absolute convergence of series CSIR NET DEC 18 question 61

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  • Опубликовано: 18 сен 2024
  • Solution series for CSIR NET DEC 2018
    question 61
    REAL ANALYSIS
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Комментарии • 16

  • @stutisrivastava3998
    @stutisrivastava3998 5 лет назад +4

    Great job sir. I am really impressed with your subject knowledge and way of teaching. Sir please provide topic wise full lectures.

  • @indumathikrishnappa379
    @indumathikrishnappa379 4 года назад +1

    Beautiful. And thank u very much for solving my doubt on grouping. thank u again and again sir.

  • @bikashdutta8935
    @bikashdutta8935 2 года назад

    Very good explanation of sir

  • @bikashdutta2585
    @bikashdutta2585 Год назад

    Excellent🙏🙏🙏

  • @ruchimishra8775
    @ruchimishra8775 2 года назад

    Thanks sir

  • @amitsaini821
    @amitsaini821 5 лет назад +1

    Nice explanation sir, always stuck in this question but not anymore 😊👍

  • @sheespalchauhan1787
    @sheespalchauhan1787 Год назад

    Thank you sir

  • @biswajitgorai627
    @biswajitgorai627 Год назад

    we use the inequality of u only for modulus not in general

  • @umeshstudypoint7495
    @umeshstudypoint7495 3 года назад

    Nice explaination sir

  • @anupmandal5396
    @anupmandal5396 4 года назад

    Great job sir

  • @akshayakumar8706
    @akshayakumar8706 5 лет назад

    Amazing explanation sir

  • @souravdas-pn5qj
    @souravdas-pn5qj 3 года назад

    Nice

  • @chinnikrishnar5549
    @chinnikrishnar5549 5 лет назад +1

    If an=n then it is not absolutely convergent, how to proceed with this an.
    You assumed that it converges absolutely

    • @Axiomatikos
      @Axiomatikos  5 лет назад +3

      My friend chinni krishna i am not assuming that the given an is absolutely convergent i am proving that the given an is absolutely convergent
      an =n that you are taking will not satisfy the second criteria
      |an+1|

  • @umedsingh2425
    @umedsingh2425 3 года назад

    What if this diverges to - ♾️