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Excellent explanation sir.Ln (1+x) ka expansion h na sir yeand (1/2)= Ln (sqrt (e)) So Ln (2) greater than 0.5 because 2 is greater than sqrt(e).Am I correct ?
Sir log 2 ka value o. 3010 but you put the value of ln2
Which is actually correct
Sir/MamWhat will be cutoff for JRF Under category
105-115
Obc?
111
Log2 = . 30..
Visit our websitesites.google.com/view/nextgenmaths/math-for-everyone
Why you take. 69
ln(2)=0.69
Answer per effect pd rha h
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Excellent explanation sir.
Ln (1+x) ka expansion h na sir ye
and (1/2)= Ln (sqrt (e))
So Ln (2) greater than 0.5 because 2 is greater than sqrt(e).
Am I correct ?
Sir log 2 ka value o. 3010 but you put the value of ln2
Which is actually correct
Sir/Mam
What will be cutoff for JRF Under category
105-115
Obc?
111
Log2 = . 30..
Visit our website
sites.google.com/view/nextgenmaths/math-for-everyone
Why you take. 69
ln(2)=0.69
Answer per effect pd rha h