Thank you so much for solving my puzzle! The way you approached the breakin was totally fascinating - you got the same results for the same reasons, but visualized it completely backwards from how I did. Very, very interesting to watch, and I'm so glad to see that you enjoyed it as much as I hoped!
I loved your puzzle - even though could not find the break-in and had to learn at the master's feet. After that, it was *still* great fun and a wonderful use of the no-repeat constraint of killer sudoku. Do you have particular preference in what sect you want to be beatified? 'Cos beatified you will be, no escape possible. Even if you retire to the summit of Everest, we will find you there and force you to share your magic with the rest of humanity.
One of my favorite quotes I’ve heard in recent time is “every dead body on Mount Everest was once a very motivated person, so maybe take it down a notch”.
Footsteps of redemption for this world if these setters and Sir Simark the Cracker can echo the song of the universe day in day out. Can I recommend 'The Universe Speaks in Numbers' (Graham Farmelo 2018), about the role of mathematics and number theory in fundamental physics?
I love this community so much! It’s so awesome that the setters are fans and that we have this lovely and supportive group of super talented folks! You all are the best and I’m glad this channel is here to bring it all together
Loved how Clover fooled us with the title, as its always more about getting down safely than reaching the summit. Great puzzle from a great setter with a lovely solve as always.
@@longwaytotipperary Touché, Tippy. I should explain that in the original the spoofed verse reads: כי לא על הלחם לבדו יחיה האדם כי על כל מוצא פי ה' יחיה האדם [For not on the bread by itself will the adam live, for on the totality of what comes forth from the mouth of the Erternal One will the adam live], where I have left the word usually rendered as 'man', untranslated. Hebrew has a different word for 'man' as the masculine of our species: איש ['ish'] and its feminine counterpart אשה [isha]. אדם [adam], the name of the guy in that garden, simply denotes 'human'. His partner חוה [Chavah, Eve] means 'lifegiver' and 'adam' can be read as 'aspiring to resemble'. While it is true that the verbs used with adam are always in the masculine, that is due to the double role that binary grammatical gender plays. Fun fact: some languages do not have such a thing, e.g. Hungarian. It does not necessarily express gender bias but it can be heard as such. On the flipside, I would not want to count being a native Hungarian speaker as an antidote against sexism or mysogyny. Ask a simple question, get a simple answer 🤣.
@@amoswittenbergsmusings I would never classify your answers as "simple." 😄 Some lead me to a dictionary, some to other forms of research. It so happens that I enjoy researching - so to me, your answers and comments are always a delight! I have many interests and at one time was intrigued by the Hebrew alphabet. So I recognize your profile icon as Aleph - the oneness of God. And corresponds to the "A" in English - right?
@@longwaytotipperary The A 'descends' from the aleph or alef but alef is not a vowel but a consonant. Hebrew and Arabic do not have letters for vowels. The sound of this consonant is the 'glottal stop', the sound of Australian or Cockney "goo'morning", a sudden *absence* of sound that replaces the 'd'. Its form, as apparent from my icon, is in three: the upper and lower elements are two copies of the letter 'yud', the later Greek iota. It is a consonant, too, and has the sound of an English 'y' or German 'j'. The diagonal is a letter as well, the 'vav', or English 'w'. Hebrew letters are also numbers and the number represented by alef is one, or One, His Oneness. The three constituent letters are twice 10 for the two letters yud and 6 for the letter vav, together 26 which is the numerical value of His ineffable name. I give this information as just information, nothing more. There is much much more to be said about the alef but this comment is already enough off-topic. My icon is very dear to me.
Watching Simon solve this: “Wow. Simon is genius.” Watching Simon solve this after watching Clover’s video explaining her setting and logic and solve path: “HOW DID SIMON NOT SEE THAT?!?!?”
I do think the best approach to conquering Everest is to start at the top. Brilliant puzzle, particularly the start which seemed to unfold like magic as if I weren't controlling what I did (started slightly differently to Simon). I can understand why other setters might be disconsolate at the sight of this.
Great puzzle, Clover, and great solve, Simon. It was interesting coming back to watch the video after solving the puzzle on my own since my break-in ended up taking a slightly different path. I looked at the 21 and 22 cages and looked for places where the cells of one cage saw a lot of the cells in the other cage. This let me determine that 7 had to go in either r1c3 or r2c3 and that 6 went in either r3c1 or r3c2. From there, I got that the 18 cage in Box 3 had to have two digits below 5, so 4 and 5 were the only ones that worked, giving me a 4-5-9 triple there. That left me with a 2-3-9 triple in the 14 cage in Box 7. So I ended up at the same point that you did, Simon, just with a different approach to the logic. I always enjoy puzzles where you can reach the same conclusion from a couple of different angles.
Great to set up the pieces on the board and play out your variant. Homework assignment: in what sense is your approach isomorphic to Simon's? I mean, this is like two different proofs of the same theorem. What is the essence of the theorem that enables both proofs?
It's a bit cliche to point out the missed obvious deductions, but I was a little amused that, after so often quoting REM recently, he missed that the 3 in the corner disambiguated the 2/3 in the 14 cage in box 7. Anyway, what a delightfully tough puzzle and a fun watch!
At this point I’m almost inclined to believe it’s on purpose. To see if he can get away with missing the obvious and work around it with some complicated logic to beat the puzzle anyway! It’s his brand now, and he owns it :) either way it’s fascinating to see such brilliant mind at work.
For some reason, even Clover's GAS puzzles trip me up so I'm always nervous to try a Clover puzzle but always excited to see Simon attempt one. Nice one.
Could you also arrange a video with one of the puzzle makers commenting on one of your videos, discussing if you took the intended paths and how they look at your way of solving. Might result in some interesting stuff.
