Roy's Identity

[@varunadharmaratna6074]

Thank you! Extremely useful!!! 🙏

[@rohitmunshi9573]

Great video. If possible please make a video on envelope theorem

[@chhandamachhangte655]

where does the minus sign that cancel -2m comes from

[@legallyleyley]

When you are taking dV/dPx, you get -M^2/(4Px^2Py). I was able to solve to get dV/dPx= (Px*(dM^2/dPx)-M^2)/(4Px^2Py). How do you know that Px*(dM^2/dPx)=0? I would have thought it was equal to Px*(2Px(x^2)+2Py(xy)). Thank you!

[@nicksm7980]

If there's any French speaker here, please, help. Is [roi] pronunciation correct? I've heard that his last name actually pronounced something like [ruwah], but I cannot find the justification for this anywhere.

[@niharikasrivastava2591]

Is the equation for ordinary demand for good Roy's identity?

[@nishathussain99]

What should we do next to derive Roy's identity?

[@arshidahmad7430]

Nothing..Roy's identity simply helps us to find marshallian demand functions in a easy way...otherwise we have to go through the long method what is called lanragian method...

[@tolgahandagasan]

Thank you, it was very helpful.

[@EconomicsinManyLessons]

You are very welcome!

[@brightngwarai1478]

very good but i have a problem with your volume.

[@laibanawaz2959]

How you can take the derivate sir with respect to px

[@niharikasrivastava2591]

Are u asking the step of deriviating V with the respect to Px? Just apply the quotient rule by considering numerator as u and denominator as v

[@saraha.d7186]

Yea why is the px squared?

[@soumya4769]

@@saraha.d7186 the derivative of 1/ Px is -1 / Px²

[@jahidullaskar524]

How this - has come

[@thenewbeginning8346]

Thank you sir. Please derive direct indirect utility function from, alogx1 + x2. How to do this. Please help me.

[@michaelyiadom8874]

please you didnt derive the roys identity

[@sushmitabhattacharjee9560]

Superb explanation!!!

[@EconomicsinManyLessons]

Thank you so much!