UGC NET Electronic Science June 2019 Part 3 (Q50 - Q75)

[@CravingGyan]

Q63. Soln
apply nodal analysis, u ll get
-1 + [(v-1)/j1] + V = 0
2V = 1+j1
Vmagnitude = sqrt(1+1)/2 = 0.707 which is approximately 1V

[@pranavedayoga]

Thanks alot sir for clarifying my doubt

[@CravingGyan]

Keep posting your doubts on Telegram group & get it cleared
Thank you

[@RiteshkumarSingh-ii2kh]

Thank you very much sir !!! Very good explanation video 👌👍

[@rajalingam4252]

Sir, please solve Q68

[@kademsthoughts5597]

Good explanation sir.. All ways ur videos and mock tests add more content and more confidence to me.. Sir... thanks keep rocking...

[@vismayagirivas3856]

Thank-you sir

[@sanketmitra8251]

I cannot find any link for Q76-Q100 solutions

[@CravingGyan]

I'll upload ASAP

[@CravingGyan]

ruclips.net/video/1MlotjQYlwM/видео.html

[@ganapathisaraswathi9045]

sir to get top marks how to prepare and which are the text book to prepare

[@CravingGyan]

Be strong in fundamentals

[@saavib471]

Thank you sir... Next solutions of Q. 76 to 100 when will come?

[@CravingGyan]

coming soon

[@saavib471]

@@CravingGyan okay sir

[@jyotisujeeth8391]

Sir difference between negative instructions and not instructions is it both perform same operation

[@CravingGyan]

NOT is logical operation
NEG is 1s complement

[@jyotisujeeth8391]

@@CravingGyan thank you sir

[@kademsthoughts5597]

Max 3 order dynamic range =2/3(noise level - 3rd order intercept)
Then nl=-95db, toi=30db
=2/3(-95-30)
=-83.33
I think we have to apply modulus then 83.33=83db
If I am wrong correct it sir?

[@studytosuccess7351]

Sir in question 63 if we apply the kcl on resistor nodewe can find out tha value of voltage 1v without knowing tha value of capacitor.

[@CravingGyan]

Q63. Soln
apply nodal analysis, u ll get
-1 + [(v-1)/j1] + V = 0
2V = 1+j1
Vmagnitude = sqrt(1+1)/2 = 0.707 which is approximately 1V

[@crazymithleshmoments457]

HOW YOU SOLVE QUESTION NO 69...

[@jyotisujeeth8391]

Thank you sir