This is one such question where you need to use intuition to find an answer. I tried to explain how you could approach the question. But I find it really difficult to give a simple explanation. To get a large remainder . We need to pick a number in such a way where that number and the reversed number is also large. One such possibility is 94 . Reversed number is 49. Both are large numbers and if you check the remainder , you will get 45 as the remainder (94/49). And from options we can see there is no other bigger remainder and can go with that answer. I was trying to explain how I could arrive at 49 and 94 as a probable case. That's what I tried to explain in the initial part. Sorry if I failed to explain properly 😅
This is one such question where you need to use intuition to find an answer.
I tried to explain how you could approach the question. But I find it really difficult to give a simple explanation.
To get a large remainder . We need to pick a number in such a way where that number and the reversed number is also large. One such possibility is 94 . Reversed number is 49. Both are large numbers and if you check the remainder , you will get 45 as the remainder (94/49).
And from options we can see there is no other bigger remainder and can go with that answer.
I was trying to explain how I could arrive at 49 and 94 as a probable case. That's what I tried to explain in the initial part. Sorry if I failed to explain properly 😅
This is so humble of you to state this. Malayali aanenu manasilayi! 😅. Thanks bro!
Just consider
10x+y-(10y+x)=45
Leads to x--y=5
9-4=5
thank you
Another easy way
For rem yx
How u assume 49? On what basis??
After 49... When all numbes reversed it will be very less numbers....49 is max@@amanpandey8690