At 44:31 how to plug the nontrivial zeros rho into the last term of the equation?? How does it work to get a result there? How to plug in the nontrivial zeros? Like 1/2+it ? Then how to do them sum of it?? Please can someone give me one example?
I personally believe that Ramanujan played a significant role in demonstrating that we can go beyond the simple sum of 1+2+3... and arrive at the Riemann Hypothesis. In other words, without him, the Riemann Hypothesis might not have received the well-deserved attention it now commands, or maybe never materialized if he hadn't broken the taboo of divergence and the bi-alias rule that must converge to be meaningful.
@@nahidhkurdi6740 Okay, there are some points in your aggregation. I feel like you read the first half of my comments and believe that I meant Riemann used Ramanujan's work to develop his hypotheses. That wasn't my intention. You seem to be under the impression that because Hilbert listed it in his list, it gives glory to RH. I was trying to address this misconception. You need to ask yourself if that was true, why the other problems are not as famous. My explanation was because Ramanujan's work and his elegant, simple method of solving mind-boggling concepts like 1+2+3...=-1/12 intrigued others to learn and arrive to RH. On a side note, it's very disrespectful that you compare Ramanujan at 13 years old because of his age and believe he didn't accomplish anything at that age. Srinivasa Ramanujan, a self-taught Indian mathematician, made significant contributions to mathematical analysis, number theory, infinite series, and continued fractions. However, you are correct; there is no indication that Ramanujan proposed or worked on the Riemann Hypothesis, and I didn't say that. Hilbert's famous list of problems was presented in 1900, well after Ramanujan's early work. Remember, Ramanujan died at age 32. Srinivasa Ramanujan's early mathematical talent began to surface when he was a teenager. Around the age of 13, Ramanujan started to independently explore mathematical concepts and formulate his own theorems. His early work was primarily focused on number theory, infinite series, and mathematical analysis. Here are a few notable accomplishments from his early years. But that wasn't my point. His simple and elegant method was the source for many today to get excited about the Riemann Hypothesis. The glory and publicity of RH are not because of Hilbert's list but because of his simple method 1+2+3..=-1/12. This is my belief, and I will stand by it. You are entitled to have your own beliefs, and there is nothing wrong with that. We all admire someone people, and that is perfectly fine.
Hi sir In reiman hypothesis used S=x + yi Zeta(0)= sum of [1/n^s] Unknown terms are two x and y. Atleast y should be known to find out x as 1/2. Complex continuation required to which here not explained. I want to know.crtical line formula x=1/2 is it correct. Or any other complex line formula present for it.
Putting holographic superposition into correct terminology is the same mechanism for everyone who sees the circumstances, but has a differing array of line-of-sight abstractions, compositions of e-Pi-i transverse=> tangential trancendental density-intensity information, and only logarithmic condensation coherence-cohesion objectives => solid-liquid objects of Quantum-fields rotation, to share terms of identification. WYSIWYG but what you think you understand is probably not logarithmic condensation modulation cause-effect phenomena with pure-math relative-timing ratio-rates in holistic temporal Perspective. So collating-collapsing functional e-Pi-i Fluxion-Integral Temporal abstractions in 0-1-2-ness picture plane condensation Superspin modules is a Polar-Cartesian self-defining infinitesimal coordination-identification positioning system with a complication that even numberness => symmetry-> resonance harmonic with a floating zero-infinity floating point coordinate in the plane, and occasional orthogonal-normal logarithmic interference positioning in coplaner axes placing prime sight-line axes in the 1/2 symmetrical Singularity alignment. (All pictorial concepts of Geometric Orthographic Projection Drawing and Perspective combining Fluxion-Integral Temporal Calculus Condensation Actuality) As simple as amateurish visualisation can be reduced without having to resort to trying to explain the pseudo random cycles of Fractal scaling conglomerations of Primes and Cofactors, this lecture has partially illuminated. Mathematical Disproof Methodology has to have a sequence or algorithm of potential possibilities to test by assembly in a program list or Tabulation, but Projection Drawing Conception is a simultaneous holographic Modulation Mechanism interference positioning resonance Imaging. The eye of the Beholder has to make their own unique intuitive Observation and relate it to conventional terminology. This means the Clay Prize is earned by the people who interpret the Imagery. (?)
Hello I'm from Brazil the formula of non-primes automatically you discover the primes are 3+3+3+3... to infinity and the 7+7+7... and the perfect squares odd minus ending 5 example 9×9.11 ×11.13.13...
