Z[i] is an Euclidean Domain - Result - Euclidean Domain - Lesson 5

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Here in this video i will explain a result which states that Z[i] is an Euclidean Domain.
everything is explained in Hindi
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Before this topic i did various other topics of Real Analysis:
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• Lower Bound, GLB and I... cyclic vbv

[@MirzaAkbaraliAkbarali-me1ff]

Osammmmmm lecture u are a great teacher (From Pakistan)

[@MrAjitutube]

#21:15 I believe explanation goes like this---send (m+in)(c+id) to the LHS gives (a+ib) - (m+in)(c+id) which belongs to Z[i] therefore RHS should belongs to Z[i]. Hence remainder 'r' belongs to Z[i].

[@learnmatheasily]

Yes .

[@biplusaikia4345]

22:47
It should be (alpha d+ beta c)^2 🤔🤔🤔

[@karanjakhar2000]

nice explanation mam thank you so much

[@mathematicalschool8691]

(alpha+i.beta).(c+i.d) kaise z(i) me belong karega? Kyuki alpha or beta to rationals v ho skte hain n?

[@learnmatheasily]

Alpha beta rationals nai integers he

[@UmaRubab-lo6cb]

Mam share the link in which prove is Z[I] is subring of C

[@learnmatheasily]

Please check playlist.

[@syeddanishiqbal5759]

mam I've lot of problem about delta valuation how we can think about de it? plz give me some logic for it

[@learnmatheasily]

Before taking any function just keep that in mind It should belongs to Z and sarisfy euclid's algorithm.

[@syeddanishiqbal5759]

@@learnmatheasily Ty

[@msakhawat3641]

f(a+sqrt(-5)b)=a^2 +5b^2 is ED ??

[@HELLOWORLD-en8xd]

I have some question mam

[@ranjansaraf2166]

Thank u mam

[@mohdtalhakhan7859]

thanks maim

[@kindaeasy9797]

4-5 aur variables le leti behen, itne mai hi kyu ruk gyi

[@learnmatheasily]

Next time bata Dena bhaiya kitne variables use karne he.