Impulse problem

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  • Опубликовано: 15 окт 2024

Комментарии • 16

  • @yoprofmatt
    @yoprofmatt  10 лет назад +3

    Because that was a mistake. Good catch!

  • @ArcanumObscura
    @ArcanumObscura 10 лет назад +4

    How did you get 24 m/s using (2.5-.98)(10) ?
    I got 15.2 m/s

    • @maxsolar1139
      @maxsolar1139 6 лет назад +2

      I know it was three years ago but I definitely should have read the comments xD... I spent a good ten minutes redoing my work to see why I wasn't getting 24m/s

  • @williamcashion5262
    @williamcashion5262 2 года назад

    Did you ever do (like) a water jet on a wall or like air molecules on a piston? Ie, a high collision rate?

    • @yoprofmatt
      @yoprofmatt  2 года назад

      No, I'll have to put that on the to do list. Great idea.
      Cheers,
      Dr. A

  • @pipertripp
    @pipertripp 6 лет назад +1

    I like how the kinematic equation Vf = Vo + at just falls out of the impulse concept. The latter is obviously more powerful since the force applied doesn't have to be constant.

    • @yoprofmatt
      @yoprofmatt  6 лет назад +1

      Pretty cool, eh.
      Note: Here we used a constant force so we could bring it out of the integral, and then of course we end up with a kinematic equation. If the force is not constant, then you can't bring it out of the integral, you don't get constant acceleration, and you can't use the kinematic equations.
      Cheers,
      Dr. A

    • @pipertripp
      @pipertripp 6 лет назад +2

      yep. that what I meant by the last bit. Thanks for all of these vids. Very helpful, esp I'm just learning this stuff on my own for fun.

  • @igml1145
    @igml1145 8 лет назад

    in the first problem, could we use newton's second law and find a, a=F/m=2.5 m/s^2
    then v_f=v_i+a*t=a*t=2.5*10=25 m/s... we get the same thing

    • @yoprofmatt
      @yoprofmatt  8 лет назад

      +ig ml
      Ig,
      Absolutely you can! Well done.
      Cheers,
      Dr. A

  • @jntmisra
    @jntmisra 6 лет назад

    I am confused about this situation where in a cart there is a bob hanging through a string and a bullet hits the bob horizontally ( the cart is open from one end) so will momentum be conserved in cart + bob + bullet system or just in bob + bullet....i thought that momentim will be conserved in first system but in the solution givwn in my book they chose second system and i sont understand why

    • @yoprofmatt
      @yoprofmatt  6 лет назад

      This is what you want: ruclips.net/video/h_rnqo7XB2U/видео.html
      Cheers,
      Dr. A

  • @RavinderKumar-os8wn
    @RavinderKumar-os8wn 4 года назад

    Bhai kati zhr

  • @RavinderKumar-os8wn
    @RavinderKumar-os8wn 4 года назад

    👍👍💯💯

    • @yoprofmatt
      @yoprofmatt  4 года назад

      Vishal Rao,
      Thanks for the comment, and keep up with the physics!
      You might also like my new website: www.universityphysics.education
      Cheers,
      Dr. A