Crystallography, stereographic projections, Lecture 3 of 9

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  • Опубликовано: 25 авг 2024
  • An introduction to stereographic projections and their applications, the Wulff net and methodology.
    Associated teaching materials can be found on:
    www.phase-tran...
    H. K. D. H. Bhadeshia

Комментарии • 31

  • @user-nu7oe6jn1p
    @user-nu7oe6jn1p 2 года назад +1

    A very explicit interpretation of the application of the Wulff net! Thank you so much! 😊

    • @bhadeshia123
      @bhadeshia123  2 года назад +1

      Glad it was helpful! There are free resources available at
      www.phase-trans.msm.cam.ac.uk/teaching.html

  • @schrodinger1988
    @schrodinger1988 10 месяцев назад +2

    Dear Prof. ,
    I think, in the slide at 18:17 , the (110) plane should be parallel to the Z axis, but it's parallel to the x axis, so it is the (011) plane.

    • @bhadeshia123
      @bhadeshia123  10 месяцев назад

      The plane is indeed (011) but there is no mistake. I am using the standard crystallographic notation that [uvw] in square brackets refers to directions, not planes.

  • @MuhammadNadeem-pk7re
    @MuhammadNadeem-pk7re 3 года назад +2

    Dear sir thank you sooooooo very much. Really much informative this lecture was.Thumbs up!

  • @whysoserious0609
    @whysoserious0609 2 года назад +1

    Thanks for your lecture! Helps a lot

    • @bhadeshia123
      @bhadeshia123  2 года назад

      You are welcome. You can freely download my book on the subject from
      www.phase-trans.msm.cam.ac.uk/2020/Crystallography_book.pdf

    • @whysoserious0609
      @whysoserious0609 2 года назад

      @@bhadeshia123 Thanks for the info! I'm still a little confused that when finding poles for {110} plane, it must lies on great circle containing (100) and (001) pole. Is this great circle the trace of 110 plane?

  • @hikguru
    @hikguru 3 месяца назад

    Hello Dr. Bhadeshia. At the 19:29 mark a pole is marked as one, one bar, one bar on the top left quadrant. Should it not be one bar, one bar, one instead? Thx.

    • @bhadeshia123
      @bhadeshia123  3 месяца назад

      Thank you, you are quite right, it should read bar 1, bar 1, 1, as shown on page 40 of this book that you can download free-of-charge. www.phase-trans.msm.cam.ac.uk/2020/Crystallography_book.pdf

  • @diptamahanta
    @diptamahanta Год назад

    Loved the music too

    • @bhadeshia123
      @bhadeshia123  Год назад

      Thank you. You can find more freely available resources on this subject from
      www.phase-trans.msm.cam.ac.uk/teaching.html

  • @franciscocanillas1613
    @franciscocanillas1613 Год назад +1

    you're an angel 🥲 thank you so much

    • @bhadeshia123
      @bhadeshia123  11 месяцев назад

      You are more than welcome. A book on crystallography, and many other resources freely available on my web site,
      www.phase-trans.msm.cam.ac.uk/teaching.html

  • @florianmartini5528
    @florianmartini5528 2 года назад

    Thank you very much for this video.

    • @bhadeshia123
      @bhadeshia123  2 года назад

      You are most welcome. You can freely download a book on the subject from:
      www.phase-trans.msm.cam.ac.uk/2020/Crystallography_book.pdf

  • @brendawilliams8062
    @brendawilliams8062 2 года назад

    Nice presentation. Thx

  • @juheekim3886
    @juheekim3886 10 месяцев назад

    Thank you for your detailed description, sir! I think this video is really helpful to many MSE students.
    However, I didn't understand one thing, so I want to ask a question. At 9:13, you said that the pole (the black dot in fig. (d)) will be at 90 degrees to every point of the trace. I didn't understand why the point is vertical to the trace line.
    I understand that the pole of [011] is perpendicular to the plane (011), but why is it perpendicular to the trace on the equatorial plane?

    • @bhadeshia123
      @bhadeshia123  10 месяцев назад

      If you look at the three-dimensional diagram, bottom right, the pole goes from the centre of the sphere and towards the right (i.e., normal to (011) and therefore is at 90° from all points on the plane. Note that the plane is inclined to the equatorial plane.

    • @juheekim3886
      @juheekim3886 10 месяцев назад

      ​@@bhadeshia123 Ah, you mean the plane (011) has the "real" line, and the trace is just the projection of the "real" line..?
      So, even though the trace is on the equatorial plane, pole of [011] is perpendicular to the line overlapping plane (011) and the Northern Hemisphere.
      I hope I understand your description, sir. Thank you for your quick answer, and I hope you have a great day!

  • @fakhryhatta6711
    @fakhryhatta6711 3 года назад +1

    why do we have (111) trace plane (31:56) different from the (111) trace plane in 19:08
    I still confuse with the meteorite sample actually Prof. Please give me any clue or more explanation. thank you before

    • @bhadeshia123
      @bhadeshia123  3 года назад +1

      The trace at 19.08 is not of (111) but of (0-1 1). You have to be specific about the meteorite question.

  • @joudanon5342
    @joudanon5342 Год назад

    thank you sir

    • @bhadeshia123
      @bhadeshia123  Год назад

      You are very welcome. There are more resources available freely on
      www.phase-trans.msm.cam.ac.uk/teaching.html

  • @sushantsawant6577
    @sushantsawant6577 Год назад

    Which software are you using for such geometry? If it's multiple software can you make video on same?

  • @SohrabF
    @SohrabF 2 года назад

    Sir, first of all, many thanks and appreciation for sharing your beautiful knowledge here. Then, is the indices of the blue pole at 15:33, [111]?