Romanian Math olympiad

Hello everyone
In this video I solved a nice Romanian math problem. If you enjoyed the video, dońt forget to subscribe!❤️
solving a quadratic equation
• How can you solve quad...
#algebra #calculus #math #matholympiad #mathwithmarker

[@mathpro926]

nice solution
all students like your videos

[@MathwithMarker]

@@mathpro926 Thanks💛

[@Hexer1985]

When you simplify your fraction by x^2, you have to note and write down that x=0 is excluded to be a solution. You have to do the same for x=1 and x=-1 when you simplify the fraction further by x^2-1.

[@MathwithMarker]

@@Hexer1985 you can say that again💛

[@user-xi8zr7yr7p]

Very good ❤❤❤

[@gopalakrishnabhatkr]

X=2√2

[@cyruschang1904]

(x^8 - x^2)/(x^4 - x^2) = 9
(x^6 - 1)/(x^2 - 1) = 9
(x^2 - 1)(x^4 + x^2 + 1)/(x^2 - 1) = 9
(x^4 + x^2 + 1) = 9
x^4 + x^2 - 8 = 0
x^2 = (-1 +/- ✓33)/2
x = +/- ✓(((✓33) - 1)/2) or +/- i✓(((✓33) + 1)/2)

[@CC--qn4gf]

Why did I also get x = ± 1?

[@cosmosapien597]

Denominator would become 0 in that case, which isn't allowed.

[@MathwithMarker]

@@cosmosapien597 yoùre right

[@bobbyheffley4955]

Both numerator and denominator are 0 at x=-1, 0, and 1. The equation is indeterminate at these values.