Rules: 03:14 Let's Get Cracking: 03:48 What about this video's Top Tier Simarkisms?! Cooking with Gas: 2x (22:58, 23:02) Knowledge Bomb: 1x (18:54) And how about this video's Simarkisms?! Beautiful: 8x (21:02, 21:24, 22:43, 23:33, 32:12, 33:37, 36:51, 45:03) Sorry: 7x (19:09, 19:50, 26:47, 29:39, 34:47, 35:27, 43:11) By sudoku: 7x (10:09, 27:45, 29:56, 37:05, 39:01, 41:59, 43:41) Useless: 5x (04:47, 04:49, 05:22, 31:17, 33:16) Hang On: 5x (06:07, 06:07, 14:21, 15:24, 30:50) Approachable: 4x (13:36, 45:48, 45:51, 45:54) Goodness: 3x (14:18, 25:06, 28:59) Secret: 3x (04:06, 04:09, 38:36) Brilliant: 3x (00:27, 44:53, 46:08) Good Grief: 2x (16:11, 45:06) Clever: 2x (21:04, 36:53) Stuck: 2x (36:29, 43:46) What on Earth: 1x (34:28) Naked Single: 1x (40:47) Nonsense: 1x (16:52) Recalcitrant: 1x (38:57) Lovely: 1x (41:04) Break the Puzzle: 1x (16:50) Fascinating: 1x (01:13) Oh It Can!: 1x (38:34) Come on Simon: 1x (31:28) Surely: 1x (07:40) FAQ: Q1: What is a Simarkism? A1: A Simarkism is something that Simon and Mark typically or frequently say. Q2: How do you do this so fast? A2: I'm not made of flesh and blood, but of sand ... Q3: Why don't you include 'XX' and 'YY'? A3: Probably it's already on the list ('Scooby-Doo' for example), but not mentioned in this video. But if you think it's not, tell me what you'd like me to include and there's a good chance I'll add it! Q4: You missed 'XX' at 'YY:ZZ'! A4: That could very well be the case! Human speech is hard to understand for computers like me, especially British sometimes! Point out the ones that I missed and maybe I'll learn! Q5: Could you turn these statistics into videos? A5: I've been playing around with the idea and I'm open to input as to what people would like to see. Let me know if you are interested in this and/or have suggestions.
1:00:44 an exact hour solve 2 days in a row. I am happy i got it. the last 1/4 of the solve took me 1/2 of the time. I could have done it under 45 minutes if i kept my tempo.
19:00 there is an another way to disambiguate whether there is a repeated digit or not, if we look at the cells R1C3 and R2C3, they both see all the cells from another cage except for R4C2. So if both R1C3 and R2C3 have 1, 2, 3, 4 and 5 in them, then there can't be all 1-2-3-4-5 in the other cage, because two of these digits, which are R1C3 and R2C3, will both have to go in R4C2, so it breaks. Therefore the R1C3 and R2C3 pair has to contain both a 7 and the R4C2 cell whatever it is. The same logic applies to the R3C1 and R3C2 cells in relationship with the R2C4 cell, which again means that the R3C1 and R3C2 pair contains both a 6 and the R2C4 cell whatever it is. This gives us that both 6 and 7 are in box 1 so the digits of those two cages which aren't in box 1 have two be 1-2-3-4-5 in 6 cells, which gives us one repeated digit. 🙃
I have yet to watch Clover's video, but I agree with her comment here - I solved this completely differently to you! I used the clustering of digits in box 1 to deduce the triads in boxes 2 and 4, and then used Aad van der Wetering to conclude that R6C6 is a 1 and that the two remaining triads in boxes 2 and 4 must sum to 46. Your solution felt like a real back-door solution which was fascinating to see!
Wow! Great puzzle. Keeps you working right up to the finish. No way I could have solved this on my own. CTC's puzzle solving skills are amazing. And the setters (and puzzles) they showcase here are simply marvelous. Like Dirk says, "What a time to be alive!"
"I can't believe I don't have a digit," he says with the cell selected where he very easily could have a digit using logic he's already demonstrated...
It's Killer Sudoku Jim, but not as we know it. Disgusting? Perhaps not. But I got through it. So much logic to work out and it took me an age to work out what needed to be in those 7 cells surrounding box 9. Being daft didn't help - knocking out 2 as a possible in r6c6 got a lot easier when spotting the obvious 2 above it. An excellent evening. We're so fortunate here and Clover is pretty awesome. Such brilliant setting. The Japanese Sums are lots of fun too - barring the one that was originally impossible! 44 down, 1 to go. Thanks and congratulations to everyone who produced that pack.
Took me over an hour, and I needed 3 hints from Simon. Would not have gotten it on my own, or at least it would've taken me another hour or two and probably some bifurcation. I am pleased that I figured out the first box and the 189 on my own.
21:00 Indeed, the simpler way would be to look at the two halves of the two cages that *are* in box 1. Because then you know for a fact there are no repeated digits between them (being in the same box). That way, you can look at the effects on the 18 and 14 cages in isolation, and it's a lot simpler to understand what's going on. Looking at the 18 first: Because there are no repeated digits, this means that any digit in the top half of the 21 cage (except 6) goes in the right half of the 22 cage, and is therefore pushed into the 18 cage. Now, that means that two of the digits from 1-5 go into the 18, and the only way that's possible is if those are 4 and 5, and the 18 cage is 459. And also, the top half of the 21 cage has to be 456. Then, separately, you can do the same logic downwards, but 4 and 5 are already gone so you get 2 and 3, etc.
Another way to break into the puzzle would be noticing R3C1C2 and C3R1R2 cannot both be common digits, as it would force 2 digits in R4C2 and R2C4. This tremendously reduces the steps needed to force 2 common digits from both cages into the 18 and 14 cage, allowing you to greatly reduce the options in the first 2 cages.
I'm obsessed with Simon because he'll finish up saying something immensely clever and then, when you least expect it, he'll say something like "this cell is a bit sus" or "epic fail" and it ALWAYS catches me off guard its very funny
The way Simon ruled out 6 from R2C7 that lead him to 7-8 pairs in R3C7 and R3C8 was pretty decent, but there was another way. As we had a 2-3 pair in column 6, we could rule out those two digits from the same cells, as they were seen by cage and by sudoku. I mention this, because the same trick could be used to find 8 in R8C3 and Simon would have finished it slightly faster. For me it was 27:07 and I find it as a personal best solve ever. Amazing puzzle.
A slightly easier way to show that there has to be a repeat digit in the yellow regions: Consider the digits in r3c1 and r3c2, where can they go in the 22 cage? Only in r2c4, which means one of them is a 6. Similarly, one of r1c3 and r2c3 is a 7.
20:09 for me. This is probably the first time ever that I used more colors to solve a sudoku than Simon. You can get to the same logic for the break-in thinking of each cell in particular, which I found way easier. However, I have to admit that his way looks much better. Awesome puzzle!!
So I put this video on like 3 days ago, then I had to pause it some 15 minutes in. Cut to two days later, out of nowhere, *the algorithm* decides to suggest a video to me with Brian Blessed talking about a trip to Everest. I don't know why this miracle fell in my lap, but I'm glad it did. Cut today as I resume this video, now I understand.
Here's a little bit of logic Simon didn't find at the start. Once you've marked up the 6-cell 21- and 22-cages, you can actually narrow down the locations of the 6 and 7 to two cells each. Eg, look at the two cells (3,1) and (3,2). These both see five cells of the 22-cage, so if neither of these cells was a 6, then they'd both have to live in the remaining cell of the 22-cage, ie in (2,4). So in fact the 6 in the 21-cage lives in one of (3,1) or (3,2). Similarly, the 7 in the 22-cage is in one of (1,3) or (2,3). This then also has the effect of forcing there to be a repeated digit in Simon's yellow cells.
