this one is a total hairball

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  • Опубликовано: 3 окт 2024
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Комментарии • 9

  • @doronezri1043
    @doronezri1043 3 дня назад +3

    In this case I think Fourier Transform may be more useful than Laplace. Specifically, the FT of Sinc is rect, so you have the convolution of two rects (triangle) evaluated at zero🍻

  • @reaperskyfall6691
    @reaperskyfall6691 3 дня назад +6

    I pray to almighty our journey of maths should progress along with succession of time and people who are with us hope achieve their goals before 2024 ends

    • @owlsmath
      @owlsmath  3 дня назад +1

      Hi Skyfall. Good thoughts! I’m with you 👍

    • @chrisjuravich3398
      @chrisjuravich3398 3 дня назад +2

      Pi/2 by inspection (and Lobachevsky).

    • @leif1075
      @leif1075 3 дня назад +1

      ​@@owlsmathwhy use such advanced maetbids a lot of ppl.will nkt have heard of..why nkt do integration by parts starting with sin ×^2/× or rewrote the numerstpr as 1 minus cos x^2..arent ppl more limely to do that and solve that way?? Thanks for sharing

    • @owlsmath
      @owlsmath  3 дня назад

      Hi @@leif1075 - does that work with integration by parts? I didn't try it that way but if it works its a good way. For me I do like to cover multiple ways so IBP would be fine :)

  • @archismanrudra9336
    @archismanrudra9336 3 дня назад +1

    Another option is find the laplace (or fourier transform) or sin x / x, which is a square wave in the frequency space, so the square of that has fourier or laplace which is the convolution product, which is not too hard to do. There is an interesting paper by one of the borwein brothers called borwein integral; not exactly the same, but the approach will work. Here is a video re that: ruclips.net/video/851U557j6HE/видео.html

  • @maxvangulik1988
    @maxvangulik1988 День назад +1

    would complex contour integration work?

    • @owlsmath
      @owlsmath  21 час назад

      I think it works here but I’m not sure. I didn’t try it