Performance of Reliable Data Transfer - Transport Layer | Computer Networks Ep. 3.4.2 | Kurose, Ross

Describing the performance constraints incurred by stop-and-wait vs. pipelined algorithms. This is setting the stage for discussing the TCP transport protocol in future videos.
Based on Computer Networking: A Top-Down Approach 8th edition, Chapter 3, Section 4.2, 4.3, and 4.4.
Slides are copyright 1996-2020 J.F. Kurose, K.W. Ross All Rights Reserved., and freely available here: gaia.cs.umass.edu/kurose_ross...
Background music: www.epidemicsound.com/referra...

[@cliintbeastw00d]

this is better to follow than reading word for word with the book. i'm happy i found you, i wouldn't be able to read this so clearly.

[@EpicNetworks]

Glad it was helpful!

[@brainify6172]

I'll surely recommend this channel to my fellow classmates. Very Nice and Apt Explanation. Helped in my exams, to study and review fast. Thanks a Lot!

[@EpicNetworks]

That's great! Glad the videos are helpful!

[@xZ1gZagx]

Great explanation of the Go-Back-N and Selective Repeat algorithms.

[@EpicNetworks]

Glad it was helpful!

[@habibaghasafari2237]

I might be wrong but in your example, at 1:58 I think the utilizing speed should be 270 Kb/s. If we multiply (0.00027*10^9)/1000 = 270 Kb/s but you said 33 Kb/s. Did I understand it wrong? How the utilizing speed is 33 Kb/s ?

[@EpicNetworks]

I misspoke. It should be 33 kB/s, not 33 kb/s.

[@habibaghasafari2237]

@@EpicNetworks Yes, so I was right. it was 270 kbits/s which is 33.75 kbytes/s. Thank you for clarifying it.

[@habibaghasafari2237]

Also, at 2:56, instead of 0.024 you wrote "0.0024". Also 0.024/30.008 = 0.00079978 which rounds up to 0.0008 not "0.00081"

[@EpicNetworks]

These are the Kurose & Ross slides, I didn't write them.

[@habibaghasafari2237]

@@EpicNetworks ok so the slides are wrong.

[@mett_2002]

It sure is a bot

[@ajeyarajupadhyaya8287]

Very bad teaching