I'm confused about the text under this video on your Radiopedia review course. You pasted a section from a radiopedia article titled "Scatter to primary ratio" that lists five measures for decreasing the scatter ratio, two of which are "decreased subject to film distance" and "air gap". That seems contradictory, since an air gap is the distance between the subject and the film (or detector). It's as if it's saying that creating distance between the object and the detector decreases scatter, and closing the distance between the object and the detector decreases scatter. How can two directly opposite techniques both reduce scatter?
Great videos. Thanks. Questions: 1. Do photoelectric effect and Compton scatter consider ionization? 2. What happens to vacant valence electron in Compton scatter?
Great questions. 1. Yes, both are ionising events. 2. The vacancy left after Compton scatter is filled by surrounding ‘free’/valance electrons. The ion is reduced by gaining an electron in the valence shell. No characteristic x-ray is formed because it is not getting the electron from a higher energy shell within the atom 🙂
i read many texts tryna udnerstand difference between compton effect n photoelectric effect...but not one mentioned that photoelectric effect is a FULL ON collision, while compton effect collision isnt...and theres ur rum..thank you sir
Makes such a difference when you realise all of the x-ray energy is absorbed by the electron in photoelectric effect. Was a lightbulb moment for me too!
hi thanks for these lectures.You just said that with photoelectric effect a photoelectron is released and doesnt form an image but confers dose to the patient,How then is an image formed coz you again said that you want photoelectric effect for image formation via different tissue densities?
Technically not. An auger electron is emitted after the vacancy is filled which is a slightly different process than Compton scatter and photoelectric effect. Although the two are often used interchangeably. It’s best to use the term photoelectron when talking about an electron that is released as a direct result of an incident x-ray
Your channel.is really so helpful for us ...from india😊😊
Your tutorials are really helpful.I am a radiography student from Ghana.
Great to hear Godwin. Regards from South Africa 🇿🇦
Sir you are so amazinggggg. Please upload CT physics too❤
Thank you Chaz. CT physics still to come! Trying my best to get these out as quick as possible 🙂
Hi, will the released electron in Compton be called a photoelectron? Or a recoil electron? Thanks in advance.
I'm confused about the text under this video on your Radiopedia review course. You pasted a section from a radiopedia article titled "Scatter to primary ratio" that lists five measures for decreasing the scatter ratio, two of which are "decreased subject to film distance" and "air gap". That seems contradictory, since an air gap is the distance between the subject and the film (or detector). It's as if it's saying that creating distance between the object and the detector decreases scatter, and closing the distance between the object and the detector decreases scatter. How can two directly opposite techniques both reduce scatter?
Thanks for letting me know. It's been updated! Air gap is the correct answer
Great videos. Thanks.
Questions:
1. Do photoelectric effect and Compton scatter consider ionization?
2. What happens to vacant valence electron in Compton scatter?
Great questions. 1. Yes, both are ionising events. 2. The vacancy left after Compton scatter is filled by surrounding ‘free’/valance electrons. The ion is reduced by gaining an electron in the valence shell. No characteristic x-ray is formed because it is not getting the electron from a higher energy shell within the atom 🙂
Thanks for the reply.
i read many texts tryna udnerstand difference between compton effect n photoelectric effect...but not one mentioned that photoelectric effect is a FULL ON collision, while compton effect collision isnt...and theres ur rum..thank you sir
Makes such a difference when you realise all of the x-ray energy is absorbed by the electron in photoelectric effect. Was a lightbulb moment for me too!
hi thanks for these lectures.You just said that with photoelectric effect a photoelectron is released and doesnt form an image but confers dose to the patient,How then is an image formed coz you again said that you want photoelectric effect for image formation via different tissue densities?
Thank you so much Sir
Kindly I'm inquiring about the question bank you talked about in the video
Hi Khamos - there's a link in the first line of the video description if you are keen to check the question bank out 😊
ruclips.net/video/iRH0GBdb1Qo/видео.htmlsi=6Ilc6ZDi0pNujbUv
Who's here is also doing a master in health physics?
Sir thanks for your contributions, I am a radiology student studying in India, can you please drop the link of the question bank.
Absolutely! Love to hear where everyone is from 👍www.radiologytuts.com/bundles/x-ray-ultrasound-and-mri-question-banks
Thank you 🙏
🤗 Thanks for your support!
Great mbro ❤
Keep going 💯
Thanks mate 💯
where’s the link for the saq questions
There should be a link in the description of most videos 🙂
is photo electron and auger electron the same?
Technically not. An auger electron is emitted after the vacancy is filled which is a slightly different process than Compton scatter and photoelectric effect. Although the two are often used interchangeably. It’s best to use the term photoelectron when talking about an electron that is released as a direct result of an incident x-ray