Hello Almost that's right this is a vortex circle a vortex number are those that go from 1 to 9 with the (0) in the center there in the vortex the numbers go back and forth with their opposites vs example 7+7+7+7 opposite 3-3-3-3-3 also 8+8+8+8 opposite 2 -2-2-2 also 9+9+9+9 opposite 1-1-1-1 e 6+6+6+6 opposite 4-4-4-4 o number (5) fold in itself 5.10.15.20.25....... hope you understood a little thank you
Also Goldbach's conjecture is easy all odds are a pair with 1 more number and the primes are odd divided by 1 so added two primes add two (1)(1) Does not matter the size. it also has the wildcard numbers 2 that goes through all the pairs and the number 5 that doubles in itself 5.10.15.20....
Lokema dmagena misak proof tiyan oke hari qardk gan sanjwakwath htiam en na😂bun.... Mulu numenrs wla katwam. Chitryak wage pena one😅 Reimann hyooth8se dka pwrof krla eka me butiak lokewayh aduam thrnewa😂wen loeka koamwetha..... Mnihwma smapurma 1k order ekta enwa ema twa eka dk8an ba 😂logic walta klewa reimann 😂reiman hyoothseis ke locily proof dena ba mada edan 😅ehen dadi mehen lissnwa🤣mehen wedi ehen lisnwa laga tiem kwadwath oeme na kwi lasna😅mukuth ndada na😂... Krpam baln pripuakkami threnwa u hari anith maths waradi.
I might be wrong, but this could work: ruclips.net/video/PvUrbpsXZLU/видео.html P.S. A piece of advice: make video 1.5 times faster, I speak very slowly)
The answer to the Riemann Hypothesis is Infinity. Infinity times infinity equals infinity to the power of infinity. Infinity squared equals infinity to the power of infinity. If 2 is a prime then so is infinity. You are all welcome.
Lucid, well structured, perfectly articulated
At 44:31 how to plug the nontrivial zeros rho into the last term of the equation?? How does it work to get a result there? How to plug in the nontrivial zeros? Like 1/2+it ? Then how to do them sum of it??
Please can someone give me one example?
Thank you for the clarification, and apologies for my misunderstanding. I'll delete my original post.
This is very informative thank you for this !!!
Will this help in finding if closed formulas exist for zeta at odd positive integral s values?
Nice and informative lecture!
Beautiful lecture!
Great Lecture! 😊
I personally believe that Ramanujan played a significant role in demonstrating that we can go beyond the simple sum of 1+2+3... and arrive at the Riemann Hypothesis. In other words, without him, the Riemann Hypothesis might not have received the well-deserved attention it now commands, or maybe never materialized if he hadn't broken the taboo of divergence and the bi-alias rule that must converge to be meaningful.
Re-evaluate this belief of yours. The Reimann hypothesis was on Hilbert's famous list of problems when Ramanujan was only 13 years old.
@@nahidhkurdi6740
Okay, there are some points in your aggregation. I feel like you read the first half of my comments and believe that I meant Riemann used Ramanujan's work to develop his hypotheses. That wasn't my intention. You seem to be under the impression that because Hilbert listed it in his list, it gives glory to RH. I was trying to address this misconception. You need to ask yourself if that was true, why the other problems are not as famous. My explanation was because Ramanujan's work and his elegant, simple method of solving mind-boggling concepts like 1+2+3...=-1/12 intrigued others to learn and arrive to RH.
On a side note, it's very disrespectful that you compare Ramanujan at 13 years old because of his age and believe he didn't accomplish anything at that age. Srinivasa Ramanujan, a self-taught Indian mathematician, made significant contributions to mathematical analysis, number theory, infinite series, and continued fractions. However, you are correct; there is no indication that Ramanujan proposed or worked on the Riemann Hypothesis, and I didn't say that. Hilbert's famous list of problems was presented in 1900, well after Ramanujan's early work. Remember, Ramanujan died at age 32.
Srinivasa Ramanujan's early mathematical talent began to surface when he was a teenager. Around the age of 13, Ramanujan started to independently explore mathematical concepts and formulate his own theorems. His early work was primarily focused on number theory, infinite series, and mathematical analysis. Here are a few notable accomplishments from his early years. But that wasn't my point. His simple and elegant method was the source for many today to get excited about the Riemann Hypothesis. The glory and publicity of RH are not because of Hilbert's list but because of his simple method 1+2+3..=-1/12.
This is my belief, and I will stand by it. You are entitled to have your own beliefs, and there is nothing wrong with that. We all admire someone people, and that is perfectly fine.
Thankyou. 2719 is a problem for 7 squared.
Hi sir
In reiman hypothesis used S=x + yi
Zeta(0)= sum of [1/n^s]
Unknown terms are two x and y. Atleast y should be known to find out x as 1/2. Complex continuation required to which here not explained. I want to know.crtical line formula x=1/2 is it correct. Or any other complex line formula present for it.
