Thank you!! For explaining in actual English( not textbook language) and without any annoying equations, and for actually showing the circuit in practice and it's graph. Wow man, I couldn't ask for more.
Hi, sir and all others, I wonder what if we have a capacitor directly connected to a voltage source. Is there a way to find the I(t)? Due to the absence of a resistor, we cannot get a time constant. Thank you
i(t) =C•d/dt v(t), if v(t) = A•u(t) then i(t) = A•C• delta(t), it means the capacitor will be charged with no time at A volts by an infinite current. In practice it doesn't happen as the power supply have a resistance as well as the capacitor, but is not recommended at all as it creates a current peak which could damage the power supply or the capacitor.
That's why capacitors can be lethal. They will hold that charge and will give you a real wake up call if you were to touch the leads. 12v won't kill you but if you're working on an amplifier where there could be 400v stored on a capacitor it could kill you. Hence the importance of discharging capacitors before working on anything. Thank you for such a great and simple explanation.
that was a good explanation. I remember you said you'd do a follow-up vid on how capacitors behave in AC circuits. Was looking forward to it as this seemed to lay the foundation... couldn't find it. Did you do one? Could you do one? Thanks
At 4:30 you said when the capacitor charges up, there will be no PD between the battery and the former, so does that mean before it charges up there is a PD between them? as in through the wire? Or where would this PD be? Thank you so much your videos are amazing!
I am still not clear on this. My problem is I have a model train passenger car. It is a lighted car and when it goes over a dirty rail and loses connectivity, the light goes out. What value of a 24volt capacitor that will hold about two seconds worth of charge at 14 volts so that the light never turns off while running. I am actually using a strip of 12 volt LEDs and have tried a couple of capacitors that I had but they don't hold power more than a fraction of a second. Thanks in advance for your help.
You forgot as usually everyone does, to explain how they charge and discharge since a battery is always trying to flow to it. How does the cap know when to discharge and from which side does it discharge? those are the questions I needed answers too. otherwise good video.
Most of the current would flow through the capacitor as it charges up. At this time little current goes through the resistor, but as the capacitor approaches Full Charge most of the current travels through the resistor. Once the Capacitor is fully charged - All of the current is going through the resistor. This is only when the resistor and the capacitor are in parallel to each other.
How about a Capacitor and Inductor in series with a DC battery, Can you please make a video on the Physics what happens? no resistors involved. Thank You, Sir. Now also the same dc battery connect the inductor and capacitor in parallel, please explain the Physics how the inductor and the capacitor: current and voltages.
current does not flow from positive to negative, its flow is from negative to positive, Benjamin franklin falsely stated that conventional current flow is from positive to negative his theory was later disproved
I have yet to see anyone explain this to me in English But...here’s my grasp DC signals do fuck all to capacitors Because...... Capacitors are basically batteries Shitty batteries, you wouldn’t use them as a battery...but....they are a little can that can get full of angry pixies and discharge them later So....putting a DC power on a capacitor is gonna be about as interesting as putting a battery on a battery charger.....”real fuckin neato” And once that battery is full....pixies don’t want shit to do with it It’s a traffic jam in their, and there’s nowhere for the pixies to go So....unless you’re gonna pick the capacitor up and shock your friend....putting a DC signal on a capacitor by itself is useless But, it seems in amplifiers....we take an AC signal AND a dc signal to boost our ac signal with some hardcore DC power Then use the capacitors to get rid of the DC power to give us a super-charged AC signal Is this at least a tentative grasp?
Thank you!! For explaining in actual English( not textbook language) and without any annoying equations, and for actually showing the circuit in practice and it's graph. Wow man, I couldn't ask for more.
Thanks man, this was a great brush up for me after a few years of not studying circuits. Excellent explanation.
Nice video. Its hard to realy find god videos expleaning elektroniks. So tanks alott, eksues my bad english here from Norway. Thanks agan.
Hi, sir and all others,
I wonder what if we have a capacitor directly connected to a voltage source. Is there a way to find the I(t)? Due to the absence of a resistor, we cannot get a time constant. Thank you
i(t) =C•d/dt v(t), if v(t) = A•u(t) then i(t) = A•C• delta(t), it means the capacitor will be charged with no time at A volts by an infinite current. In practice it doesn't happen as the power supply have a resistance as well as the capacitor, but is not recommended at all as it creates a current peak which could damage the power supply or the capacitor.
So nice explanation sir thanks
That's why capacitors can be lethal. They will hold that charge and will give you a real wake up call if you were to touch the leads. 12v won't kill you but if you're working on an amplifier where there could be 400v stored on a capacitor it could kill you. Hence the importance of discharging capacitors before working on anything. Thank you for such a great and simple explanation.
