Hi, thank you very much for this great video very detailed and well explained. Please could you help by explaining why the tetrahedron 4-noded and the triangular 3-noded finite elements do not require numerical integration while the 8-noded quadrilateral finite element does.
Thanks for your comment. Numerical integration is used to solve complex integration. For the case of 3 Noded triangular element, you are dealing with constant strain triangle (CST), therefore, you are simply integrating a constant number.
Thank you very much ! I was wondering for shear locking, you said "linear element cannot represent that curved edges..." but fully integrated element are no more linear ?
Linear elements can be both fully integrated or have reduced integration. Full integration will only cause shear locking, to avoid it we can either use linear with reduced integration or higher order with full or reduced integration.
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thankyou nice explanation sir
sir plz make a similar video on surface traction, edge traction ,patch test
Great explanation. thanks a lot, sir. It would be better if you could explain it with an example
You are welcome. I am glad you found it helpful. I will try to incorporate more examples in my lectures every semester I teach it.
Great lectures. Thanks !
You are welcome! I am glad you found it helpful
Hi, thank you very much for this great video very detailed and well explained. Please could you help by explaining why the tetrahedron 4-noded and the triangular 3-noded finite elements do
not require numerical integration while the 8-noded quadrilateral finite element does.
Thanks for your comment. Numerical integration is used to solve complex integration. For the case of 3 Noded triangular element, you are dealing with constant strain triangle (CST), therefore, you are simply integrating a constant number.
it seems that 12:39, you were wrong, "a" and "b" should be a = C0 - C1. And b = C0 + C1. Isn't it?
Hi,
You are right, that’s a typo.
It will not affect the equation though.
Thank you very much ! I was wondering for shear locking, you said "linear element cannot represent that curved edges..." but fully integrated element are no more linear ?
Are Linear element "automatically" fully integrated ?
Linear elements can be both fully integrated or have reduced integration. Full integration will only cause shear locking, to avoid it we can either use linear with reduced integration or higher order with full or reduced integration.