Loke onam problem ela soutin eka apiam komda hariytma harida dnagame😅
Krlana plwan or bari onam prnyak eg wedita imtegraion eka harimda
Ekam kai loek tiem
Compelx version eka arn
Complex numners wekum orme digasam ai bayda na ne😑
Byaunoth bacomplex versiin eka ganin lesiyem naman plwan ekath complex version ekn ekam ewanu mtham eka presise resut 1k wene🤣
Scrata poerful self coortion ekak denwa🙂
Putting holographic superposition into correct terminology is the same mechanism for everyone who sees the circumstances, but has a differing array of line-of-sight abstractions, compositions of e-Pi-i transverse=> tangential trancendental density-intensity information, and only logarithmic condensation coherence-cohesion objectives => solid-liquid objects of Quantum-fields rotation, to share terms of identification. WYSIWYG but what you think you understand is probably not logarithmic condensation modulation cause-effect phenomena with pure-math relative-timing ratio-rates in holistic temporal Perspective.
So collating-collapsing functional e-Pi-i Fluxion-Integral Temporal abstractions in 0-1-2-ness picture plane condensation Superspin modules is a Polar-Cartesian self-defining infinitesimal coordination-identification positioning system with a complication that even numberness => symmetry-> resonance harmonic with a floating zero-infinity floating point coordinate in the plane, and occasional orthogonal-normal logarithmic interference positioning in coplaner axes placing prime sight-line axes in the 1/2 symmetrical Singularity alignment. (All pictorial concepts of Geometric Orthographic Projection Drawing and Perspective combining Fluxion-Integral Temporal Calculus Condensation Actuality)
As simple as amateurish visualisation can be reduced without having to resort to trying to explain the pseudo random cycles of Fractal scaling conglomerations of Primes and Cofactors, this lecture has partially illuminated.
Mathematical Disproof Methodology has to have a sequence or algorithm of potential possibilities to test by assembly in a program list or Tabulation, but Projection Drawing Conception is a simultaneous holographic Modulation Mechanism interference positioning resonance Imaging. The eye of the Beholder has to make their own unique intuitive Observation and relate it to conventional terminology. This means the Clay Prize is earned by the people who interpret the Imagery. (?)
akay
Reimam hypothses ekath emai habi eka acra druni na ai reiammm ge com0elx nalyso tiwma
Comolex nalysis baswenam proof kram 😏
Okak laki. Omoelx nalysi mastee kalam.
Awesome
Complex anaysi wlain reut eka proof krla harinum har8am thama😏eka mawia wada 😂
Tyamn reimNm wage nikam dakam kiyan dwask ekum complex nalyso wlaim eadk kran 😂
Wado wage imtegraion krlai atha loeldi fial 😅utruak gani ok 🙄eka atha loeta hriyata apply wen epai 😂hasin imtegratiin 1k math hdwaki me dan....
Hello I'm from Brazil the formula of non-primes automatically you discover the primes are 3+3+3+3... to infinity and the 7+7+7... and the perfect squares odd minus ending 5 example 9×9.11 ×11.13.13...
I did not understand your question
Hello Almost that's right this is a vortex circle a vortex number are those that go from 1 to 9 with the (0) in the center there in the vortex the numbers go back and forth with their opposites vs example 7+7+7+7 opposite 3-3-3-3-3 also 8+8+8+8 opposite 2 -2-2-2 also 9+9+9+9 opposite 1-1-1-1 e 6+6+6+6 opposite 4-4-4-4 o number (5) fold in itself 5.10.15.20.25....... hope you understood a little thank you
Also Goldbach's conjecture is easy all odds are a pair with 1 more number and the primes are odd divided by 1 so added two primes add two (1)(1) Does not matter the size. it also has the wildcard numbers 2 that goes through all the pairs and the number 5 that doubles in itself 5.10.15.20....
This is dumb. Crap.
Hi This is Abhijeet Deshpande and....
This is how to understand the theorem....
Points:
1.) From 1 to 100, calculate the number of odds and evens
2.) Now for every single of the odd and even numbers, measure and write down the number of steps, for both to go to the number 4.
3.) For both the odd and even numbers, calculate individually as below,
a.) Add the number of steps to get a total of both odd and even
b.) Get a total of odd / even numbers by addition
i.e.
a.) How many numbers are odd and even
b.) And what the the sum total of odd and even by addition
c.) What is the sum total of odd and even by division
d.) What is the sum total of odd and even numbers by substraction
4.) Divide the number of steps with the number of odd / even numbers wiithin 1 to 100
5.) Now upon fiding the value of the division of both odd and even numbers,
Use the above results of calculations to calculate with the results to determine the base structure or the point of average c
divisions or calculations, where both the calculations of odd and even align,
And Voila, you have a symmetry of calculative set of equations that would determine the results of any similar supposedly unsolvable equations.