I have now finished the puzzle after yet more fabulous logic (the forcing of the 14 cage was a lovely idea). I would definitely suggest changing the title of the video: the puzzle is difficult in places but I think calling it ‘disgusting’ would just put people off, when in reality it is brilliant to solve. Maybe you could call it something like ‘there are many forces at work’ due to the fact it is called ‘Everest’ and involves forcing so many killer cages.
I'm watching this after watching Clover's reaction to it. I've never been so smug in my life. I keep saying "C'mon, it's easy. How can you not see this-and-that"
I just knew looking at the symmetry there was a more elegant solve path than what I slogged out. I deduced the 459 cage by noting that only 1 digit from the 22 cage can appear in r1c456 and the other two would have to be selected from 689. you can't make 18 in three cells without at least one of those digits which gives a virtual 689 triple in row one and eliminates them from r1c1. This gives an 89 pair in box 1. From there you use cage geometry to mark a few equivalences and conclude that 2 cells in the 18 cage must be from 1-5. The only way to make that is with 459 and you go from there.
It is fascinating to *see* Simon think, go over in his mind what he has found, formulating a way to express it and then give an exposition that is crystal clear, all within a few seconds. When he says "Hang on...", he already *knows* that he knows. The man is so incredibly gifted.
Okay, so the way I broke in here seems very different from Simon. The diagonal in box 1 has to have 89 on it. But so does one of r3c4-5 and one of c3r4-5, and so that has to be common (one of 1-5), which is now everything on the diagonal. r2c4 has to be in r3c1-2 and therefore (1) one of 1-5 and (2) in r1c7-9. The one of r3c4-5 that isn’t on the diagonal in box 1 is in r2c1, and therefore also (1) one of 1-5 and (2) in r1c7-9. So those must be 45, and from there it’s a little more straightforward.
Much simpler way of starting this is to see that 2 cells in box 1 of the 21-cage see all but one of the cells in the 22-cage, and vice versa. So the 6 and 7 must appear in box 1 in row 3 and column 3.
Took me longer because I can't keep the number combo possibilities of the boxes in my head so I have to calculate them out each time but I really liked this puzzle!
I am SO happy I was able to figure this one out for myself, with no help whatsoever!! 35:16 was my time. This is like a new level of sudoku euphoria...
Took about an hour to finish. The start of the puzzle went quickly (finding the 1,8,9 in the top-left box), but then I was stuck on the 14-cage in the middle box. I speculated it didn't contain a 1, but I couldn't manage to explain why not. So I continued the puzzle under the assumption that the cage contains 2,3,4,5 , and the puzzle solved nicely after it.
If you like stories about Mount Everest, I cannot recommend you enough "The summit of the gods", a manga series by Jiro Taniguchi . It is truly wonderful. I hope you will read it, if you haven't already.
There is an alternate break in to the 21 and 22 cages, they have one one different digit, a 6 and 7, r3c1 and r1c2 are either two repeated digits in the 22 cage or a 6 and one repeated digit. If the are both repeated digits, they would both have to go in r2c4, so one of them is the 6. The logic is the same for the 7 in r1c3 and r2c3. That makes the caged cells in box 2 and 4 be from 1,2,3,4,5. Box 1 outside the cages is 89 and one other digit, so there can only be that repeated digit in the 1,2,3,4,5. Only the 4,5 work in the 18 cage with the 9, so those must be the repeated digit in rows 2 and 3, then of the remaining, the 2,3 are the only ones that work in the 14 cage and must be repeated in columns 2 and 3, leaving the cages 1-2-3 in box 4 and 1-4-5 in box 2
so I saw the initial break in a little different. everything in the 21 cage other than the 6 has to appear 22 cage but r3c1 and r3c2 see the whole of the 22 cage other than r2c4. So they have to be 6 and the number in r2c4, and that number has to also appear in the top right 18 cage. r2c1 also now must be in the 22 so it has to be in either r3c4 or r3c5 and must also appear in the top right 18. Maxing them out gets you 459 in the 18. Apply the same logic vertically and you get the 239 in the 14 cage at the bottom left
I haven’t actually fully solved the puzzle yet but I feel that I have to mention this. I decided to explore the 21 and 22 cages after noticing the fact that some of the cells were restricted as to where they could go in the other cage (bearing in mind that there were exactly 5 shared digits, the numbers 1 to 5). It didn’t take me too long to realise that there was a domino in each cage (both in box 1) which was somehow forced into a single cell in the other cage!!! Of course, the only possibility was that exactly one digit in each domino was in both cages and the other was the non-repeated digit (a 6 in the 21 cage, a 7 in the 22). Therefore, all of the other digits in the cages had to be repeated, meaning that they had to go somewhere in both cages. Once I had coloured all of the cells in the two cages, I suddenly realised that exactly 2 of those colours (representing one of the digits 1 to 5) were forced into the 18 and 14 cages at the end of row 1 and column 1 and that this forced each cage in turn to be made up of the digits 4,5,9 and 2,3,9 respectively (since every colour represented a different digit). This is one of the most beautiful pieces of logic in a solve that I have ever come across. I am, of course, looking forward to the rest of the solve but I just wanted to first say thank you to Clover; as moments go that one was an absolute joy (and probably the nearest I have ever got to being as excited as Simon). :)
At least one of the R3C1 and R3C2 cells have to: a) exist in the other cage and b) be a "12345". The only position is R2C4. If both R3C1 and R3C2 are "12345", we have no cell to place both of them. So 6 lives there. The same is true for the domino R1C3 and R2C3. One of these exists at R4C2 and is "12345" and the other is 7. At this point, we know that all the cages' cells at boxes 2 and 4 are "12345" and it is easy to show that R2C1 lives in the domino R3C4, R3C5, and that R1C2 lives in the R4C3, R5C5 domino. So we have to place at least 2 digits of "12345" in the 14 and 18 cages of boxes 3 and 7. And the 18 cage gives us the 459 etc.
Interestingly, the conclusion that there must be a repeated digit in yellow is true even if you remove the 14 and 18 cages. You can get there just by carefully considering where the yellow cells go in box 1.
