Riemann Hypothesis visualised

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  • Опубликовано: 2 окт 2024

Комментарии • 65

  • @DeanNiemi-r1m
    @DeanNiemi-r1m Год назад +8

    It is no coincidence we use t for both the imaginary part of the complex argument and a time variable. Reimann is inviting us to walk along the real 1/2 line to inspect the complex codomain values. Think of time as a cursor.
    Generally, nobody uses the variable t without it meaning time.
    This part is more advanced, but it can get confusing if later on we wish to use t as the codomain imaginary variable. Then a paradigm shift is in order.

    • @nunnyu
      @nunnyu 4 месяца назад +5

      zip up riemanns pants when you are done bro

  • @p_square
    @p_square 2 года назад +23

    one of the most beautiful functions in mathematics

    • @kodtech
      @kodtech 2 года назад

      is just a Polylogarithm function case....

  • @frankansari3457
    @frankansari3457 4 года назад +18

    Would be nice to have t to be also shown (perhaps as growing bar seperately).

    • @MarkusShepherd
      @MarkusShepherd  4 года назад +5

      Frank Ansari yes, I agree. This would pretty much be the same as plotting the argument and the image it maps to at the same time.

  • @willyou2199
    @willyou2199 7 лет назад +9

    at the start z(0).. did you mean z(1/2+0i) ?
    because z(1/2)= -1.46......, and z(0)= -1/2

    • @MarkusShepherd
      @MarkusShepherd  7 лет назад +6

      Yes, you are right, my mistake. :-( Unfortunately, youtube doesn't let me edit those any more, so we'll be stuck with that error...

    • @GorjeCeleb
      @GorjeCeleb 5 лет назад

      hello

  • @SidneySilvaCarnavaleney
    @SidneySilvaCarnavaleney 3 года назад +3

    ¿Qué impacto causaría si afirmo que he encontrado el número primo más grande y más pequeño encontrado en todo momento, ya que la "Hipótesis de Rielman ha perdido toda su fuerza, ya que afirmo que algunos números no son primos"?
    Estimado noble amigo de este sencillo canal, con mi respeto a los profesores, alumnos y amigos de este sencillo canal, les reportaré algo muy intrigante sobre estos números primos, con un simple PA (Progresión Aritmética), puedo decir con total veracidad, demostrando científica y matemáticamente que los números que citaré a continuación no son primos, y los primos gemelos no existen:
    2; 19; 41; 59; 61; 79; 101; 139; 179; 181; 199; 239; 241; 281; 359; 401; 419; 421; 439; 461; 479; 499; 521; 541; 599; 601; 619; 641; 659; 661; 701; 719; 739; 761; 821; 839; 859; 881; 919; 941; 1019; 1021; 1039; 1061; 1181; 1201; 1259; 1279; 1301; 1319; 1321; 1361; 1381; 1399; 1439; 1459; 1481; 1499; 1559; 1579; 1601; 1619; 1621; 1699; 1721; 1741; 1759; 1801; 1861; 1879; 1901; 1979;
    ¿Y cómo sería la hipótesis de Rieman, si estos no son primos? Al tratarse de un descubrimiento innovador en el Universo de las Matemáticas, los enunciados de épocas pasadas quedan nulas, dice el autor de la obra "Un atrevimiento del pi ser racional", Sr. Sidney Silva.
    Dentro de mi obra "La audacia de π para ser racional", demostrando Matemática y Científicamente que es un número Racional e Irreversible con una fracción de números enteros.

    • @zokalyx
      @zokalyx 2 года назад +3

      ???
      This looks AI generated

  • @Jon-mi8by
    @Jon-mi8by Год назад +2

    its almost like gravity of the function is changing

  • @DivineRedwood
    @DivineRedwood 2 года назад +2

    *True or false - every time the graph "hits" the origin (0,0) a "prime number" is shown to exist.*

    • @denysvlasenko1865
      @denysvlasenko1865 2 года назад

      Incorrect...

    • @omerd602
      @omerd602 Год назад +1

      False - there's much more nuance to it than that, although the values of the zeros do help in determining the locations of primes

  • @wisecase2136
    @wisecase2136 7 лет назад +14

    What series do you use to calculate this?

