Push Pull Power Amplifier Output Stage Circuit Analysis, Class B Push Pull Amplifier Solved Problem

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  • Опубликовано: 12 дек 2024

Комментарии • 15

  • @EngineeringinDepth
    @EngineeringinDepth  11 месяцев назад +1

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  • @hieuo3073
    @hieuo3073 3 месяца назад +2

    very interested .thank you

  • @Enigma758
    @Enigma758 11 месяцев назад +1

    These are great practice problems, please keep them coming! Are you a prof?

  • @surendrakverma555
    @surendrakverma555 11 месяцев назад +1

    Very good

  • @BBoysAndTrickers
    @BBoysAndTrickers 28 дней назад

    when do we know to use open circuit or assume high and low of ac in? my professor does open circuit in most cases especially with mosfet or is that for mosfet only

    • @EngineeringinDepth
      @EngineeringinDepth  27 дней назад +1

      Can you please clarify the use of open circuit? do you mean when there is no any voltage applied to the input terminal?

    • @BBoysAndTrickers
      @BBoysAndTrickers 27 дней назад

      @@EngineeringinDepth yes, with Vp still active

    • @EngineeringinDepth
      @EngineeringinDepth  27 дней назад +1

      @@BBoysAndTrickers In MOSFETs and FETs, since the gate terminal doesn't draw any current (we can neglect the very small current to the gate) , then we can assume the the gate terminal has zero voltage when there is no voltage applied to the gate.

  • @artemdavinci
    @artemdavinci 11 месяцев назад +1

    Why the gain factor for base current calculation? These are unrelated parameters.

    • @EngineeringinDepth
      @EngineeringinDepth  11 месяцев назад

      Do you mean Beta is unrelated? can you elaborate more?

    • @artemdavinci
      @artemdavinci 10 месяцев назад

      @@EngineeringinDepthThe base current depends on the base resistor and the voltage. The base current becomes part of the emitter current, but does not increase. Beta affects only the collector current and the emitter current

    • @EngineeringinDepth
      @EngineeringinDepth  10 месяцев назад +1

      @@artemdavinci For BJT transistors, we always have IE = (1+β) *IB and IC = β*IB. The fact that we use BJT transistors is their current gain. The transistors in this output stage are configured as a common collector (emitter follower) for this reason to provide higher output current gain at their emitter terminals.