No maverick flying by today! Perhaps that's because Simon was too high up the mountain to hear Maverick's airplane far below, or anyway the amount of turbulence around the Everest's summit would be too dangerous for airplanes ;-)
I'm having incredible trouble imagining a viewer of the channel going "man simon is going too slow with these solves" especially since simon usually completes these puzzles far faster than the average time for the test solvers
Does the software check against standard sudoku rules? Or against the actual solution? I made a mistake somewhere along the line. Ended up having to retrace my steps with the 33 cage in bottom left. Totally forgot about not repeating digits within cages. Software told me I was right, after filling in the puzzle. I immediately noticed two 8s in the 33 cage. Pulled the video up to check against Simon, and found that C4, C5, and C6 had all kinds of transposed digits in them. (From me doing something dumb with the 2-3, 6-7, 7-8, 8-6 pairs.) But still, "Looks good to me" prompt when I entered the last digit. I guess the software checks against standard rules and not the actual solution?
I don't think I've ever said this in relation to a 'Clover' puzzle ... too tough for me. I tried using SET, and in particular using the same 'Aard' trick that succeeded for me the other puzzle with another puzzle, but I got nowhere. It *never* occurred to me to use the cages contained entirely in boxes 3 and 7, in conjunction with the 21- and 22-cages. I watched up to the 15:08 point of the video, and was able to solve it from there. Incredible puzzle ... but yes, too clever for me.
I approached the conclusion on the 12345 at the start differently than Simon did. Question, how many of the digits in the yellow in b2 can be in the cages in b1? Exactly 2 of them, for if 3 of them did, then one digit would be repeating twice in a row. How many of the digits in the yellow in b4 can be in the cages in b1? Exactly 2 of them, for if 3 of them did, then one digit would be repeating twice in a column. If you add these together, you have 4 digits in the yellow appearing in the cages in b1. So where does the 5th digit appear? It must necessarily be located in both yellow sections. Then, you can go into what digits can be in the 18 and the 14 cages, knowing that they cannot repeat in these cages. 459 must go into the 18 cage, and so 4 and 5 are removed from the options in the 14 cage, which must then be 239. I think clover should have entirely flipped this grid, because the descent from Everest is supposed to be the easy part, after the hard part of climbing it. This puzzle is a struggle going down, until you get to the point where you are going back up. With a puzzle named Everest, I expected to start at the bottom of the grid, but here we're supposed to start at the opposite side of the grid. With the way the puzzle is right now, it would be more appropriate to call it "Descending into Madness" than "Everest".
So, in solving this, I found another solution that keeps the rules of Sudoku, but fails the totaling requirement; naturally the "Looks good to me" popped up. I was genuinely surprised when you came up with another solution. The system doesn't seem to check the additional rules... ...good to know!
> The "Disgusting" Sudoku! Look! There's some kind of mold around this five! And here: somebody has scattered barber hair and mayonnaise all along row seven!
It's a mystery.... very few people know what it is..... Some even guard the knowledge of this number... To become a guardian of this number you are sworn to.... secrecy
After watching the video, I'm kinda surprised the way you factored out 6 and 7 out of the 21 and 22 cages. Way I look at was through coloring of cells, and finding that each of R3C1/R3C2 and R1C3/R2C3 were cells fighting to go into R2C4 or R4C2. Then a lot of coloring was used to find the rest of the placements.
At 43:20 he drags his mouse along row 8 from the 1-2 cell in the ten cage to the already set 1 in box 8, and I'm like "finally he saw it" and then he didn't see it.
Im always surprised how easy simon makes sudokus look his iq must be so high id love to see him finish a puzzler magazine from start to finish on a video. Also he is such a softly well spoken man love CTC videos been watching for a few years
Thank you so much for solving my puzzle! The way you approached the breakin was totally fascinating - you got the same results for the same reasons, but visualized it completely backwards from how I did. Very, very interesting to watch, and I'm so glad to see that you enjoyed it as much as I hoped!
Wonderful!
I loved your puzzle - even though could not find the break-in and had to learn at the master's feet. After that, it was *still* great fun and a wonderful use of the no-repeat constraint of killer sudoku. Do you have particular preference in what sect you want to be beatified? 'Cos beatified you will be, no escape possible. Even if you retire to the summit of Everest, we will find you there and force you to share your magic with the rest of humanity.
Sorry Bill for the downtick, fat fingers.
Thank you, Clover! Beautiful, elegant setting! And surprisingly more approachable than I had expected! :-D
Thank you for an amazing puzzle!
One of my favorite quotes I’ve heard in recent time is “every dead body on Mount Everest was once a very motivated person, so maybe take it down a notch”.
CTC is truly a RUclips hidden gem. I have started sudoku during my break at work now. Always excited for the next livestream too!
Another one of the worlds best sudoku puzzles by an exceptionally good setter. Like every day on Cracking the Cryptic. What a time to be alive!
Accurate.
Footsteps of redemption for this world if these setters and Sir Simark the Cracker can echo the song of the universe day in day out. Can I recommend 'The Universe Speaks in Numbers' (Graham Farmelo 2018), about the role of mathematics and number theory in fundamental physics?
Well I get to watch this with no qualm having scaled this mountain already. The view up here is breathtaking!
This is the Brian Blessed clip referred to. Strong language.
ruclips.net/video/jwuw6Z33018/видео.html
I love this community so much! It’s so awesome that the setters are fans and that we have this lovely and supportive group of super talented folks! You all are the best and I’m glad this channel is here to bring it all together
Loved how Clover fooled us with the title, as its always more about getting down safely than reaching the summit. Great puzzle from a great setter with a lovely solve as always.
On a gloomy day and processing some gloomy news, watching Simon and hearing his contagious laugh gave me respite for a little while. Thank you.
Oh no, Tippy. Hang in there. Maybe some soul music? 'Man shall not live by puzzles alone.'
@@amoswittenbergsmusings Thank you, Amos. So that goes for women too, huh?
@@longwaytotipperary Touché, Tippy. I should explain that in the original the spoofed verse reads: כי לא על הלחם לבדו יחיה האדם כי על כל מוצא פי ה' יחיה האדם [For not on the bread by itself will the adam live, for on the totality of what comes forth from the mouth of the Erternal One will the adam live], where I have left the word usually rendered as 'man', untranslated.
Hebrew has a different word for 'man' as the masculine of our species: איש ['ish'] and its feminine counterpart אשה [isha]. אדם [adam], the name of the guy in that garden, simply denotes 'human'. His partner חוה [Chavah, Eve] means 'lifegiver' and 'adam' can be read as 'aspiring to resemble'.
While it is true that the verbs used with adam are always in the masculine, that is due to the double role that binary grammatical gender plays. Fun fact: some languages do not have such a thing, e.g. Hungarian. It does not necessarily express gender bias but it can be heard as such. On the flipside, I would not want to count being a native Hungarian speaker as an antidote against sexism or mysogyny.