    • @MarkusShepherd
      @MarkusShepherd  7 лет назад +4

      wisecase 2 www.riemannhypothesis.info/2016/04/visualising-the-riemann-hypothesis/

  • @thatkindcoder7510
    @thatkindcoder7510 2 года назад +1

    Engineers after checking the first 10 zeros to a 2 decimal place precision: "Seems true"

  • @Jeff-zc6rr
    @Jeff-zc6rr 6 месяцев назад +1

    too bad this isn't the riemann zeta function. This is the analytical continuation of the zeta function, or what we call the functional equation., If you try to put the zeros of the riemann zeta function into the actual riemann zeta function it does not go to zero.

  • @JwalinBhatt
    @JwalinBhatt Год назад +2

    This is awesome, but I always wonder why do we approximate the prime counting function to begin with? Cant we have Riemann like approximation for a smooth curve which passes through the primes: 2,3,5,7,... but not in staircase fashion?

    • @lih3391
      @lih3391 Год назад

      Likely its difficult to come up with a function like that, it might just come less naturally from the math

    • @JwalinBhatt
      @JwalinBhatt Год назад

      @@lih3391 Could be, but there has to alteast be some attempt or perhaps a formal definition of the problem.
      Something like a Bohr-Mollerup theorem for primes. People could just try brute forcing or some searching algorithm (Eureqa software) in the space of functions to have some good guesses.
      There has to be atleast something in this direction, I wonder why I cant find anything.

  • @mechwarreir2
    @mechwarreir2 8 лет назад +5

    is there any symmetry to this pattern or is it completely random? I would think its random since the zeta function is composed of an infinite product of primes.

    • @MarkusShepherd
      @MarkusShepherd  8 лет назад +5

      The zeta function itself is highly symmetrical - it has two axes of symmetry, Re z = 1/2 and the x-axis. This means you could have the mirrored spiral going "south" along the critical line. Otherwise we're still trying to understand the pattern of the zeros and why they all line up on Re z = 1/2... ;-)

    • @mechwarreir2
      @mechwarreir2 8 лет назад +1

      I meant symmetries in polar form. Also I don't think Re(z) = 1/2 is a symmetric axis since there are countably infinite zeros on the analytical continuation to Re(z) < 0 but no zeros right of Re(z) =1/2.
      As for polar form, I've never seen a more chaotic analytical spiral. Being a hypertrancendental function, you cannot express the zeta function as a solution to a differential equation, otherwise you should be able to use a fourier transform to derive all symmetries and solve the Riemann hypothesis.

    • @sarithasaritha.t.r147
      @sarithasaritha.t.r147 Год назад +1

      There is always, always a pattern to everything

    • @brandonfox9618
      @brandonfox9618 7 месяцев назад

      @@MarkusShepherdThey’re not just zeros. They’re “non-trivial” zeros!

  • @MatveiPB8
    @MatveiPB8 3 года назад +1

    Cursos de la Corporación Andina del Fomento en Economía, Edtoy subiendo el curso 0 para el programa del CAF

  • @rainbowbloom575
    @rainbowbloom575 4 года назад +4

    How are the zeroes of the function related to prime numbers?

    • @MarkusShepherd
      @MarkusShepherd  4 года назад

      Cristina López well, that's a big question... I answered some of it in my blog, a good article to start would be this one: www.riemannhypothesis.info/2014/10/tossing-the-prime-coin/

    • @rainbowbloom575
      @rainbowbloom575 4 года назад

      @@MarkusShepherd Many thanks xD, I will try to understand

    • @rainbowbloom575
      @rainbowbloom575 4 года назад

      Also, what music plays in the background?

    • @MarkusShepherd
      @MarkusShepherd  4 года назад

      @@rainbowbloom575 I actually don't know. It is one of RUclips's free music that I just chose from their list, but by now so much has changed in their interface that I cannot find the name anymore...

  • @frankansari3457
    @frankansari3457 Год назад +2

    One of my favorite RUclips videos ever.

    • @Alexander-oh8ry
      @Alexander-oh8ry 3 месяца назад +1

      Wow, my condolences for your uninteresting life

  • @mihaleben6051
    @mihaleben6051 3 месяца назад

    >looks at graph
    >crosses zero multiple times
    So uh...

  • @minn2410
    @minn2410 4 года назад +1

    A Bow. Told U so..

  • @jennyone8829
    @jennyone8829 Год назад

    🎈

  • @momomomomomo842
    @momomomomomo842 7 лет назад +2

    I can't comprehend clearly 'cause the first variable 0 is not on the critical line.