Thanks a lot, This video really help us to understand
Excellent presentation young man! I am also VERY impressed....TEKTRONIX equipment! You take things SERIOUSLY!!! That's GREAT!
BTW....."subbed" now.
Thank you for the video. Can you link to the next "Capacitors in AC Circuits" I can't find it.
Thx
Does the top half (the plus side) of the circuit also have current flowing through it when the capacitor is charging?
that was a good explanation. I remember you said you'd do a follow-up vid on how capacitors behave in AC circuits. Was looking forward to it as this seemed to lay the foundation... couldn't find it. Did you do one? Could you do one? Thanks
Oh man!!!! Thanks a lot...You really helped me out.
At 4:30 you said when the capacitor charges up, there will be no PD between the battery and the former, so does that mean before it charges up there is a PD between them? as in through the wire? Or where would this PD be? Thank you so much your videos are amazing!
Thanks man, very helpful while trying to get into this by myself =D
I am still not clear on this. My problem is I have a model train passenger car. It is a lighted car and when it goes over a dirty rail and loses connectivity, the light goes out. What value of a 24volt capacitor that will hold about two seconds worth of charge at 14 volts so that the light never turns off while running. I am actually using a strip of 12 volt LEDs and have tried a couple of capacitors that I had but they don't hold power more than a fraction of a second. Thanks in advance for your help.
Nice video, when wil you be doing "Capacitors in AC Circuits"?
You forgot as usually everyone does, to explain how they charge and discharge since a battery is always trying to flow to it. How does the cap know when to discharge and from which side does it discharge? those are the questions I needed answers too. otherwise good video.
Q. How can I figure out the current flowing in the simple circuit you have drawn ??
Put an ammeter in the circuit
This I understand cheers
Does the Current relationship transfer to Farads then back to Current?... I think that's sounds correct... but.. I doubt my own brain.
thank you very much
very good expilnation
Why does the capacitor try to charge upto 12v only?
because that is the voltage supply in this circuit
if the supply voltage was 20 v then it would
charge up to 20 volts
what would happen if you put a 3 ohm 1/2 watt resistor in parallel with the capacitor?
Most of the current would flow through the capacitor as it charges up. At this time little current goes through the resistor, but as the capacitor approaches Full Charge most of the current travels through the resistor. Once the Capacitor is fully charged - All of the current is going through the resistor. This is only when the resistor and the capacitor are in parallel to each other.
got any servers still?
Nope, explained that in vlog 4. Im doing electrical engineering now.
Current flows inversely to voltage and voltage flows from positive to negative.
How about a Capacitor and Inductor in series with a DC battery, Can you please make a video on the Physics what happens? no resistors involved. Thank You, Sir. Now also the same dc battery connect the inductor and capacitor in parallel, please explain the Physics how the inductor and the capacitor: current and voltages.
ThanQ
current does not flow from positive to negative, its flow is
from negative to positive, Benjamin franklin falsely stated
that conventional current flow is from positive to negative
his theory was later disproved
On a resistor is almost 20W in a short amount of time.
Hows ur leg man?
It is theory. Don't waste our time with the argument.
Made a simple concept too complicated
How come you repeat just about every single word/sentence?
you need to improve audio
Hard to follow!
I have yet to see anyone explain this to me in English
But...here’s my grasp
DC signals do fuck all to capacitors
Because......
Capacitors are basically batteries
Shitty batteries, you wouldn’t use them as a battery...but....they are a little can that can get full of angry pixies and discharge them later
So....putting a DC power on a capacitor is gonna be about as interesting as putting a battery on a battery charger.....”real fuckin neato”
And once that battery is full....pixies don’t want shit to do with it
It’s a traffic jam in their, and there’s nowhere for the pixies to go
So....unless you’re gonna pick the capacitor up and shock your friend....putting a DC signal on a capacitor by itself is useless
But, it seems in amplifiers....we take an AC signal AND a dc signal to boost our ac signal with some hardcore DC power
Then use the capacitors to get rid of the DC power to give us a super-charged AC signal
Is this at least a tentative grasp?
I swear I was told current flowed negitive to positive
Jud Stansell electrons do. Conventional current no. Watch my video series on the physics behind electricity to see the difference.
I really hope 2 years later since posting this video you have realised that DC does not flow from positive to negative.
Positive to negative flow is the conventional current representation, which he mentioned.
Was about to ask, because the last video I watched trying to understand this said it goes from negative to positive...