Ask a simple question, get a simple answer 🤣.
@@amoswittenbergsmusings I would never classify your answers as "simple." 😄 Some lead me to a dictionary, some to other forms of research. It so happens that I enjoy researching - so to me, your answers and comments are always a delight! I have many interests and at one time was intrigued by the Hebrew alphabet. So I recognize your profile icon as Aleph - the oneness of God. And corresponds to the "A" in English - right?
@@longwaytotipperary The A 'descends' from the aleph or alef but alef is not a vowel but a consonant. Hebrew and Arabic do not have letters for vowels. The sound of this consonant is the 'glottal stop', the sound of Australian or Cockney "goo'morning", a sudden *absence* of sound that replaces the 'd'.
Its form, as apparent from my icon, is in three: the upper and lower elements are two copies of the letter 'yud', the later Greek iota. It is a consonant, too, and has the sound of an English 'y' or German 'j'. The diagonal is a letter as well, the 'vav', or English 'w'. Hebrew letters are also numbers and the number represented by alef is one, or One, His Oneness. The three constituent letters are twice 10 for the two letters yud and 6 for the letter vav, together 26 which is the numerical value of His ineffable name. I give this information as just information, nothing more. There is much much more to be said about the alef but this comment is already enough off-topic.
My icon is very dear to me.
Watching Simon solve this: “Wow. Simon is genius.”
Watching Simon solve this after watching Clover’s video explaining her setting and logic and solve path: “HOW DID SIMON NOT SEE THAT?!?!?”
Clover, is, one of the greatest setters in the world. Clearly this is going to be a phenomenal video.
I do think the best approach to conquering Everest is to start at the top.
Brilliant puzzle, particularly the start which seemed to unfold like magic as if I weren't controlling what I did (started slightly differently to Simon). I can understand why other setters might be disconsolate at the sight of this.
Great puzzle, Clover, and great solve, Simon. It was interesting coming back to watch the video after solving the puzzle on my own since my break-in ended up taking a slightly different path. I looked at the 21 and 22 cages and looked for places where the cells of one cage saw a lot of the cells in the other cage. This let me determine that 7 had to go in either r1c3 or r2c3 and that 6 went in either r3c1 or r3c2. From there, I got that the 18 cage in Box 3 had to have two digits below 5, so 4 and 5 were the only ones that worked, giving me a 4-5-9 triple there. That left me with a 2-3-9 triple in the 14 cage in Box 7. So I ended up at the same point that you did, Simon, just with a different approach to the logic. I always enjoy puzzles where you can reach the same conclusion from a couple of different angles.
That’s exactly the same way I did it! :-D
Ruling a 1 out of the 14 cage in the center box was the next important trick. It was fairly smooth sailing after that. :-D
Great to set up the pieces on the board and play out your variant.
Homework assignment: in what sense is your approach isomorphic to Simon's? I mean, this is like two different proofs of the same theorem. What is the essence of the theorem that enables both proofs?
Simon telling us the very special secret in such a coy manner is the most wonderful thing in all of RUclips and I hope it never ends.
It's a bit cliche to point out the missed obvious deductions, but I was a little amused that, after so often quoting REM recently, he missed that the 3 in the corner disambiguated the 2/3 in the 14 cage in box 7. Anyway, what a delightfully tough puzzle and a fun watch!
At this point I’m almost inclined to believe it’s on purpose. To see if he can get away with missing the obvious and work around it with some complicated logic to beat the puzzle anyway! It’s his brand now, and he owns it :) either way it’s fascinating to see such brilliant mind at work.
@@DirkieB Yep, even I was shouting "there's a 3 in the corner" and i'm a rank amateur at Sudoku.
For some reason, even Clover's GAS puzzles trip me up so I'm always nervous to try a Clover puzzle but always excited to see Simon attempt one. Nice one.
Could you also arrange a video with one of the puzzle makers commenting on one of your videos, discussing if you took the intended paths and how they look at your way of solving. Might result in some interesting stuff.
Rules: 03:14
Let's Get Cracking: 03:48
What about this video's Top Tier Simarkisms?!
Cooking with Gas: 2x (22:58, 23:02)
Knowledge Bomb: 1x (18:54)
And how about this video's Simarkisms?!
Beautiful: 8x (21:02, 21:24, 22:43, 23:33, 32:12, 33:37, 36:51, 45:03)
Sorry: 7x (19:09, 19:50, 26:47, 29:39, 34:47, 35:27, 43:11)
By sudoku: 7x (10:09, 27:45, 29:56, 37:05, 39:01, 41:59, 43:41)
Useless: 5x (04:47, 04:49, 05:22, 31:17, 33:16)
Hang On: 5x (06:07, 06:07, 14:21, 15:24, 30:50)
Approachable: 4x (13:36, 45:48, 45:51, 45:54)
Goodness: 3x (14:18, 25:06, 28:59)
Secret: 3x (04:06, 04:09, 38:36)
Brilliant: 3x (00:27, 44:53, 46:08)
Good Grief: 2x (16:11, 45:06)
Clever: 2x (21:04, 36:53)
Stuck: 2x (36:29, 43:46)
What on Earth: 1x (34:28)
Naked Single: 1x (40:47)
Nonsense: 1x (16:52)
Recalcitrant: 1x (38:57)
Lovely: 1x (41:04)
Break the Puzzle: 1x (16:50)
Fascinating: 1x (01:13)
Oh It Can!: 1x (38:34)
Come on Simon: 1x (31:28)
Surely: 1x (07:40)
FAQ:
Q1: What is a Simarkism?
A1: A Simarkism is something that Simon and Mark typically or frequently say.
Q2: How do you do this so fast?
A2: I'm not made of flesh and blood, but of sand ...
Q3: Why don't you include 'XX' and 'YY'?
A3: Probably it's already on the list ('Scooby-Doo' for example), but not mentioned in this video. But if you think it's not, tell me what you'd like me to include and there's a good chance I'll add it!
Q4: You missed 'XX' at 'YY:ZZ'!
A4: That could very well be the case! Human speech is hard to understand for computers like me, especially British sometimes! Point out the ones that I missed and maybe I'll learn!
Q5: Could you turn these statistics into videos?
A5: I've been playing around with the idea and I'm open to input as to what people would like to see. Let me know if you are interested in this and/or have suggestions.
Mountain climbers have a saying - going up is optional, but getting down is mandatory.
Well done!
1:00:44 an exact hour solve 2 days in a row. I am happy i got it. the last 1/4 of the solve took me 1/2 of the time. I could have done it under 45 minutes if i kept my tempo.