    • @HL-iw1du
      @HL-iw1du 4 года назад +1

      I think this video has the real part of the input of the zeta function fixed at 1/2 and the imaginary part of the input increasing as time goes on. The video displays both the real part and the imaginary part of the output of the function corresponding to the input at any given time.

  • @ffhashimi
    @ffhashimi 8 лет назад +8

    This is really amazing; and it's very useful
    ..I can't understand the process from the script so I have some questions :
    I understood from your post that you add time as variable to the 1/2+yi
    1- why did you start with value 1.460..
    2- did that mean you used the first 200 zita zeros?
    will you explain more how did you create this great animation?
    and thanks for this animation

    • @MarkusShepherd
      @MarkusShepherd  8 лет назад +4

      The script essentially calculates the values of zeta for 1/2+0i, 1/2+0.1i, 1/2+0.2i, ..., 1/2+14i, ..., 1/2+200i. At each time step this new value will be plotted while the old values "fade". Hope that helps!

  • @rayubinger9780
    @rayubinger9780 Год назад

    Seen these loops before but nobody explains how they come from the RZ function.

    • @MarkusShepherd
      @MarkusShepherd  Год назад +1

      Does this article help? www.riemannhypothesis.info/2016/04/visualising-the-riemann-hypothesis/

    • @rayubinger9780
      @rayubinger9780 Год назад

      @@MarkusShepherd Yes, thanks!
      "These are the values of \zeta(s)ζ(s) as ss goes up the critical line s=\frac12+tis=21​+ti. We start at1 t=0t=0 at the beginning of the video and go all the way up to t=200t=200. \zeta(1/2)\approx-1.4603545\ldotsζ(1/2)≈−1.4603545…, so this is where the values start."
      Perfectly clear now! But now, unsure why bother? We already know the critical line has an infinitude of zeroes.

  • @drakanDS
    @drakanDS 2 года назад

    music?

  • @RSLT
    @RSLT 2 года назад +2

    Beautiful!

  • @someguy4003
    @someguy4003 3 года назад +3

    Beautiful

  • @Meuszik
    @Meuszik 8 лет назад +1

    how did you create an animation like this?

    • @MarkusShepherd
      @MarkusShepherd  8 лет назад +2

      Sage. I wrote a few comments on the video here: www.riemannhypothesis.info/2016/04/visualising-the-riemann-hypothesis/ it also has a link to the script :-)

  • @paulthompson9668
    @paulthompson9668 7 лет назад

    Markus, watching the spiral makes me sick to my stomach. There's just something gross about it, like playing poker with people who don't know how to fold, and ending up losing every once in a while to hands that no one in their right minds would play after a high pre-flop bet.

    • @MarkusShepherd
      @MarkusShepherd  7 лет назад +3

      Paul Thompson you're welcome!

    • @paulthompson9668
      @paulthompson9668 7 лет назад

      Haha Markus. Now I wonder if it would be possible for you to do an animation of the Riemann Zeta function as the values go up all the lines (simultaneously) between 0 and 1. Would we see an interesting paintbrush- like spiral, or would it be complete chaos?

    • @MarkusShepherd
      @MarkusShepherd  7 лет назад

      It would certainly be possible and probably not that difficult - I might try it one of these days, or you could try too if you want to get your hands dirty on the Sage code I posted here: www.riemannhypothesis.info/2016/04/visualising-the-riemann-hypothesis/
      Using "all the lines" would probably too much to see anything, but with the right selection I'm sure it'd be very interesting!

    • @paulthompson9668
      @paulthompson9668 7 лет назад

      I haven't programmed in Sage before. Is it possible to add comments to the code? If so, could you put in comments in the appropriate places to let me know where I would have to add code to make it do the animation I asked about? I imagine we would need a nested for-loop.

  • @stephankuerner315
    @stephankuerner315 7 лет назад +1

    I cracked it you lie completely wrong

    • @MarkusShepherd
      @MarkusShepherd  7 лет назад +2

      Sorry, what's there to crack and who is wrong where?

    • @MarkusShepherd
      @MarkusShepherd  7 лет назад

      Sure...

    • @stephankuerner315
      @stephankuerner315 7 лет назад

      Sure ... yes - the Dax or the Lotto can be easily calculated and this shows that it is fraud. Because it is to be proved by this - it can not be found (I believe)

    • @willyou2199
      @willyou2199 7 лет назад +7

      i dont think he knows what he's saying