These equative calculations of mine can also solve the problems of Rieman hypothesis of prime numbers as well.
As such I am eligible to win the seed of Clay Institute for of and towards the same.
3x+1, Rieman Hypothesis
© Abhijeet Deshpande, 2021
Wah pandey
@@vikraal6974 💪😁👍
Pandeyji . how many pegs?
My mother s phone
But no pegs
Twis pr8ems oroof or disproof klaoth 😂
Twis priem kwadwath
Proof ornath ba
Disproof krath ba😏
Ewa tham atham maths mali 🙂
Api hotmu moka hari eka imtegration 1k
Complex versionn eken krla apsta edi wes num e imtefraionethod eki waradi 😅complexcersion ekek eka hari 🙄omum kram... 2k na😂
Kisim olamk or ona kisma deyak aey kdma qtne na😅
Onam syatwm ekak efiicetly kisima htwak natwa hriytma wadkrnwa tham ndeth ma😂aiecra lasnta wadlrme un reiman nami me🙂
Habi wada... Oestma🤣
Oya oagranti ths qage nmai.....aths nami oagrmati emgeerla wage nam ia😂
Compelx nalysis.
Complwx nalyis ema hodtam krla mathemtican kenek unoth 😏.... Katkrla wakd na thama
Reimanm hupothses eka proof kradi eda uwage wenwa. Misk
Millin dooes adla na😂
Ekgra powerful 😅mnihwma wes wenwa misk... Eka proof krpa na ba🙂edath reimma thdai bun adth emami 🙃
Pitacunweswewa misk 😏
D9ller milor gana krna eka hari kiyal dkina thanta edai... Miloen waod na😂kola klai wetrai.
Lokema dmagena misak proof tiyan oke hari qardk gan sanjwakwath htiam en na😂bun.... Mulu numenrs wla katwam. Chitryak wage pena one😅
Reimann hyooth8se dka pwrof krla eka me butiak lokewayh aduam thrnewa😂wen loeka koamwetha.....
Mnihwma smapurma 1k order ekta enwa ema twa eka dk8an ba 😂logic walta klewa reimann 😂reiman hyoothseis ke locily proof dena ba mada edan 😅ehen dadi mehen lissnwa🤣mehen wedi ehen lisnwa laga tiem kwadwath oeme na kwi lasna😅mukuth ndada na😂... Krpam baln pripuakkami threnwa u hari anith maths waradi.
Awkwma twispriem cojeture eka atrla dham 🙄nikam athel ek wem epa meka alam eka thrugam dgaldi meka it gives you free 😏
Have eny of you People New aboute this bolivia enginier, that supoust solve that all ready?
$1 Million? I would do it for 2 Million. What do you say?
I’d think about it.
I might be wrong, but this could work: ruclips.net/video/PvUrbpsXZLU/видео.html
P.S. A piece of advice: make video 1.5 times faster, I speak very slowly)
The answer to the Riemann Hypothesis is Infinity.
Infinity times infinity equals infinity to the power of infinity.
Infinity squared equals infinity to the power of infinity.
If 2 is a prime then so is infinity.
You are all welcome.
Your cheque is in the mail.
I think "EratoSTHenes", not "EraStoTHenon"
They also used a picture of Thales instead of Eratosthenes anyway!
36 54 Spirale
Logic walin kwadwath bsain bari dak8n bari ewagema ganite ekam stya😂aantha kalyak logiclproof kalth enen na🤣
Twims priem eka wage😅
E conjectrure eka hairth na wardith na 😏
Inatrum krakra edan... Krkreka ekta hari twimsla loel epden nwe
Eoademda na 😅
Ganige amata hukaku meodnewa raely hari...
Natum na🤣
Hetu ati weta ati we ntiwemen nati we😏wen phdli krla wediyak na
Twis primes... Hari ow... Amtya kt8wna ow😅amatyak nda na😂reimann hypothesi eka hari kiyal pligtoh num nikm daki 😅
Ok.... Eko reimmwa proof krm ba😏
Oya 2k tham mnikam yaku 2ka😏
1.reimann hypothesis
2.twis primes🙂
Twis priems maru wadi 😅proof krma ba
En isa rein hyoothesi eka axiom 1k krna😂ekao... Twisla eoden hetwa dkan 🙄bane hamoam reiman nami me🤔
I solved Riemann hypothesis which website I publish this is not Joke I am mathematician
So, true or not?
Good job, will you decline the prize like Grigori Perelman did?
@Cutiemouse yes decline 1 million money because real mathematician doesn't care money
I did not do this for money😎
What’s zeta of s=3?
@@mikedavid5071 ζ(3) = 1.2020569031595942853997381615114499907649862923404988
No podría estar al español
Solved it : ruclips.net/video/grxSNq5g6aI/видео.html