19:00 there is an another way to disambiguate whether there is a repeated digit or not, if we look at the cells R1C3 and R2C3, they both see all the cells from another cage except for R4C2. So if both R1C3 and R2C3 have 1, 2, 3, 4 and 5 in them, then there can't be all 1-2-3-4-5 in the other cage, because two of these digits, which are R1C3 and R2C3, will both have to go in R4C2, so it breaks. Therefore the R1C3 and R2C3 pair has to contain both a 7 and the R4C2 cell whatever it is. The same logic applies to the R3C1 and R3C2 cells in relationship with the R2C4 cell, which again means that the R3C1 and R3C2 pair contains both a 6 and the R2C4 cell whatever it is. This gives us that both 6 and 7 are in box 1 so the digits of those two cages which aren't in box 1 have two be 1-2-3-4-5 in 6 cells, which gives us one repeated digit. 🙃
Came here to say the same thing. That's how I got started, and I think it's a bit easier to visualize.
I think it’s no wonder that “Clover” sounds like “clever.” She certainly is. Great setting and great solving, well done.
I can't help but refer to her as 'Clover the Clever' ... a half-decade of watching MLP with my daughter conditioned me.
I have yet to watch Clover's video, but I agree with her comment here - I solved this completely differently to you! I used the clustering of digits in box 1 to deduce the triads in boxes 2 and 4, and then used Aad van der Wetering to conclude that R6C6 is a 1 and that the two remaining triads in boxes 2 and 4 must sum to 46. Your solution felt like a real back-door solution which was fascinating to see!
Wow! Great puzzle. Keeps you working right up to the finish. No way I could have solved this on my own. CTC's puzzle solving skills are amazing. And the setters (and puzzles) they showcase here are simply marvelous. Like Dirk says, "What a time to be alive!"
Lovely stuff. My daily dose of puzzling. Cheers Simon 👍
Such a beautifully constructed puzzle! Lovely to see.
"I can't believe I don't have a digit," he says with the cell selected where he very easily could have a digit using logic he's already demonstrated...
The geometry is so lovely.
That was great. Took me 17 minutes, apparently. Although I did forget to restart the clock for over an hour!
It's Killer Sudoku Jim, but not as we know it.
Disgusting? Perhaps not. But I got through it. So much logic to work out and it took me an age to work out what needed to be in those 7 cells surrounding box 9. Being daft didn't help - knocking out 2 as a possible in r6c6 got a lot easier when spotting the obvious 2 above it. An excellent evening. We're so fortunate here and Clover is pretty awesome. Such brilliant setting.
The Japanese Sums are lots of fun too - barring the one that was originally impossible! 44 down, 1 to go. Thanks and congratulations to everyone who produced that pack.
Took me over an hour, and I needed 3 hints from Simon. Would not have gotten it on my own, or at least it would've taken me another hour or two and probably some bifurcation. I am pleased that I figured out the first box and the 189 on my own.
21:00 Indeed, the simpler way would be to look at the two halves of the two cages that *are* in box 1. Because then you know for a fact there are no repeated digits between them (being in the same box).
That way, you can look at the effects on the 18 and 14 cages in isolation, and it's a lot simpler to understand what's going on.
Looking at the 18 first:
Because there are no repeated digits, this means that any digit in the top half of the 21 cage (except 6) goes in the right half of the 22 cage, and is therefore pushed into the 18 cage.
Now, that means that two of the digits from 1-5 go into the 18, and the only way that's possible is if those are 4 and 5, and the 18 cage is 459. And also, the top half of the 21 cage has to be 456.
Then, separately, you can do the same logic downwards, but 4 and 5 are already gone so you get 2 and 3, etc.
Exactly how I did it.
Same.
No idea why Simon made it so complicated.
[Edit: Removed a claim Simon hadn't shown there was at least one repeated digit. I was wrong. He had]
Another way to break into the puzzle would be noticing R3C1C2 and C3R1R2 cannot both be common digits, as it would force 2 digits in R4C2 and R2C4. This tremendously reduces the steps needed to force 2 common digits from both cages into the 18 and 14 cage, allowing you to greatly reduce the options in the first 2 cages.
I found myself shouting 10 cage a lot. Simon's genius again never ceases to amaze.
I'm obsessed with Simon because he'll finish up saying something immensely clever and then, when you least expect it, he'll say something like "this cell is a bit sus" or "epic fail" and it ALWAYS catches me off guard its very funny
Another lovely day with another gorgeous puzzle? Yes please.
The way Simon ruled out 6 from R2C7 that lead him to 7-8 pairs in R3C7 and R3C8 was pretty decent, but there was another way. As we had a 2-3 pair in column 6, we could rule out those two digits from the same cells, as they were seen by cage and by sudoku.
I mention this, because the same trick could be used to find 8 in R8C3 and Simon would have finished it slightly faster.
For me it was 27:07 and I find it as a personal best solve ever. Amazing puzzle.
A slightly easier way to show that there has to be a repeat digit in the yellow regions: Consider the digits in r3c1 and r3c2, where can they go in the 22 cage? Only in r2c4, which means one of them is a 6. Similarly, one of r1c3 and r2c3 is a 7.
20:09 for me. This is probably the first time ever that I used more colors to solve a sudoku than Simon. You can get to the same logic for the break-in thinking of each cell in particular, which I found way easier. However, I have to admit that his way looks much better. Awesome puzzle!!
Three in the corner, three in the spotlight, yet still it gets ignored.
The absence of song was noted.
A disquieting incident. We must ensure that lessons are learned. Elsewhere I have elaborated.
So I put this video on like 3 days ago, then I had to pause it some 15 minutes in. Cut to two days later, out of nowhere, *the algorithm* decides to suggest a video to me with Brian Blessed talking about a trip to Everest. I don't know why this miracle fell in my lap, but I'm glad it did. Cut today as I resume this video, now I understand.
Here's a little bit of logic Simon didn't find at the start. Once you've marked up the 6-cell 21- and 22-cages, you can actually narrow down the locations of the 6 and 7 to two cells each. Eg, look at the two cells (3,1) and (3,2). These both see five cells of the 22-cage, so if neither of these cells was a 6, then they'd both have to live in the remaining cell of the 22-cage, ie in (2,4). So in fact the 6 in the 21-cage lives in one of (3,1) or (3,2). Similarly, the 7 in the 22-cage is in one of (1,3) or (2,3). This then also has the effect of forcing there to be a repeated digit in Simon's yellow cells.
I have now finished the puzzle after yet more fabulous logic (the forcing of the 14 cage was a lovely idea). I would definitely suggest changing the title of the video: the puzzle is difficult in places but I think calling it ‘disgusting’ would just put people off, when in reality it is brilliant to solve. Maybe you could call it something like ‘there are many forces at work’ due to the fact it is called ‘Everest’ and involves forcing so many killer cages.
