an engineering student studying from home during the pandemic, your videos are a lifesavers. Thank you very much!
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Gracias, tus videos también ayudan a gente que habla otro idioma
Thank you! It's really helpful to watch someone go through the motions.
I came looking for how I can understand the sign of the answer and I got it plus an explanation for why that is. Great content :)
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You are correct - if you look at the coordinate system that I draw at 1:42 you will see that the y-axis has a zero value at the center line of the channel.
My only question is that the "y" in your formula represented the distance between the plate and where Umax is located? Thank you for showing this example.
This velocity profile doesn't make sense to me. The velocity is moving backwards at the wall (y= +/- h)?
Thank you. It's a really good explanation.
But could I ask a question? what about the shear stress of the lower wall? if y= -0.25, then tau on fluid is positive,on the other hand, tau on wall is negative, so shear stress of the upper wall and lower wall are opposite directions. it's really confused.
Did you get an answer for this? I have the same problem in understanding. Cheers
Thank you so much sir. Your concept is very clear. You are great.
How did u get value for y? Is it given in question?
Where did the value for y come from?
Perfect language. Thank You Sir!
Where the Y value is coming from?
won't Shear stress equal - of viscocity * velocity gradient
Thank you for this sir. Very helpful!
can you please tell me where does 0.25 came from? ... I mean the y in last equation
The coordinate system is defined at the centerline of the channel. The y in the last equation is the y-location of the upper wall - so half the channel width.
why the result changed from -3.12 N/m² to +3.12 N/m², please explain 🙏
Sir, when will fluid flow at any value of shear force or it should be greater than the viscosity of fluid?
y = 0.25 ×10^-3 where did that came from sir?
it is the distance from the umax, (center) to the top
how is 0.5mm equal 0.005 m, it would not be 0.0005?
h in the denominator is 0.5 X 10^-3 m which is 0.0005 m
For y=h τ=μ*(du/dy)* (π/2) = 0.0013*(0.30/(0.00025) *(π/2)= 2.449
For y=-h τ=-2.449
How value of mew is calculated?
I think it came from interpolating the values from the table A.1
I interpolated and got 0.001155 so I guess it's about right with different tables and slightly different numbers
ruclips.net/video/XPCgGT9BlrQ/видео.html 💐💐💐💐