Thank you so much!! ♥️ My teacher took almost two hours to explain it and I still need to watch someone else to understand, yet you did it in 10 minutes!!! Thank you again
Oh my goodness. Thank you guys so much. You are saving my life right now! (Ok so that's an exaggeration, but you ARE saving my circuits course: I've read my text-book on this and tried to understand but was confused until I saw this!) Thanks again!
i read the textbook and the references on the syllabus and with the doctor explainibg in the class and all of the brushed over it and didn't give this detail. thank you some much . بيض الله وجهك منيه ليوم الدين وفي كل كتاب وسنه
When analyzing a circuit, the first thing is to assign reference directions across elements when they are not given. The way my book explained it is as follows: If the current is entering the positive terminal, just plug in the values obtained, i.e., V = IR, P = VI. Otherwise, just add a negative sign. Note that given that reference directions are arbitrary, you could get negative values for I and/or V. That can trip people up because if they get a negative value for I or V while I is entering the negative terminal, they’re afraid to add the appropriate negative sign.
@5:00 So, when we 'fix' the reference voltage so positive current enters positive voltage node, we make the negative current enter the negative voltage node? If this is not the case, I am confused, because it just looks like negative current enters positive voltage node. If you could please explain this that would be great.
Think of it this way: P = I*V. In that case the I = -2A and it was entering the minus terminal which through passive sign convention means we calculate the I as negative (if the current enters through the positive terminal we calculate the I as positive). So P = (-I)*V and since I has the value -2A in this case it goes like this P = -(-2A)*V = 2A*V.
Thank you so much!! ♥️
My teacher took almost two hours to explain it and I still need to watch someone else to understand, yet you did it in 10 minutes!!! Thank you again
Oh my goodness. Thank you guys so much. You are saving my life right now! (Ok so that's an exaggeration, but you ARE saving my circuits course: I've read my text-book on this and tried to understand but was confused until I saw this!) Thanks again!
this professor is amazing. very detailed and clear. 100 likes on his lecture.
Literally the best circuit video out there for explaining this fundamental crucial foundational concept, this video should have a lot more views.
Read textbook and lectures useless with trick poll questions....This video saved me time and made me feel like zeus. thank you
Your 10 min video was better than the 3 books I have read.
Respect from India.. Thanks a lot!!
i read the textbook and the references on the syllabus and with the doctor explainibg in the class and all of the brushed over it and didn't give this detail. thank you some much .
بيض الله وجهك منيه ليوم الدين وفي كل كتاب وسنه
Amazing, simple and comprehensive explanation! Thanks a lot
Excellent video!
WELL DONE SIR. I UNDERSTAND A LOT FROM YOUR VIDEO. EVEN THOUGH THIS IS MY 1ST TIME LEARNING THIS.
Straight to the point, I LOVE IT!
Thank you very much, I search correct video about this concept this correct video I understood very clearly than ever before🎉😊
You are an excellent teacher. Thank you so much!
You are a perfect teacher. Thank you so much..
Awesome content.
Preparing for my circuits exam that's tomorrow. Thank you so much!
When analyzing a circuit, the first thing is to assign reference directions across elements when they are not given. The way my book explained it is as follows: If the current is entering the positive terminal, just plug in the values obtained, i.e., V = IR, P = VI. Otherwise, just add a negative sign. Note that given that reference directions are arbitrary, you could get negative values for I and/or V. That can trip people up because if they get a negative value for I or V while I is entering the negative terminal, they’re afraid to add the appropriate negative sign.
This video literally redeemed me. Thanks so much
i am in love with this guy...amazing keep it up
Thank you so much, Professor. I hope you could post up more videos about Electric Circuits.
Thanks a lot for your good explanation
Wow you are superb
5:25 doesn't -2A means current just flowing through the opp side, in this case positive terminal? So no need to change voltage polarity?
you are great teacher
This was a great explanation! Many thanks,
@5:00 So, when we 'fix' the reference voltage so positive current enters positive voltage node, we make the negative current enter the negative voltage node? If this is not the case, I am confused, because it just looks like negative current enters positive voltage node. If you could please explain this that would be great.
Think of it this way: P = I*V. In that case the I = -2A and it was entering the minus terminal which through passive sign convention means we calculate the I as negative (if the current enters through the positive terminal we calculate the I as positive). So P = (-I)*V and since I has the value -2A in this case it goes like this P = -(-2A)*V = 2A*V.
thanks for making me understand what i fail to understand in 5hour lecture
TERIMA KASIH BANGET PAKKKK
Excellent job!
Thank you so much you’re so amazing
very helpful, thank you
you are a life saver
Great stuff!
Sir when current enter into negative and leave into positive so current is negative or voltage is?
thanks so much
🇮🇳 Jai Hind
Thank you
super-useful video... thank you btw!
You're very welcome!
I like it yoo
Awesome
Great!
God bless you
Hey pardon my ignorance..... but wouldn't this be -2W?
I believe this is -2W and its generated, but fiik
Are we the only one who noticed this?
@@chayannesantiago8231 but how?
Lifesaver
1 que if current leaves from +ve terminal it should be supplying power but u write it's absorbing?
It's absorbing for the circuit element not for source
Sir , could please write the information you have said here ?
I just wanna understand the power absorbed and supplied
i think the last question answer 10:34 supposed to be -2w generated
Τ Η Ε Β Ε S T !
Just saved me from giving up on school
I am not sure when the current is going to be negative
I got confused when he switched signs at 4:09
Passive sign convention made simple
I love you.
My exam is in an hour. I probably shouldn't be here
Ampere per serving = coulombs.
Basically a Mesh analysis of the circuit...
Thanks a lot