Why is the puzzle called Everest? Why, because it was there!
42:57…. If only Simon had his favorite song playing in his head… “that’s 3 in the corner…”😃
I was literally thinking the exact same thing at that moment! 😁
38:40 I was so sad he didn't say it at that point 😥
And when he didn't use it to resolve the 23 pair in the 18 cage in box 7, I was literally shouting - " Simon there's a 3 in the corner!)
I'm watching this after watching Clover's reaction to it. I've never been so smug in my life. I keep saying "C'mon, it's easy. How can you not see this-and-that"
38:31 solved for me. This is another masterpiece. Absolutely brilliant puzzle!
Wow, huge respect!!
This puzzle receives the glum_hippo seal of approval, which has been specifically created to commemorate this puzzle.
Surely it's a hippo of approval?
I just knew looking at the symmetry there was a more elegant solve path than what I slogged out. I deduced the 459 cage by noting that only 1 digit from the 22 cage can appear in r1c456 and the other two would have to be selected from 689. you can't make 18 in three cells without at least one of those digits which gives a virtual 689 triple in row one and eliminates them from r1c1. This gives an 89 pair in box 1. From there you use cage geometry to mark a few equivalences and conclude that 2 cells in the 18 cage must be from 1-5. The only way to make that is with 459 and you go from there.
I like the slight hesitation when he is saying "brilliant" while he is checking if it validates. lol
It is fascinating to *see* Simon think, go over in his mind what he has found, formulating a way to express it and then give an exposition that is crystal clear, all within a few seconds. When he says "Hang on...", he already *knows* that he knows. The man is so incredibly gifted.
What a cool break-in! Really neat correlations. 38:44
Okay, so the way I broke in here seems very different from Simon. The diagonal in box 1 has to have 89 on it. But so does one of r3c4-5 and one of c3r4-5, and so that has to be common (one of 1-5), which is now everything on the diagonal. r2c4 has to be in r3c1-2 and therefore (1) one of 1-5 and (2) in r1c7-9. The one of r3c4-5 that isn’t on the diagonal in box 1 is in r2c1, and therefore also (1) one of 1-5 and (2) in r1c7-9. So those must be 45, and from there it’s a little more straightforward.
Much simpler way of starting this is to see that 2 cells in box 1 of the 21-cage see all but one of the cells in the 22-cage, and vice versa. So the 6 and 7 must appear in box 1 in row 3 and column 3.
That's what I saw after a few minutes. I kept waiting for Simon to think about the box 1 digits and start colouring
Took me longer because I can't keep the number combo possibilities of the boxes in my head so I have to calculate them out each time but I really liked this puzzle!
We all love clover! X
Beautiful, elegant setting! And surprisingly more approachable than I had expected! :-D
I am SO happy I was able to figure this one out for myself, with no help whatsoever!! 35:16 was my time. This is like a new level of sudoku euphoria...
Took about an hour to finish.
The start of the puzzle went quickly (finding the 1,8,9 in the top-left box), but then I was stuck on the 14-cage in the middle box. I speculated it didn't contain a 1, but I couldn't manage to explain why not. So I continued the puzzle under the assumption that the cage contains 2,3,4,5 , and the puzzle solved nicely after it.
21:10 That's wrong because we love watching your videos even if it's long or if you struggle.
Really enjoyed this one, thanks clover!
Fun fact - prior to the 2020 lockdown, the last year that passed in which no climbers died on Mount Everest was 1977.
Simon’s knowledge of Mt Everest’s geography interests me.
*saw the video length and puzzle setter*
Ah yes, this will be a gooooooood one
If you like stories about Mount Everest, I cannot recommend you enough "The summit of the gods", a manga series by Jiro Taniguchi . It is truly wonderful. I hope you will read it, if you haven't already.
There is an alternate break in to the 21 and 22 cages, they have one one different digit, a 6 and 7, r3c1 and r1c2 are either two repeated digits in the 22 cage or a 6 and one repeated digit. If the are both repeated digits, they would both have to go in r2c4, so one of them is the 6. The logic is the same for the 7 in r1c3 and r2c3. That makes the caged cells in box 2 and 4 be from 1,2,3,4,5. Box 1 outside the cages is 89 and one other digit, so there can only be that repeated digit in the 1,2,3,4,5. Only the 4,5 work in the 18 cage with the 9, so those must be the repeated digit in rows 2 and 3, then of the remaining, the 2,3 are the only ones that work in the 14 cage and must be repeated in columns 2 and 3, leaving the cages 1-2-3 in box 4 and 1-4-5 in box 2
so I saw the initial break in a little different. everything in the 21 cage other than the 6 has to appear 22 cage but r3c1 and r3c2 see the whole of the 22 cage other than r2c4. So they have to be 6 and the number in r2c4, and that number has to also appear in the top right 18 cage. r2c1 also now must be in the 22 so it has to be in either r3c4 or r3c5 and must also appear in the top right 18. Maxing them out gets you 459 in the 18. Apply the same logic vertically and you get the 239 in the 14 cage at the bottom left
Everyone gangsta until Simon goes "Oh, hang on a minute..."
I just love how Simon does it.
I'll never get tired of seeing Simon move his mouse over a digit that disambiguates other pencil marked cells only for him to go "ohhh NO" lmao
I haven’t actually fully solved the puzzle yet but I feel that I have to mention this. I decided to explore the 21 and 22 cages after noticing the fact that some of the cells were restricted as to where they could go in the other cage (bearing in mind that there were exactly 5 shared digits, the numbers 1 to 5). It didn’t take me too long to realise that there was a domino in each cage (both in box 1) which was somehow forced into a single cell in the other cage!!! Of course, the only possibility was that exactly one digit in each domino was in both cages and the other was the non-repeated digit (a 6 in the 21 cage, a 7 in the 22). Therefore, all of the other digits in the cages had to be repeated, meaning that they had to go somewhere in both cages. Once I had coloured all of the cells in the two cages, I suddenly realised that exactly 2 of those colours (representing one of the digits 1 to 5) were forced into the 18 and 14 cages at the end of row 1 and column 1 and that this forced each cage in turn to be made up of the digits 4,5,9 and 2,3,9 respectively (since every colour represented a different digit). This is one of the most beautiful pieces of logic in a solve that I have ever come across. I am, of course, looking forward to the rest of the solve but I just wanted to first say thank you to Clover; as moments go that one was an absolute joy (and probably the nearest I have ever got to being as excited as Simon). :)
At least one of the R3C1 and R3C2 cells have to: a) exist in the other cage and b) be a "12345". The only position is R2C4. If both R3C1 and R3C2 are "12345", we have no cell to place both of them. So 6 lives there. The same is true for the domino R1C3 and R2C3. One of these exists at R4C2 and is "12345" and the other is 7. At this point, we know that all the cages' cells at boxes 2 and 4 are "12345" and it is easy to show that R2C1 lives in the domino R3C4, R3C5, and that R1C2 lives in the R4C3, R5C5 domino. So we have to place at least 2 digits of "12345" in the 14 and 18 cages of boxes 3 and 7. And the 18 cage gives us the 459 etc.
