Fluid Mechanics 12.4 - Gravity Driven Liquid Film on an Inclined Surface

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  • Опубликовано: 11 окт 2024
  • In this segment, we apply the conservation of mass and Navier Stokes equations to obtain the velocity distribution in a liquid film sliding down an inclined surface.
    Module 12: Navier Stokes Equations:
    In module 9, we covered the differential form of the conservation of momentum. We also made an assumption that fluid is inviscid and ended up with the Euler's equations. In this module, we relax the inviscid restriction and obtain the Navier Stokes equations, which are a very important equation for establishing the foundation for further studies in fluid dynamics.
    Student Learning Outcomes:
    After completing this module, you should be able to use the Navier Stokes equations to determine viscous flow characteristics between parallel plates and circular tubes. This material is based upon work supported by the National Science Foundation under Grant No. 2019664. Any opinions, findings, and conclusions, or recommendations expressed in this material are those of the author and do not necessarily reflect the views of the National Science Foundation.

Комментарии • 20

  • @Shiptoast0
    @Shiptoast0 2 года назад +1

    clear concise to the point and appeal to simple reason, perfect

  • @kaleishamiller1585
    @kaleishamiller1585 4 года назад +2

    Very clear and helpful video!

  • @chivo2468
    @chivo2468 2 года назад

    Good day and thank you so much for the explaination. You made it extremely clear! Would you be so kind as to point me in the right direction for cases in which the flow is not steady ( ∂u/∂x ≠ 0 ). I mean I think the initial crossing out of the NS-Equation would be easy but what should I do after that? I'm designing an inclined channel to set up a thin film of thickness h. The velocity of the thin film will be measured with a pitot tube that I will somehow install at a selected height y (according to your nomenclature), therefore the value I will be calculating is the thickness h mentioned above, and then I will confirm it with a measurement device. I am a bit confused however since, even though I differentiate now between steady and non-steady (h not constant throughout x) flows, I can't seem to find which one of the two occur naturally when a body of water flows in an inclined surface (and therefore I don't know which initial assumptions I should consider for my set-up. I would be extremely thankful if you could shine some light on my issue! :)

  • @SuhasSathyakiran
    @SuhasSathyakiran 3 года назад +1

    Thank you very much sir😃 Explanation is very clear and Precise.

  • @TianqiZeng
    @TianqiZeng 2 года назад +1

    Thank you sooooo much for the explanation. It helped a lot.

  • @143mathematics
    @143mathematics 3 года назад +2

    very good.

  • @devashishthakkar6723
    @devashishthakkar6723 Год назад +1

    Lovely 😍

  • @carolinagervacio9595
    @carolinagervacio9595 3 года назад

    I love how u explain. Sorry, which Is the app yo use for your keyboard?

  • @moses2061
    @moses2061 2 года назад

    What reference book can you recommend?

  • @fredrickedafe4782
    @fredrickedafe4782 Год назад

    Just want to be much clearer in this, is the pressure P1 same as P2?
    I see there's a difference in height between P1 and P2. Doesn't that make a difference in pressure? I need to be corrected Sir,
    Thanks

  • @abanobjoseph4222
    @abanobjoseph4222 3 года назад

    Excuse me sir, from which text book you got the problem?

    • @CollegeFluidMechanics
      @CollegeFluidMechanics  3 года назад

      Hello Abanob, I am not taking the questions from books. I am preparing them myself.

  • @ElgaymeproTorshock
    @ElgaymeproTorshock 3 года назад +1

    nahhhh

  • @fredrickedafe4782
    @fredrickedafe4782 Год назад

    Just want to be much clearer in this, is the pressure P1 same as P2?
    I see there's a difference in height between P1 and P2. Doesn't that make a difference in pressure? I need to be corrected Sir,
    Thanks

    • @CollegeFluidMechanics
      @CollegeFluidMechanics  Год назад

      That is correct. P1 must be equal to P2. Both points are exposed to the atmosphere which has a constant pressure value at a given elevation.