sir there is an error, according to the question there is only 2 'i4' but in the 1-item set the mentioned data frequency has 4 so just correct that part :)
confidence = Frq(x,y)/frq(x). So why is it divided by the number of items (N)? So, the confidence calculation is incorrect. Please correct me if I'm incorrect.
Frequency of I3 at the first calculation should be 6
Yes and also I4 is 2
i know right? huddar what bro
sir there is an error, according to the question there is only 2 'i4' but in the 1-item set the mentioned data frequency has 4 so just correct that part :)
@@MaheshHuddar 2 item sets I2 and I3 frequency is 4
@@MaheshHuddar nope even I3 are 6, but he only wrote 5 of them
and also i3 has an error the frequency is 6 not 5
Sir please continue the videos.... Complete other modules also... It's helping me a lot...
You're a legend.
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Sir actually the 1item sets the item4 have frequency 2 and the item5 have also have frequency 2 but you write 4 is there it's wrong sir
Thank you! Really clear
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@@MaheshHuddar Can we use bread butter example method to find association rules for this problem? Please clarify
Thank you🙂
Perfect explanation ❤️
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ur a legend. Thanks a lot for the videos..
You're welcome!
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Sir, frequency of i4 in first calculation is 2 kada ?
Sir, frequency of i2,i3 in 2-item set is 4 ?
Sir finnali ans correct a vachindi sir ela tesukunna .
very nicely explained sir
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Thank you sir
Welcome
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This video is well. But with the mistake you made, it spoiled everything. In my opinion, you need to redo it. :-)
But it was helpful
I3 support is 6
yes
Also I4 support is 2
Sir but i3 is there in 6
I2, i3 came 4times in items but u took 3times
confidence = Frq(x,y)/frq(x). So why is it divided by the number of items (N)? So, the confidence calculation is incorrect. Please correct me if I'm incorrect.
same confusion have come through Any conclusion
awesome
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how one can come to know minimum support is 2
1 item set... value of i3 has to be 6
great video , how can we determine the value of support and confidence level during the real life example
They will give during the exam
Sir for subset creation part, how to know min support = 22% and min confidence = 50%
Confidence will be given in question
And support they have given 2 in question so total items is 9
So 2/9 is 22😊
@@supriyabala6954 thank you Supriya Bala :)
@@supriyabala6954 What if in 3item set no item satisfies min. Support ??
then how to proceed??
@@samarendrasingh1456maybe you can try proceeding in the same way but do it for 2 frequent itemset
Sir,What If a transaction id contain more than one similar item should we consider that as one during frequency count
??
Consider two times
@@MaheshHuddar Sir and in Fp growth we should only consider once??
Sir while calculating the support and confidence(initially) the frequency of which two items should be taken sir ??
Min support 33.33 how I will calculate
(9*33)//100
@@tejapandruvada7164 What if in 3item set no item satisfies min. Support ??
then how to proceed??
what if minimum support count is 3.5 what should we take ? 3 or 4 ?
Consider above 3.5 values
@@yamelite7520 thanks
What if in 3item set no item satisfies min. Support ??
then how to proceed??
Then take freq 2item set
hello sir the frequency of I3 is 6 times and you have taken 5 times
It is 6