Aww I feel so special lol. ☺ I'm one of the few Simon tells the secret too. 😁
Interestingly, the conclusion that there must be a repeated digit in yellow is true even if you remove the 14 and 18 cages. You can get there just by carefully considering where the yellow cells go in box 1.
No maverick flying by today! Perhaps that's because Simon was too high up the mountain to hear Maverick's airplane far below, or anyway the amount of turbulence around the Everest's summit would be too dangerous for airplanes ;-)
I'm having incredible trouble imagining a viewer of the channel going "man simon is going too slow with these solves" especially since simon usually completes these puzzles far faster than the average time for the test solvers
Does the software check against standard sudoku rules? Or against the actual solution?
I made a mistake somewhere along the line. Ended up having to retrace my steps with the 33 cage in bottom left. Totally forgot about not repeating digits within cages.
Software told me I was right, after filling in the puzzle.
I immediately noticed two 8s in the 33 cage. Pulled the video up to check against Simon, and found that C4, C5, and C6 had all kinds of transposed digits in them. (From me doing something dumb with the 2-3, 6-7, 7-8, 8-6 pairs.)
But still, "Looks good to me" prompt when I entered the last digit.
I guess the software checks against standard rules and not the actual solution?
So, I just noticed that this is 5 months old. It showed up in my notifications today. ....Whatever.
I don't think I've ever said this in relation to a 'Clover' puzzle ... too tough for me.
I tried using SET, and in particular using the same 'Aard' trick that succeeded for me the other puzzle with another puzzle, but I got nowhere. It *never* occurred to me to use the cages contained entirely in boxes 3 and 7, in conjunction with the 21- and 22-cages. I watched up to the 15:08 point of the video, and was able to solve it from there.
Incredible puzzle ... but yes, too clever for me.
I approached the conclusion on the 12345 at the start differently than Simon did. Question, how many of the digits in the yellow in b2 can be in the cages in b1? Exactly 2 of them, for if 3 of them did, then one digit would be repeating twice in a row. How many of the digits in the yellow in b4 can be in the cages in b1? Exactly 2 of them, for if 3 of them did, then one digit would be repeating twice in a column. If you add these together, you have 4 digits in the yellow appearing in the cages in b1. So where does the 5th digit appear? It must necessarily be located in both yellow sections. Then, you can go into what digits can be in the 18 and the 14 cages, knowing that they cannot repeat in these cages. 459 must go into the 18 cage, and so 4 and 5 are removed from the options in the 14 cage, which must then be 239. I think clover should have entirely flipped this grid, because the descent from Everest is supposed to be the easy part, after the hard part of climbing it. This puzzle is a struggle going down, until you get to the point where you are going back up. With a puzzle named Everest, I expected to start at the bottom of the grid, but here we're supposed to start at the opposite side of the grid. With the way the puzzle is right now, it would be more appropriate to call it "Descending into Madness" than "Everest".
Took me over an hour, and I couldn't fully get it on my own, but I did get through it.
So, in solving this, I found another solution that keeps the rules of Sudoku, but fails the totaling requirement; naturally the "Looks good to me" popped up. I was genuinely surprised when you came up with another solution. The system doesn't seem to check the additional rules...
...good to know!
> The "Disgusting" Sudoku!
Look! There's some kind of mold around this five! And here: somebody has scattered barber hair and mayonnaise all along row seven!
Highest praise to clover for this one. If you didn't solve it yet, TRY IT!
Jeez. I used Ard to work out that the two nines had to be in the centre of box 2 and box 4, and r6c6 was maxed at 3. Was quite some different path
Love seeing Simon do some very hard trick when there's a simple way he doesn't see. Like remembering "3 in the corner".
Makes me fill special. 😂😂😂
And it just dawned on me why these have been an hour late this week...
Good morning! 😎
nodlesh bom from quaking teh crypt: yu cannon put a seventree in a single soduku sell.
I'm watching the video while there's firework outside. Have a good night, y'all!
Huh??? Every number in a row, column or a box add up to 45? Why nobody told me this secret...!
Or ..were you not listening? 🤪
If you rotate the puzzle 45 degrees clockwise, it does look like a mountain..
What a lovely break-in.
1 , 3 , 6 , 10 , 15 , 21 , 28, 36, ?? , 55 , 66
I can never remember the triangular number between 36 and 55. It rarely comes up.
It's a mystery.... very few people know what it is..... Some even guard the knowledge of this number... To become a guardian of this number you are sworn to.... secrecy
@@Jonnysh the Answer + 3 ?
The first rule of Sudoku club is you don't talk about ??.
@@voorth it's the answer + 3 (in the corner)
Triangular numbers greater than 45 exist? Nope, have no use for those around here. 🙂
Googled the Everest story and now it is my favorite story as well. 🤣
Found it 😲
couldnt find it, what are the magic words to google for?
@@PjotrV Allan McRae has the link further down in the comments.
46:16 time. Was not wanting to go looking for set, but it just had to rear its head in.
After watching the video, I'm kinda surprised the way you factored out 6 and 7 out of the 21 and 22 cages.
Way I look at was through coloring of cells, and finding that each of R3C1/R3C2 and R1C3/R2C3 were cells fighting to go into R2C4 or R4C2. Then a lot of coloring was used to find the rest of the placements.
First time I've found the breakin faster than Simon, of course then I immediately got stuck and had to get Simons help for the remainder..
Looking Forward to this!
At 43:20 he drags his mouse along row 8 from the 1-2 cell in the ten cage to the already set 1 in box 8, and I'm like "finally he saw it" and then he didn't see it.
My head cannon is that this is a collaboration with EmpLemon because of the timing.
That breakin was like climbing an actual mountain.
Im always surprised how easy simon makes sudokus look his iq must be so high id love to see him finish a puzzler magazine from start to finish on a video. Also he is such a softly well spoken man love CTC videos been watching for a few years
23:12 if anyone wants the brian blessed story: ruclips.net/video/jwuw6Z33018/видео.html
Saying “six by force” is probably not the best thing to say for those lip readers out there.
Disgustingly beautiful!